Question
Download Solution PDFThe force requirement in blanking operation of a metal sheet is 10 kN. The thickness of sheet is T and the diameter of blanked part is D. For the same material and same conditions, if the diameter of blanked part is increased to 1.7 D and thickness of the sheet is reduced to 0.5 T, what will be the new blanking force required?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Blanking force is given by:
For a circular blank, perimeter is
Therefore,
Given:
Initial blanking force = 10 kN
Initial diameter =
New diameter =
Calculation:
New force,
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