Question
Download Solution PDFWhat is the maximum area of the rectangle with perimeter 620 mm?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Perimeter of rectangle = 620 mm
Formula Used:
Perimeter of rectangle, P = 2(l + w)
Area of rectangle, A = l × w
For a given perimeter, the maximum area of a rectangle is achieved when it is a square (i.e., length = width).
Calculation:
⇒ 620 = 2(l + w)
⇒ l + w = 620 / 2
⇒ l + w = 310
For maximum area, l = w
⇒ l = 310 / 2
⇒ l = 155 mm
⇒ w = 155 mm
Maximum Area = l × w
⇒ Maximum Area = 155 × 155
⇒ Maximum Area = 24025 mm2
The maximum area of the rectangle with perimeter 620 mm is 24025 mm2.
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