The number of instantaneous centers for 8-link kinematic chain is

Concept:

The instantaneous centre method of analysing the motion in a mechanism is based upon the concept that any displacement of a body having motion in one plane, can be considered as a pure rotational motion of a rigid link as a whole about some centre, known as an instantaneous centre.

The number of instantaneous centres in a considered kinematic chain is equal to the number of combinations of two links:

If N is the number of instantaneous centres and n is the number of links then:

\(N = \frac{{n\left( {n - 1} \right)}}{2}\)

Calculation:

Given:

n = 8

\(N = \frac{{n\left( {n - 1} \right)}}{2} = \frac{{8\left( {8 - 1} \right)}}{2} = 28\)

Hence, the answer is None of the above.