The value of 52 × 3 ÷ 4 + \(\sqrt{441}\) ÷ 7 ×  3 + 5 - 32 ÷ 8 × 12 is

This question was previously asked in
CTET (Mathematics & Science) Official Paper-II (Held On: 07 Jul, 2024)
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  1. 15
  2. 21
  3. 0
  4. 5

Answer (Detailed Solution Below)

Option 4 : 5
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3Concept used: 

BODMAS

Step 1 : Bracket 

Step 2 : OF

Step 3 : Divide

Step 4 : Multiplication

Step 5 : Addition

Step 6 : Substraction

Calculation: 

Evaluate the square root: √(441) = 21.

Substitute the value back into the expression: 52 × 3 ÷ 4 + 21 ÷ 7 × 3 + 5 - 32 ÷ 8 × 12.

Perform the multiplication and division from left to right:

52 × 3 ÷ 4 + 21 ÷ 7 × 3 + 5 - 32 ÷ 8 × 12.

52 × 3 ÷ 4 + 3 × 3 + 5 - 4 × 12.

52 × 3/4 3 × 3 + 5 - 4 × 12.

 52 × 3/4 + 9 + 5 - 48 

13 × 3 + 9 + 5 - 48

39 + 14 - 48

53 - 48 = 5

 

∴ The Correct answer is Option (4): 5

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