The whole circle bearing of a traverse are recorded as given below. Convert these to reduced bearings for BC & CD.

Line AB BC CD DA
bearing 70°30' 120°45' 223°30' 320°47'

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JKSSB JE Civil Jal Shakti 6 Dec 2022 Official Paper (Shift 2)
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  1. S59° 15' E & N53° 30' W
  2. S59° 15' E & S43° 30' W
  3. S59° 15' W & S53° 30' E
  4. N120° 45' E & S53° 30' E

Answer (Detailed Solution Below)

Option 2 : S59° 15' E & S43° 30' W
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ST 1: JKSSB JE - Surveying
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20 Questions 20 Marks 20 Mins

Detailed Solution

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Concept:

Whole circle bearing (WCB) system:

  • All bearings are taken in a clockwise direction with respect to the North Pole.
  • These bearings are observed by the prismatic compass.
  • The whole circle bearing of any line varies from 0∘ to 360.
  • The whole circle bearing is also called the azimuth.

Quadrantal bearing (QB) system:

  • In this system, the bearing of the line is measured eastward or westward from the north or south pole whichever is near.
  • These bearings are observed by the surveyor compass.
  • It is also called reduced bearing system
  • The quadrant bearing of a line cannot be greater than 90.

RB of a line = WCB of a line (if 0∘ < WCB < 90)

RB of a line = 180 - WCB of a line (if 90∘ < WCB < 180)

RB of a line = WCB of a line - 180 (if 180∘ < WCB < 270)

RB of a line = 360 - WCB of a line (if 270∘ < WCB < 360)

RB = Reduced bearing, WCB = Whole circle bearing

Calculation:

Given

Line AB BC CD DA
bearing 70°30' 120°45' 223°30' 320°47'

 

Calculating reduced bearing for BC:

F1 Vilas Engineering  28.12.2022 D13

Reduced bearing of line BC = 180∘ - 120∘ 45' = 59∘ 15∘ 

Reduced bearing of line BC = S 59∘ 15 E

Similarly calculating reduced bearing for CD:

Reduced bearing of line CD = 223∘ 30' - 180∘ 0' = 43∘ 30∘ 

Reduced bearing of line CD = S 43∘ 30 W

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