Time period of a simple pendulum in a stationary lift is ‘T'. If the lift accelerates with g/6 vertically upwards then the time period will be :

(Where g = acceleration due to gravity)

Answer (Detailed Solution Below)

Option 3 :
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JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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CONCEPT:

The time period is defined as the time required for the simple pendulum to do one oscillation and it is written as;

T = 2 

Here we have T as the time period, L is the length of the pendulum and g is the acceleration due to gravity.

CALCULATION:

Given:

The time period of a simple pendulum T and it is written as;

T = 2 -----(1)

At the stationary lift, acceleration is equal to the acceleration due to gravity and it is written as;

a = g

Now, equation (1) becomes,

T = 2  ------(2)

The lift is accelerated, a = g + g/6

⇒ a = 7g/6

The time period is written as;

T' =  

⇒ T' =  

⇒ T' =  T

Hence, option 3) is the correct answer.

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