Torque on a Current Loop MCQ Quiz in বাংলা - Objective Question with Answer for Torque on a Current Loop - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Mar 10, 2025

পাওয়া Torque on a Current Loop उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Torque on a Current Loop MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Torque on a Current Loop MCQ Objective Questions

Top Torque on a Current Loop MCQ Objective Questions

Torque on a Current Loop Question 1:

A current of 10 A is flowing through a circular coil of radius 7 cm and 10 turns. It is placed in the magnetic field such that it makes an angle of 30° with the magnetic field of 5 T. Calculate the magnitude of the torque acting on the circular coil.

  1. 77 × 10-2 Nm
  2. 385 × 10-2 Nm
  3. 770 × 10-2 Nm
  4. 850 × 10-2 Nm

Answer (Detailed Solution Below)

Option 2 : 385 × 10-2 Nm

Torque on a Current Loop Question 1 Detailed Solution

CONCEPT:

  • When a magnetic dipole of moment \(\vec M\) is held at an angle θ with the direction of a uniform magnetic field \(\vec B\), then it experiences a torque.

The magnitude of the torque acting on the dipole is

τ = M B sin θ

Where M is magnetic moment and B is magnetic field

CALCULATION:

Given – Number of turns (N) = 10, I = 10 A, B = 5 T and radius (r) = 7 cm = 7 × 10-2 m

θ = 30°

The magnitude of the torque acting on the circular coil is:

τ = M B sin θ

Here, M = INA

\(\Rightarrow M = 10 \times 10 \times \frac{{22}}{7} \times {\left( {7 \times {{10}^{ - 2}}} \right)^2}\)

⇒ M = 154 × 10-2 Am2

⇒ τ = 154 × 10-2 × 5 × sin 30°

τ = 385 × 10-2 Nm

So option 2 is correct.

Torque on a Current Loop Question 2:

The torque acting on a current carrying loop placed in magnetic field does not depend upon:

  1. shape of loop
  2. area of loop
  3. value of current
  4. magnetic field
  5. None of the above/More than one of the above.

Answer (Detailed Solution Below)

Option 1 : shape of loop

Torque on a Current Loop Question 2 Detailed Solution

CONCEPT:

  • As the current-carrying conductor experiences a force when placed in a magnetic fieldeach side of a current-carrying circular coil experiences a force in a magnetic field.
  •  In the present section, we shall see in what way the circular loop carrying current is influenced by a magnetic field.

 

F1 J.K Madhu 19.05.20 D15

  • Consider a circular coil of length l and breadth b carrying a current I placed in a uniform magnetic field B.
  • θ, be the angle between the plane of the circular coil and the magnetic field.

 Force acting on the circular loop:

F = I L B sinθ, where F is force, I = current, L = distance from the axis, B = strength of the magnetic field, θ = angle between the plane of the circular coil and the magnetic field.

  • Acting on the upper and lower sides are equal and opposite along the same line of action, they cancel each other.
  • As the force acting on the sides QR and SP are equal and opposite along different lines of action they constitute a couple.

So, the torque acting on the loop is,

T = force × arm of the couple

T = B I L × b Sinθ = B I A Sinθ

T = B I A Sinθ

EXPLANATION:

  • The torque acting on a circular current-carrying loop placed in a uniform magnetic field depends upon
    • area of the loop
    • value of current
    • magnetic field
  • The torque acting on the circular loop is

T = B I A Sinθ.

  • Therefore option 1 is incorrect.

Torque on a Current Loop Question 3:

A rectangular current carrying loop is placed in a uniform magnetic field of magnitude B. The angle between the plane perpendicular to the coil and the magnetic field is θ. The current in the loop is I. Then the torque on the rectangular loop will be-

  1. B I A cosθ
  2. B I A sinθ
  3. B I A cosθ/2
  4. B I A sinθ/2

Answer (Detailed Solution Below)

Option 2 : B I A sinθ

Torque on a Current Loop Question 3 Detailed Solution

CONCEPT:

  • As the current-carrying conductor experiences a force when placed in a magnetic field, each side of a current-carrying rectangular coil experiences a force in a magnetic field.
  •  In the present section, we shall see in what way the rectangular loop carrying current is influenced by a magnetic field.

F1 J.K Madhu 13.05.20 D12

  • Consider a rectangular coil of length l and breadth b carrying a current I placed in a uniform magnetic field B.
  • θ, be the angle between the plane of the rectangular coil and the magnetic field.


Force acting on the rectangular loop:

F = I L B sinθ, where F is force, I = current, L = distance from the axis, B = strength of the magnetic field, θ = angle between the plane of the rectangular coil and the magnetic field.

  • Acting on the upper and lower sides are equal and opposite along the same line of action, they cancel each other.
  • As the force acting on the sides QR and SP are equal and opposite along different lines of action they constitute a couple.


So, the torque acting on the loop is,

T = force × arm of the couple

T = B I L × b Sinθ = B I A Sinθ

T = B I A Sinθ

EXPLANATION:

  • The torque acting on the rectangular loop is


T = B I A sin θ.

So option 2 is correct.

Torque on a Current Loop Question 4:

What is the region around a magnet where the magnetic force is experienced known as?

  1. Magnetic field
  2. Magnetic flux
  3. Magnetic domain
  4. Magnetic pole

Answer (Detailed Solution Below)

Option 1 : Magnetic field

Torque on a Current Loop Question 4 Detailed Solution

The correct answer is: 1) Magnetic field

Explanation:

The magnetic field is the region around a magnet (or current-carrying conductor) where its magnetic force influences other magnets, magnetic materials, or moving charges. It is represented by field lines that show the direction and strength of the force.

Option Analysis

  1. Magnetic flux → Refers to the total number of magnetic field lines passing through a surface (measured in Weber).

  2. Magnetic domain → Microscopic regions within a material where atomic magnetic moments are aligned.

  3. Magnetic pole → The points (north/south) on a magnet where the magnetic field is strongest, not the surrounding region.

Additional Information

  • Magnetic fields are vector fields (have direction and magnitude).

  • They extend infinitely but weaken with distance.

  • Field lines never cross and always form closed loops.

Torque on a Current Loop Question 5:

A rectangular coil of length 40 cm and width 10 cm consists of 10 turns and carries a current of 16 A. The coil is suspended such that the normal to the plane of the coil makes an angle of 60º with the direction of a uniform magnetic field of magnitude 0.60 T. Find the magnitude of the torque experienced by the coil.

  1. 1.92 N-m
  2. \(1.92\sqrt3\, N-m\)
  3. \(1.62\sqrt3\, N-m\)
  4. \(0.64\sqrt3\, N-m\)

Answer (Detailed Solution Below)

Option 2 : \(1.92\sqrt3\, N-m\)

Torque on a Current Loop Question 5 Detailed Solution

CONCEPT:

Torque on a rectangular current loop in a uniform magnetic field:

  • If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.
    • The net force on the loop will be zero.
  • The torque on the current-carrying rectangular loop is given as,

⇒ τ = NIAB.sinθ

Where N = number of turns in the coil, I = current in the loop, A = area enclosed by the loop, B = magnetic field intensity, and θ = angle between the normal to the plane of the coil and the direction of a uniform magnetic field

  • The magnetic moment m for the loop is given as,

⇒ m = NIA

So,

\(⇒ τ = mBsinθ = \vec{m}×\vec{B}\)

mgtc

trer

CALCULATION:

Given L = 40 cm = 0.4 m, W = 10 cm = 0.1 m, N = 10 turns, I = 16 A, θ = 60°, and B = 0.60 T

Where N = number of turns in the coil, I = current in the loop, A = area enclosed by the loop, L = length of the loop, W = width of the loop, B = magnetic field intensity, and θ = angle between the normal to the plane of the coil and the direction of a uniform magnetic field

  • The area enclosed by the loop is given as,

⇒ A = L × W

⇒ A = 0.4 × 0.1

⇒ A = 0.04 m2

  • So the torque on the current-carrying rectangular loop is given as,

⇒ τ = IAB sinθ

⇒ τ = 16 × 0.04 × 0.6 × sin60

\(\Rightarrow τ=\frac{16\times4\times6\times\sqrt3}{10\times10\times2}\)

\(⇒ τ = 1.92\sqrt3\, N-m\)

  • Hence, option 2 is correct.

Torque on a Current Loop Question 6:

A rectangular loop of N number of turns encloses an area A. If the current I flows in the loop, then the magnetic moment of the loop will be:

  1. NIA
  2. IA
  3. \(\frac{IA}{N}\)
  4. None of these

Answer (Detailed Solution Below)

Option 1 : NIA

Torque on a Current Loop Question 6 Detailed Solution

CONCEPT:

Torque on a rectangular current loop in a uniform magnetic field:

  • If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.
    • The net force on the loop will be zero.
  • The torque on the current-carrying rectangular loop is given as,

⇒ τ = NIAB.sinθ

Where N = number of turns in the coil, I = current in the loop, A = area enclosed by the loop, B = magnetic field intensity, and θ = angle between the normal to the plane of the coil and the direction of a uniform magnetic field

  • The magnetic moment m for the loop is given as,

⇒ m = NIA

So,

\(⇒ τ = mB\,sinθ = \vec{m}\times\vec{B}\)

mgtc

trer

EXPLANATION:

  • We know that the magnetic moment 'm' of the current-carrying loop is given as,

⇒ m = NIA

  • Hence, option 1 is correct.

Torque on a Current Loop Question 7:

The magnetic field due to a current carrying coil increases when:  

  1. One moves way from the coil 
  2. current through the coil is increased  
  3. current through the coil is decreased 
  4. number of turns of the coil is decreased 

Answer (Detailed Solution Below)

Option 2 : current through the coil is increased  

Torque on a Current Loop Question 7 Detailed Solution

The correct answer is current through the coil is increased.

Key Points

  • The magnetic field around a current-carrying coil is directly proportional to the current passing through the coil.
  • Increasing the current results in a stronger magnetic field as per Ampere's Law, which states that the magnetic field is proportional to the current.
  • The strength of the magnetic field can be calculated using the formula B = μ₀ * (n * I), where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns, and I is the current.
  • This relationship is fundamental in electromagnetism and is utilized in various applications such as electromagnets, transformers, and inductors.

Additional Information

  • Ampere's Law:
    • Ampere's Law relates the circulating magnetic field in a closed loop to the electric current passing through the loop.
    • The mathematical expression of Ampere's Law is ∮B·dl = μ₀ * I, where B is the magnetic field, dl is an infinitesimal element of the path, and I is the current enclosed by the path.
  • Electromagnetism:
    • Electromagnetism is the branch of physics involving the study of the electromagnetic force, a type of physical interaction that occurs between electrically charged particles.
    • It is the fundamental principle behind electric motors, transformers, and many other modern devices.
  • Magnetic Field Strength:
    • Magnetic field strength, often denoted as H, is a measure of the magnetizing force and is directly proportional to the current and inversely proportional to the distance from the current-carrying conductor.
  • Permeability of Free Space (μ₀):
    • Permeability of free space, also known as the magnetic constant, is a physical constant that describes the magnetic permeability in a classical vacuum.
    • Its value is approximately 4π × 10⁻⁷ H/m (henries per meter).

Torque on a Current Loop Question 8:

A rectangular current carrying loop is placed in a uniform magnetic field at an angle, then it will experience:

  1. Force
  2. Torque
  3. Both force and torque
  4. Neither force nor torque
  5. Not Attempted

Answer (Detailed Solution Below)

Option 2 : Torque

Torque on a Current Loop Question 8 Detailed Solution

CONCEPT:

Torque on a rectangular current loop in a uniform magnetic field:

  • If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.
    • The net force on the loop will be zero.
  • The torque on the current-carrying rectangular loop is given as,

⇒ τ = NIAB.sinθ

Where N = number of turns in the coil, I = current in the loop, A = area enclosed by the loop, B = magnetic field intensity, and θ = angle between the normal to the plane of the coil and the direction of a uniform magnetic field

  • The magnetic moment m for the loop is given as,

⇒ m = NIA

So,

\(⇒ τ = mB.sinθ = \vec{m}\times\vec{B}\)

mgtc

trer

EXPLANATION:

  • If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.
  • The net force on the loop will be zero. Hence, option 2 is correct.

Torque on a Current Loop Question 9:

The current in the rectangular loop of area A is I. If this loop is placed in the uniform magnetic field of intensity B and the angle between the magnetic field and the area is θ, then the torque on the loop will be:

  1. IABsinθ
  2. \(\frac{IBsin\theta}{A}\)
  3. \(\frac{I}{BAsin\theta}\)
  4. \(\frac{IABsin\theta}{2}\)

Answer (Detailed Solution Below)

Option 1 : IABsinθ

Torque on a Current Loop Question 9 Detailed Solution

CONCEPT:

Torque on a rectangular current loop in a uniform magnetic field:

  • If a rectangular loop carrying a steady current is placed in a uniform magnetic field then it will experience a torque.
    • The net force on the loop will be zero.
  • The torque on the current-carrying rectangular loop is given as,

⇒ τ = NIAB.sinθ

Where N = number of turns in the coil, I = current in the loop, A = area enclosed by the loop, B = magnetic field intensity, and θ = angle between the normal to the plane of the coil and the direction of a uniform magnetic field

  • The magnetic moment m for the loop is given as,

⇒ m = NIA

So,

\(⇒ τ = mB.sinθ = \vec{m}\times\vec{B}\)

mgtc

trer

EXPLANATION:

Given I = current in the loop, A = area enclosed by the loop, B = magnetic field intensity, and θ = angle between the magnetic field and the area

  • So the torque on the current-carrying rectangular loop is given as,

⇒ τ = IAB.sinθ

  • Hence, option 1 is correct.

Torque on a Current Loop Question 10:

The instrument used to detect presence of current is :

  1. Ohmmeter
  2. Voltmeter
  3. Galvanometer
  4. Voltameter

Answer (Detailed Solution Below)

Option 3 : Galvanometer

Torque on a Current Loop Question 10 Detailed Solution

CONCEPT:

Voltammeter:

  • A voltammeter or coulometer is a scientific instrument used for measuring the quantity of electricity (electric charge) through electrolytic action.
    • The SI unit of quantity of electricity is the coulomb.

Voltmeter:

  • voltmeter is an instrument used for measuring the electric potential difference between two points in an electric circuit.
    • Analog voltmeters move a pointer across a scale in proportion to the voltage of the circuit; digital voltmeters give a numerical display of voltage by use of an analog-to-digital converter

Galvanometer: 

  • A galvanometer works on the principle When a current-carrying coil is placed in an external magnetic field a magnetic torque is acting on it, and which is given by 

⇒ τ = NABI Sinθ 

Where N = Number of turns B = Magnetic field I = Current A = Area

EXPLANATION:

  • ​According to the principle of the galvanometer, the angle through which the loop is rotated is proportional to the current in the coil i.e.,

⇒ θ ∝ I 

  • Hence, option 3 is the answer
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