Electronic Devices and Circuits MCQ Quiz - Objective Question with Answer for Electronic Devices and Circuits - Download Free PDF

Last updated on Mar 18, 2025

Latest Electronic Devices and Circuits MCQ Objective Questions

Electronic Devices and Circuits Question 1:

The width of the arrow in an energy flow diagram represents __________.

  1. Energy flow speed
  2. Energy efficiency of the system
  3. the amount of energy being transferred
  4. temperature of the power source

Answer (Detailed Solution Below)

Option 3 : the amount of energy being transferred

Electronic Devices and Circuits Question 1 Detailed Solution

Explanation:
 
Detailed Solution:
 
Energy Flow Diagram is a type of visual tool that is used to show the flow of energy in a system. In this diagram, the flow of energy between different energy sources and users is represented through arrows. The width of the arrow means very important in the diagram as it shows the amount of energy that is being transferred from one point to another.
 
When we talk about energy flow diagram, the width of the arrow is used to show how much energy is flowing from one point to another. It is a type of parameter that shows the amount of energy flow. Thus, the greater the width of the arrow, the greater will be the amount of energy flow.
 
For example, if energy is flowing from a particular source to a consumer in an energy flow diagram, the width of the arrow will represent the amount of energy that is flowing from that source to that consumer. Thus, this diagram clearly shows the distribution of energy among different components of energy and helps in understanding how energy is being used and where energy is being lost.
 
Analysis of other options:
 
Now let us analyze other options:
 
Option 1: Speed ​​of energy flow
 
This option is incorrect because the width of the arrow in the energy flow diagram does not represent the speed of energy flow. Any other type of parameter or symbol can be used to represent the speed of energy flow, but the width of the arrow does not represent it.
 
Option 2: Energy efficiency of the system
 
This option is also incorrect. The width of the arrow does not represent the energy efficiency of the system. Other parameters can be used to measure energy efficiency, such as measuring the ratio of energy output and energy input.
 
Option 4: Temperature of the energy source
 
This option is also incorrect. The width of the arrow does not represent the temperature of the energy source. Thermometers or other temperature measuring devices are used to measure temperature.
 
Conclusion:
 
The width of the arrow in an energy flow diagram represents the amount of energy that is being transferred from one point to another. This diagram serves as a visual representation of energy flow and helps to understand how energy is being used and where energy is being lost. Analyzing the other options, it is clear that the width of the arrow does not represent the speed of energy flow, energy efficiency of the system or the temperature of the energy source. Thus, the correct option is option 3: The amount of energy being transferred.

Electronic Devices and Circuits Question 2:

What is a crucial factor to consider in designing an active filter for high-frequency applications? 

  1. The power supply voltage of the operational amplifier
  2. The open-loop gain of the operational amplifier
  3. The value of the input resistor
  4. The slew rate of the operational amplifier

Answer (Detailed Solution Below)

Option 4 : The slew rate of the operational amplifier

Electronic Devices and Circuits Question 2 Detailed Solution

Concept

When designing an active filter for high-frequency applications, it is crucial to consider various factors to ensure the filter's performance and efficiency. The operational amplifier (op-amp) used in the active filter plays a significant role in determining the overall performance of the filter. One of the most critical specifications of the op-amp for high-frequency applications is the slew rate.

Solution

  • The slew rate of an operational amplifier is defined as the maximum rate of change of the output voltage per unit time.
  • It is typically measured in volts per microsecond (V/µs). In high-frequency applications, the signals change rapidly, and the op-amp must be able to keep up with these changes without distortion.
  • A higher slew rate ensures that the op-amp can handle fast-changing signals effectively, which is essential for maintaining the integrity of the signal in high-frequency applications.

Additional Information

Option 1: The power supply voltage of the operational amplifier

While the power supply voltage is an important factor in the operation of an op-amp, it is not as crucial for high-frequency performance as the slew rate. The power supply voltage primarily affects the maximum output voltage swing and the overall power consumption of the op-amp.

Option 2: The open-loop gain of the operational amplifier

The open-loop gain of an op-amp is the amplification provided by the op-amp when no feedback is used. Although a high open-loop gain is generally desirable for precision applications, it is not the most critical factor for high-frequency performance. The open-loop gain tends to decrease at higher frequencies, and other factors like the slew rate become more significant.

Option 3: The value of the input resistor

The value of the input resistor can affect the input impedance and noise characteristics of the filter, but it does not directly impact the high-frequency performance of the op-amp. The slew rate is a more critical factor for ensuring that the op-amp can handle fast signal changes.

Option 4: The slew rate of the operational amplifier

The correct answer. The slew rate is a key specification for high-frequency applications because it determines how quickly the op-amp can respond to rapid changes in the input signal. A higher slew rate allows the op-amp to accurately follow fast signals without introducing distortion.

Electronic Devices and Circuits Question 3:

Barkhausen's Criterion for sustained oscillations in an oscillator circuit states that:

  1. The product of the loop gain and the feedback factor must be greater than one. 
  2. The loop gain must be zero. 
  3. The phase shift around the loop must be 180 degrees.
  4. The product of the loop gain and the feedback factor must be one.

Answer (Detailed Solution Below)

Option 4 : The product of the loop gain and the feedback factor must be one.

Electronic Devices and Circuits Question 3 Detailed Solution

The correct option is 4

  • The output of the oscillator will not depend upon input voltage because there is no input voltage for an oscillator
  • An oscillator is an amplifier circuit with positive feedback in which a part of the output is feedback to the input via a feedback circuit
  • It should satisfy Barkhausen criteria |Aβ| = 1, where A is the amplifier gain and β is the feedback gain 
     

Barkhausen Criterion 'or' Conditions for Oscillation:

The circuit will oscillate when two conditions, called Barkhausen’s criteria are met. These two conditions are:

  • The loop gain must be unity or greater.
  • The feedback signal feeding back at the input must be phase-shifted by 360° (which is the same as zero degrees). In most of the circuits, an inverting amplifier is used to produce 180° phase-shift and an additional 180° phase shift is provided by the feedback network.

Electronic Devices and Circuits Question 4:

In a non-inverting amplifier using an operational amplifier, the voltage gain is determined by which of the following? 

  1. The ratio of the feedback resistor to the input resistor
  2. The sum of the input and feedback resistors
  3. The open-loop gain of the operational amplifier
  4. The product of the input and feedback resistors

Answer (Detailed Solution Below)

Option 1 : The ratio of the feedback resistor to the input resistor

Electronic Devices and Circuits Question 4 Detailed Solution

Concept

An operational amplifier (op-amp) is a high-gain electronic voltage amplifier with a differential input and typically a single-ended output. In a non-inverting amplifier configuration, the input signal is applied to the non-inverting input of the op-amp. The voltage gain of the non-inverting amplifier is determined by the feedback network connected between the output and the inverting input.

In a non-inverting amplifier, the voltage gain (Av) is given by:

\(A_v = 1 + \frac{R_f}{R_{in}}\)

where Rf is the feedback resistor and Rin is the input resistor.

Solution

The question asks about the factor that determines the voltage gain in a non-inverting amplifier using an operational amplifier. The correct answer is option 1.

The voltage gain of a non-inverting amplifier is given by the formula:

\(A_v = 1 + \frac{R_f}{R_{in}}\)

Therefore, the voltage gain is determined by the ratio of the feedback resistor (Rf) to the input resistor (Rin).

Hence, the correct answer is option 1.

Electronic Devices and Circuits Question 5:

The brightness of LED depends upon _____; when source voltage is much _____ than diode voltage, then the brightness of the LED is approximately constant.

  1. temperature; smaller
  2. temperature; greater 
  3. current; greater 
  4. current; smaller

Answer (Detailed Solution Below)

Option 3 : current; greater 

Electronic Devices and Circuits Question 5 Detailed Solution

Explanation:

LED Brightness and Current

Introduction:

Light Emitting Diodes (LEDs) are semiconductor devices that emit light when an electric current passes through them. The brightness of an LED is primarily determined by the current flowing through it. Understanding the relationship between current and brightness is crucial for designing circuits that utilize LEDs effectively.

Correct Option Analysis:

The correct option is:

Option 3: Current; greater

This option correctly indicates that the brightness of an LED depends on the current flowing through it. When the source voltage is much greater than the diode voltage, the brightness of the LED becomes approximately constant. This phenomenon can be explained through the electrical characteristics of LEDs.

Top Electronic Devices and Circuits MCQ Objective Questions

Which of the following elements is NOT suitable for the fabrication of a light emitting diode structure?

  1. Gallium phosphide
  2. Indium gallium nitride
  3. Germanium
  4. Gallium arsenide

Answer (Detailed Solution Below)

Option 3 : Germanium

Electronic Devices and Circuits Question 6 Detailed Solution

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The correct answer is ​Germanium.

Key Points

  • Silicon and germanium are not suitable because those junctions produce heat and no appreciable IR or visible light.
    • Hence Germanium is NOT suitable for the fabrication of a light-emitting diode structure.

Additional Information

  • The LED (light-emitting diode) is a PN junction device that emits light when a current passes through it in the forward direction, i.e. when LED is forward biased, it emits light.
  • In an LED, this energy lies in the visible region of electromagnetic radiation, and the photon released is perceived as light.
  • The compound semiconductor Gallium Arsenide – Phosphide is used for making LEDs of different colours.
  • Gallium Arsenide is used for making infrared LED.
  • Gallium phosphide, Indium gallium nitride, and Gallium arsenide are used for the fabrication of a light-emitting diode.
  • LEDs are generally fabricated with Direct Band Gap (DBG) semiconductors like GaAs, GaAsP, and GaP.

Which of the following device is bidirectional?

  1. TRIAC
  2. SCR
  3. GTO
  4. BJT

Answer (Detailed Solution Below)

Option 1 : TRIAC

Electronic Devices and Circuits Question 7 Detailed Solution

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TRIAC allows the current in both directions and thus it is bidirectional.

SCR, GTO (Gate Turnoff Thyristor) and BJT allow the current in only one direction.

TRIAC:

06.11.2018.001..05

  • A TRIAC is equivalent to two SCRs joined together in parallel; It has two main terminal and one gate
  • In the TRIACs, there will be single gate control conduction in both the directions
  • It is a bidirectional device and in both the directions it will conduct
  • It is available in high voltage ratings
  • TRIAC is a  5-layer device

In a UJT, the emitter terminal is:

  1. Always of the N-Type
  2. P-type for an N bar
  3. Always of the P-Type
  4. of the N-Type for a P bar

Answer (Detailed Solution Below)

Option 3 : Always of the P-Type

Electronic Devices and Circuits Question 8 Detailed Solution

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The UJT is a three-terminal, semiconductor device which exhibits negative resistance and switching characteristics for use as a relaxation oscillator in phase control applications.

 

F1 R.K. Nita 23.10.2019 D 6

 

  • We observe that the emitter terminal is p-type.
  • The structure of a UJT is quite similar to that of an N-channel JFET.
  • In a unijunction transistor, the emitter is heavily doped while the N-region is lightly doped, so the resistance between the base terminals is relatively high, typically 4 to 10 kilo Ohm when the emitter is open.

 

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The basic differences between the UJT and the BJT are as follows:

UJT

BJT

Only one junction is present in UJT.

It consists of two Junctions. It is a two junction transistor.

The conduction in this transistor is based on the flow of the majority of the carriers through it.

The conduction in this transistor is completely based on the flow of both majority as well as the minority carriers through it.

It can be used as the voltage control device.

It can be categorized as the current control device.

UJT cannot be preferred for amplification.

BJT can be used as amplifiers.

In an Op-Amp inverting amplifier, the pin 2 of 741 IC is at virtual ground. This statement is based on which law?

  1. Kirchhoff’s Voltage Law
  2. Kirchhoff’s Current Law
  3. Ohm’s Law
  4. Coulomb’s Law

Answer (Detailed Solution Below)

Option 1 : Kirchhoff’s Voltage Law

Electronic Devices and Circuits Question 9 Detailed Solution

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Op-amp:

This IC is Dual Inline Package and it is represented as 741 IC.

The pin diagram is shown below:

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Pin 2 and 3 are input terminals.

Inverting terminal:

If we apply the input at this terminal the output will have a 180° phase shift.

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Non-inverting terminal:

If we apply the input at this terminal the output will not have any phase shift at the output.

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Kirchhoff’s Voltage law:

This law states that the algebraic sum of all voltages in a closed loop will be zero.

\(\sum {V_{loop}} = 0\)

Virtual ground:

Both the terminal voltages will be equal for an op-amp.

Here we are discussing the voltage and in a loop, it will be zero.

V1 = V2

V1 – V2 = 0

KVL is satisfied here

Which of the following oscillators is the most stable one?

  1. RC phase shift oscillator
  2. Colpitt’s oscillator
  3. Crystal oscillator
  4. Hartley oscillator

Answer (Detailed Solution Below)

Option 3 : Crystal oscillator

Electronic Devices and Circuits Question 10 Detailed Solution

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Crystal Oscillator:

A crystal oscillator is the most stable frequency oscillator.

Advantages:

  • The crystal oscillator is possible to obtain a very high precise and stable frequency of oscillators
  • It has very-low-frequency drift due to change in temperature and other parameters
  • The Q is very high
  • It has automatic amplitude control


Disadvantages:

  • These are suitable for high-frequency application
  • Crystals of low fundamental frequencies are not easily available

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  • Hartley and Colpitts's oscillators are LC oscillators.
  • LC oscillators are unstable oscillators.
  • Phase shift oscillator is suitable for oscillations in AF range up to 1 kHz
  • Crystals like quartz have high-quality factors, Q (range: 10- 106). The high-quality factor will result in high-frequency stability.

How are the junctions biased in a transistor when operating in the saturation region?

  1. Emitter base junction reverse biased and base-collector junction forward biased
  2. Both the junctions forward biased
  3. Both the junctions reverse biased
  4. Emitter base junction forward biased and base-collector junction reverse biased

Answer (Detailed Solution Below)

Option 2 : Both the junctions forward biased

Electronic Devices and Circuits Question 11 Detailed Solution

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A transistor can be operated in one of the three modes: 

1) Active Region

2) Saturation Region

3) Cut-off Region

The biasing for different mode of operation is as shown in the table:

Mode

Emitter -base 

Junction

Collector-Base 

Junction

Cut off

Reverse

Reverse

Active

Forward

Reverse

Reverse Active

Reverse

Forward

Saturation

Forward

Forward

 

∴ For a transistor operating in the saturation region, both the junctions need to be forward bias.

As compared to FET, BJT has ________ input impedance and ________ output impedance.

  1. low, low
  2. low, high
  3. high, high
  4. high, low

Answer (Detailed Solution Below)

Option 2 : low, high

Electronic Devices and Circuits Question 12 Detailed Solution

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BJT

MOSFET

Bipolar device

Unipolar device

Low input impedance

High input impedance

Current controlled device

Voltage-controlled device

Low on-state voltage drop and low conduction loss

High on-state voltage drop and higher conduction loss

Secondary breakdown occurs

Free from the secondary breakdown

Negative temperature coefficient

Positive temperature coefficient

Not advisable for parallel operation

advisable for parallel operation

Lower operating frequency(10kHz)

higher operating frequency(100kHz)

On state in the saturation region

On state in the ohmic region

Controlled turn on and turn off operation of the device

Controlled turn on and turn off operation of the device

Turn on and turn off time depend on junction capacitance

Smaller turn off time

Continuous Controlled signal requirement

Continuous Controlled signal requirement

In an op-amp, the input impedance is _______ and the output impedance is _______.

  1. high; high
  2. low; low
  3. low; high
  4. high; low

Answer (Detailed Solution Below)

Option 4 : high; low

Electronic Devices and Circuits Question 13 Detailed Solution

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Operational Amplifier (OP-AMP)

F4 Vinanti Engineering 06.02.23 D2

An operational amplifier (op-amp) is an integrated circuit (IC) that amplifies the difference in voltage between two inputs. 

It has two terminals i.e. inverting and non-inverting terminals.

The output of the OP-AMP is:

\(V_{OUT}=A_V({V_{NI}-V_I})\)

Properties of OP-AMP

  • High input impedance
  • Low output impedance
  • High CMRR
  • High gain
  • High slew rate
  • Low input offset voltage
  • High bandwidth

Which of the following circuits can be used as voltage doublers?

  1. Filters
  2. Clampers
  3. Adders
  4. Clippers

Answer (Detailed Solution Below)

Option 2 : Clampers

Electronic Devices and Circuits Question 14 Detailed Solution

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Clamper circuit:

  • A clamper is an electronic circuit that changes the DC level of a signal to the desired level without changing the shape of the applied signal.
  • The Clamper circuit moves the whole signal up or down to set either the positive feedback or negative feedback of the signal at the desired level.
  • It consists of capacitors and diodes to shift the voltage level.

 

In a Voltage doubler circuit, the output voltage is double the input voltage with the circuit diagram as shown:

554F2 R.D Madhu 22.10.19 D 11

Important Points

  • Clipper circuits are used to remove the part of a signal above or below some defined reference level.
  • One example of a clipper circuit is a half-wave rectifier that clips off the negative-going waveform.

What is an oscillator?

  1. A rectifier
  2. A generator
  3. An amplifier with positive feedback
  4. An amplifier with negative feedback

Answer (Detailed Solution Below)

Option 3 : An amplifier with positive feedback

Electronic Devices and Circuits Question 15 Detailed Solution

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Explanation:

An oscillator is: An amplifier with positive feedback

  • An oscillator is a circuit that generates a continuous, periodic waveform without the need for an external input signal.
  • It achieves this by using positive feedback, where a portion of the output is fed back to the input with a phase shift of 360 degrees (positive feedback).
  • This continuous feedback loop sustains and regenerates the oscillations, producing a waveform such as a sine wave, square wave, or triangle wave.
  • Oscillators are commonly used in electronic circuits for generating signals in applications such as radio frequency (RF) communication, audio synthesis, and clock generation.
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