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The Joint distribution of x and y is as follows

x→ 1 2
y↓    
1 0.4 0.2
2 0.1 0.3

Then E(x|y = 1) is:

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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  1. 2 / 3
  2. 5 / 3
  3. 2
  4. 4 / 3

Answer (Detailed Solution Below)

Option 4 : 4 / 3
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Detailed Solution

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Formula

E(x/y = 1) = ∑xj P(x = xy/y = 1

Calculation

According to the formula

⇒ 1 × (0.4/0.3)

⇒ 4/3

∴ The E(x|y = 1) is: 4/3

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