The price of an article was increased by x%. Later the new price was decreased by x%. If the latest price was ₹1, then what was the original price of the article?

This question was previously asked in
RPF Constable 2024 Official Paper (Held On: 09 Mar, 2025 Shift 3)
View all RPF Constable Papers >
  1. \(\frac{10000}{(100 - x)(100 + x)}\)
  2. \(\sqrt{\frac{(1-x)}{10}}\)
  3. ₹100
  4. \(\frac{(1-x)}{100}\)

Answer (Detailed Solution Below)

Option 1 : ₹\(\frac{10000}{(100 - x)(100 + x)}\)
Free
RPF Constable Full Test 1
3.9 Lakh Users
120 Questions 120 Marks 90 Mins

Detailed Solution

Download Solution PDF

Given:

The price of an article was increased by x%. Later the new price was decreased by x%.

Latest price = ₹1

Calculation:

Let the original price be P. After increasing by x%, the price becomes:

P × (1 + x/100)

After decreasing by x%, the new price becomes:

P × (1 + x/100) × (1 - x/100)

We are given that the latest price = ₹1, so:

P × (1 + x/100) × (1 - x/100) = 1

⇒ P × (1 - x2/1002) = 1

⇒ P = 1 / (1 - x2/1002)

⇒ P = 1002 / (1002 - x2)

⇒ P = ₹(10000) / ((100 + x)(100 - x))

∴ The correct answer is option (1).

Latest RPF Constable Updates

Last updated on Jul 16, 2025

-> More than 60.65 lakh valid applications have been received for RPF Recruitment 2024 across both Sub-Inspector and Constable posts.

-> Out of these, around 15.35 lakh applications are for CEN RPF 01/2024 (SI) and nearly 45.30 lakh for CEN RPF 02/2024 (Constable).

 

-> The Examination was held from 2nd March to 18th March 2025. Check the RPF Exam Analysis Live Updates Here.

Get Free Access Now
Hot Links: teen patti master gold download teen patti jodi teen patti apk download