What will the total number of matches, if in a league cum knockout tournament of 16 teams which initially played in 4 groups of four, where all teams in a given group play league matches? Top two teams from each group qualify for knockout stage and losing semi‐finalist also play to decide for 3rd and 4th place

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UGC NET Paper 2: Physcial Education 21 Nov 2021 Shift 2
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  1. 32
  2. 31
  3. 30
  4. 33

Answer (Detailed Solution Below)

Option 1 : 32
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
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Detailed Solution

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Concept:

Tournament types:

  • Knockout (single, consolation, and double elimination.)
  • League or Round robin (single or double).
  • Combination 
  1. knock-out cum knock-out.
  2. knock-out cum league.
  3. league cum knock-out.
  4. league cum league.
  • Challenge (ladder and pyramid)

Explanation:

  • In the given question:
    • Total number of teams= 16
    • And 4 teams in each group
  • Therefore total match in the league system for one group:

=n(n-1)/2

=4(4-1)/2=12/2=6

  • Thus for 4 groups total matches will be 4 X 6 =24
  • Now, from each group, 2 teams reach the knockout rounds
  • Thus 8 teams in the knockout.
  • Therefore total matches for 8 teams will be, 8-1=7
  • And one match will be played for the losing team in the semifinals.
  • Thus total matches will be 

                                         =24+7+1

                                         =32

Thus, the total number of matches will be 32.

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