Question
Download Solution PDFThe kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying breaks, car A stops after 1000 m and car B stops after 1500 m. If Fₐ and Fb are the forces applied by the breaks on cars A and B, respectively, then the ratio Fₐ/Fb is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCorrect option is : (2) 2/3
From work energy theorm
W . D = ΔKE
⇒ F . S = ΔKE
⇒ (ΔKE)A / (ΔKE)B = - FA SA / FB SB
⇒ (-100) / (225) = - FA(1000) / FB(1500)
FA / FB = 2 / 3
Last updated on Jun 16, 2025
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