PERT MCQ Quiz in বাংলা - Objective Question with Answer for PERT - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Mar 17, 2025

পাওয়া PERT उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন PERT MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest PERT MCQ Objective Questions

Top PERT MCQ Objective Questions

PERT Question 1:

 If an activity has its optimistic, most likely and pessimistic times as 2, 4 and 9 respectively, then its expected time and variance are ____ and ______ respectively?

  1. 4.5 and 7/6
  2. 7 and 49/36
  3. 4.5 and 49/36
  4. 7 and 7/6

Answer (Detailed Solution Below)

Option 3 : 4.5 and 49/36

PERT Question 1 Detailed Solution

Concept:

Expected time: It represents a particular time of an activity that has 50% chances of being met and 50% chances of being exceeded.

The expected time (te) is given as:

F1 Neel Madhu 03.04.20 D1

\({{\rm{t}}_{\rm{e}}} = \frac{{{{\rm{t}}_0} + 4{{\rm{t}}_{\rm{m}}} + {{\rm{t}}_{\rm{p}}}}}{6}\)

Also, Standard deviation (σ) is given by \(\frac{{{{\rm{t}}_{\rm{p}}} - {{\rm{t}}_0}}}{6}\)

 Variance (σ 2) is given by \(σ^2 = {\left( {\frac{{{t_p} - {t_o}}}{6}} \right)^2}\)

Where, tp = Pessimistic time, t0 = Optimistic time, tm = Most likely time

Calculation

Given:

 t0 = 2 weeks, tm = 4 weeks, tp = 9 weeks

\(∴ {{\rm{t}}_{\rm{e}}} = \frac{{2\ + \ 4 \times 4 \ + \ 9}}{6}\)

 t e = 27/6 = 4.5 weeks

Standard deviation is given by

 \({\rm{σ }} = \frac{{\left( {9 - 2} \right)}}{6} = 7/6\)

 ∴ Variance = σ 2 = (7/6)2 = 49/36

 

PERT Question 2:

Consider the following AON Diagram, consisting of 7 activities of a given project, with the time of completion of each activity and its name written on the node. Find the total project duration in days.

F2 Akhil Madhuri 08.09.2021 D1

  1. 39 
  2. 40
  3. 42
  4. 36

Answer (Detailed Solution Below)

Option 2 : 40

PERT Question 2 Detailed Solution

Concept:

Critical time:

  • In project management, the critical path is the longest sequence of tasks/activities, that must be completed to successfully conclude the project, from start to finish.
  • So, it is also the minimum possible time, in which the project is said to be completed and hence also called project completion time.

Calculation:

Given:

F2 Akhil Madhuri 08.09.2021 D1

TA = 8 Days, TB = 11 Days, TC = 6 Days, TD = 12 Days, TE = 7 Days, TF = 16 Days, TG = 9 Days

Path Duration (Days)
 A - B -E - G  8 + 11 + 7 + 9 = 35 
A - B - D - G 8 + 11 + 12 + 9 = 40
A - C - F - G 8 + 6 + 16 + 9 = 39
A - C - D - G 8 + 6 + 12 + 8 = 34


∴ The duration of project completion is 40 days ie along the critical path A - B - D - G

Activity on Arrow (AOA) Diagram Activity on Node (AON) Diagram
Arrow represents activity and each node represent start/end of an activity Node represents activity and the arrow shows the direction of project
Uses concept of dummy activity No need to use dummy activity.
Used in PERT and CPM Used in Precedence diagram method (PDM)

PERT Question 3:

Various activities of a project, are shown on bar charts by:

  1. Vertical lines
  2. Horizontal lines
  3. Dots
  4. Crosses

Answer (Detailed Solution Below)

Option 2 : Horizontal lines

PERT Question 3 Detailed Solution

Explanation:

Bar chart (Gantt chart):

(i) It is a pictorial chart.

(ii) It has two coordinate axes, the horizontal axis (coordinate) represents the elapsed time and the vertical axis represents the job or activity to be performed.

Screenshot 2022-04-04 164332

From the above Gantt chart, it is clear that horizontal lines, which are blue in color show the activity of the project

(iii) The beginning and end of each bar represent starting and finishing times of a particular activity respectively.

(iv) The length of the bar shows the time required for completion.

Limitation of a bar chart:

(i) Lack of degree of detail.

(ii) A bar chart does not show the progress of work and hence it can not be used as a control device.

(iii) A bar chart is unable to depict the interdependencies of various activities clearly.

(iv) No provision to account for time uncertainties.

(v) Bar chart can not distinguish between critical and non-critical activities and hence resource smoothening and resource-leveling can not be done.

PERT Question 4:

PERT stands for

  1. Perfect Evaluation and Review Technique
  2. Programme Elongation and Review Technique
  3. Programme Evaluation and Review Technique
  4. None of the above

Answer (Detailed Solution Below)

Option 3 : Programme Evaluation and Review Technique

PERT Question 4 Detailed Solution

Concept:

PERT stands for "Programme Evaluation and Review Technique​". This network model is used for project scheduling.

Difference between PERT and CPM (Critical Path Method)

PERT

CPM

1. Probabilistic approach

1. Deterministic approach

2. Three-time estimate

2. One - time estimate

3. Event oriented network model

3. Activity-oriented network model

4. The slack concept is used

4. Float concept is used

5. Project crashing is not possible

5. Project crashing is possible

6. Deals with probabilistic time estimates

6. Deals with deterministic time estimates

PERT Question 5:

In a ‘PERT’ analysis, if the probability factor is negative, the chances of completing the project in time is

  1. Less than 50%
  2. Fifty-fifty %
  3. More than 50%
  4. Zero

Answer (Detailed Solution Below)

Option 1 : Less than 50%

PERT Question 5 Detailed Solution

Concept-

F1 Shraddha Chandramouli 13.04.2021 D 1

Probability factor \(z = \frac{{x - \overline x }}{\sigma }\)

Where x̅ = mean, σ = std. deviation.

For z = 0, P(z) = 50%

For z < 0, P(z) < 50%

For z > 0, P(z) > 50%

In this probability distribution, the curve is symmetric about mean that is

F1 Shraddha Chandramouli 13.04.2021 D 2

The area covered under the entire curve is 1 unit. So area covered upto a point which is less than mean will be less than 50%.

PERT Question 6:

Mile stone chart is an improvement over

  1. Bar chart
  2. CPM Scheduling
  3. PERT scheduling
  4. OPST scheduling

Answer (Detailed Solution Below)

Option 1 : Bar chart

PERT Question 6 Detailed Solution

Explanation:

Mile Stone chart:

  • It is a modification over the original Gantt chart (Bar Chart). MIlestone is key events of main activities represented by the bar. Therefore they give an idea about the completion of sub-activities.
  • Controlling can be better achieved with the help of milestone charts. But still, activity interrelationship and accountability of time uncertainty can not be depicted which can be overcome in-network technique. 

Important Points

Work break down structure:

  • These are incremental and hierarchical the composition of the project phases. It is a tree-like structure and it shows the description of the job for completion of the project from top to bottom.
  • The main jobs are broken down into the number of small manageable units depending upon the size, time or efforts require for completion.

Bar chart (Gantt chart):

  • It is a pictorial chart.
  • It has two coordinate axes, the horizontal coordinate represents the elapsed time and the vertical coordinate represents the job or activity to be performed.
  • The beginning and end of each bar represent starting and finishing time of a particular activity respectively.
  • The length of bar shows the time required for completion.

Limitation of bar chart:

  • Lack of degree of detail.
  • A bar chart does not show the progress of work and hence it can not be used as a control device.
  • A bar chart is unable to depict the interdependencies of various activities clearly.
  • No provision to account for time uncertainties.
  • A bar chart can not distinguish between critical and non-critical activities and hence resource smoothening and resource levelling can not be done.

PERT Question 7:

In an activity, if the latest start time is 28 days & the earliest start time is 18 days then the total float shall be

  1. 46 days
  2. 10 days
  3. 14 days
  4. 9 days

Answer (Detailed Solution Below)

Option 2 : 10 days

PERT Question 7 Detailed Solution

Concept:

Total float: 

(i) The time span by which starting or finishing of an activity can be delayed without delaying the completion of the project.

(ii) It is the maximum available time in excess of the activity completion time.

F1 Ram Shraddha 02.02.2021 D6

Total float is given by,

\({F_T} = \;\left( {T_L^j - T_E^i} \right) - \;{t_{ij}}\)

\({F_T} = \;\left( {T_L^j} \right) - \;\left( {T_E^i + {t_{ij}}} \right)\)

FT = LFT – EFT

Or, \({F_T} = \;\left( {T_L^j - \;{t_{ij}}\;} \right) - \;T_E^i\)

FT = LST – EST

Where,

LST = Latest start time = \(\left( {T_L^j - {t_{ij}}} \right)\)

EST = Earliest start time = \(T_E^i\)

EFT = Earliest finish time = \(\left( {T_E^i + {t_{ij}}} \right)\)

LFT = Latest finish time = \(T_L^i\)

Calculation:

Given,

LST = 28 days, EST = 18 days

Total float (TF) = LST – EST = 28 – 18

TF = 10 days

PERT Question 8:

The float that can be used by an activity without affecting successor activities is 

  1. Total Float
  2. Free Float
  3. Independent Float
  4. Interfering Float

Answer (Detailed Solution Below)

Option 2 : Free Float

PERT Question 8 Detailed Solution

Explanation:

Free float: It is the portion of total float by which an activity can be delayed without affecting succeeding activity i.e. the successor activity can start at its Earliest Start Time (EST).  But the preceding activities are affected by the free float. 

3

Free Float = Total Float - Head event Slack

\({F_F} = \left( {T_E^j - T_E^i} \right) - tij\)

Free float is also equal to total float minus head event slack.

\({F_F} = {F_T} - S_j\)

which implies that free float does not affect succeeding activity but affects preceding activities.

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  • Total Float: It is the maximum delay possible for an activity without considering any delay in its precedence or succeeding activity.
  • Interfering Float: Maximum amount by which an activity can be delayed without delaying the project but will cause delay to the Early Start of some following activity. It is given by Total float - Free float.
  • Independent float is the maximum delay possible for an activity that used floats of the preceding activity, but we will not affect the float of the succeeding activity.

PERT Question 9:

For a project activity, the optimistic, the pessimistic and the most likely times are 4, 14 and 6 days respectively. Its average time is ________

  1. 10 days
  2. 7 days
  3. 12 days
  4. 9 days

Answer (Detailed Solution Below)

Option 2 : 7 days

PERT Question 9 Detailed Solution

The correct answer is 7 days.

Key Points To calculate the average time for a project activity using the three-point estimation method, you can use the following formula:

Average Time = (Optimistic Time + 4 * Most Likely Time + Pessimistic Time) / 6

In this case, the optimistic time is 4 days, the pessimistic time is 14 days, and the most likely time is 6 days. Plugging these values into the formula, we get:

Average Time = (4 + 4 * 6 + 14) / 6
Average Time = (4 + 24 + 14) / 6
Average Time = 42 / 6
Average Time = 7

Therefore, the average time for the project activity is 7 days.

PERT Question 10:

Select the correct AON network diagram for the following project activities:

Activity Immediate Successor
1 2
2 3, 4
3 5
4 5

 

  1. F2 Madhuri Engineering 24.05.2022 D2
  2. F2 Madhuri Engineering 24.05.2022 D3
  3. F2 Madhuri Engineering 24.05.2022 D4
  4. F2 Madhuri Engineering 24.05.2022 D5

Answer (Detailed Solution Below)

Option 2 : F2 Madhuri Engineering 24.05.2022 D3

PERT Question 10 Detailed Solution

Explanation:

Procedure to draw any network diagram:

  1. Begin the project with any single milestone and label it start.
  2. Find all the activities that have no immediate predecessor ie they start as soon as the project starts. In this case activity, 1 will be our starting activity.
  3. Then, find the activities that have a successor of the first activity as their predecessor. In this case, the 2nd activity is the successor of the 1st activity and the predecessor of the 3rd and 4th activity.
  4. Repeat the above steps, and by satisfying all the given relationships between various activities, draw the required diagram.
  5. Use dummy activity, where ever the above relationship cannot be fulfilled without any error in the network

Errors in networking:

1) Cyclic/ looping error:

2) Dangling error

3) Wagon wheel error

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