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ఇచ్చిన త్రిభుజంలో, O అనేది అంతఃకేంద్రం, AE = 4 సెం.మీ., AC = 9 సెం.మీ మరియు BC = 10 సెం.మీ. AB భుజం పొడవు ఎంత?

19.11.2018.002

  1. 12 సెం.మీ.
  2. 8 సెం.మీ.
  3. 10 సెం.మీ.
  4. 14 సెం.మీ.

Answer (Detailed Solution Below)

Option 2 : 8 సెం.మీ.

Detailed Solution

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∵ AE + EC = AC

⇒ EC = 5 సెం.మీ.

కోణ సమద్విఖండన సిద్ధాంతం ప్రకారం,

కాబట్టి, AE/EC = AB/BC

⇒ 4/5 = AB/10

∴ AB = 8 సెం.మీ.

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