The heat that must be absorbed by ice of mass 500 g at – 10°C to take it to water at 20°C is (Specific heat of Ice is 2.2 kJ/kg K, Specific heat of water is 4.2 kJ/kg K and Latent heat of fusion of ice is 300 kJ/kg)

Concept:

Heat absorbed = Latent Heat + sensible heat

Latent heat of fusion(LH)  = m × Latent heat of fusion per kg(LH)

Sensible heat(SH) = m × specific heat × ΔT

where m = mass, ΔT = temperature change

Calculation:

Given:

m = 500 gram, Specific heat of Ice = 2.2 kJ/kg K, Specific heat of water = 4.2 kJ/kg K, Latent heat of fusion of ice = 300 kJ/kg)

Total heat absorbed = SH of ice + LH of fusion + SH of water

Total Heat absorbed = (0.5 × 2.2 × 10) + (0.5 × 300) + (0.5 × 4.2 × 20)

Total Heat absorbed = 11 + 150 + 42 = 203 kJ