Question
Download Solution PDFWhat is the bandwidth of main lobe in the spectrum of BPSK signal with carrier frequency = 1 MHz and bit rate = 1 kbps ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFBandwidth of the Main Lobe in BPSK Signal Spectrum:
Definition: In Binary Phase Shift Keying (BPSK), the spectrum of the modulated signal consists of a main lobe and side lobes. The bandwidth of the main lobe is a critical parameter that determines the frequency range over which most of the signal's power is concentrated. This bandwidth is influenced by the bit rate of the signal.
Formula for Bandwidth: The bandwidth of the main lobe for the spectrum of a BPSK signal can be approximated using the following relation:
Bandwidth of the main lobe = 2 × Bit Rate
Here:
- Bit Rate: The rate at which bits are transmitted, typically measured in bits per second (bps).
- 2: A factor that accounts for the symmetric nature of the main lobe around the carrier frequency.
Given Data:
- Carrier Frequency = 1 MHz (This value does not affect the bandwidth of the main lobe.)
- Bit Rate = 1 kbps = 1000 bps
Calculation:
The bandwidth of the main lobe is calculated as:
Bandwidth of the main lobe = 2 × Bit Rate
Bandwidth of the main lobe = 2 × 1000 bps
Bandwidth of the main lobe = 2000 Hz = 2 kHz
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