Network Theorems MCQ Quiz - Objective Question with Answer for Network Theorems - Download Free PDF

Last updated on Jun 10, 2025

Latest Network Theorems MCQ Objective Questions

Network Theorems Question 1:

Find the voltage Vs in the circuit by using Kirchoff's Voltage Law. 

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  1. 10 V
  2. 20 V
  3. 30 V
  4. 50 V

Answer (Detailed Solution Below)

Option 3 : 30 V

Network Theorems Question 1 Detailed Solution

Kirchhoff's Voltage Law (KVL)

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According to KVL, the algebraic sum of the voltages in a closed loop is always zero.

ΣV = 0

\(-V_1+V_2+V_3+V_4=0\)

Calculation

Applying KVL as per the direction ABCD:

+ 50 - 30 - VS - 10 + 20 = 0

VS = 30 V

Network Theorems Question 2:

A single-phase AC circuit has a voltage of 230 V and a current of 10 A. What is the apparent power (S)?

  1. 2.3 kVA
  2. 2.3 kW
  3. 23 VA
  4. 2300 VAR

Answer (Detailed Solution Below)

Option 1 : 2.3 kVA

Network Theorems Question 2 Detailed Solution

Apparent Power:

  • Apparent power is the total power that appears to be transferred between the source and load in an AC circuit.
  • It is given by S = VI
  • The unit of apparent power is Volt-Amperes (VA).


Calculation

Given, V = 230 volts

I = 10 A

S = 230 × 10

S = 2300 VA = 2.3 kVA

Additional Information 
Active Power:

  • Active power is the real power consumed by the circuit.
  • It is given by: P = VI cosϕ
  • The unit of active power is watts (W).


Reactive Power:

  • Reactive power is the electrical power that oscillates between the source and the load without performing useful work.
  • It is given by P = VI sinϕ
  • The unit of reactive power is Volt-Ampere Reactive (VAR).

Network Theorems Question 3:

In Norton’s Theorem, the equivalent circuit consists of _____.

  1. a voltage source in parallel with a resistor
  2. a current source in series with a resistor
  3. a current source in parallel with a resistor
  4. a voltage source in series with a resistor

Answer (Detailed Solution Below)

Option 3 : a current source in parallel with a resistor

Network Theorems Question 3 Detailed Solution

Concept:

Norton’s Theorem states that any linear electrical network with voltage and current sources and resistors can be replaced at terminals A-B by an equivalent circuit consisting of a current source in parallel with a resistor.

Calculation

The Norton equivalent circuit includes: - Norton Current (IN): The short-circuit current through the output terminals. - Norton Resistance (RN): The equivalent resistance seen from the terminals when all independent sources are turned off. These two elements are connected in parallel.

Hence, the equivalent circuit consists of a current source in parallel with a resistor.

Network Theorems Question 4:

Norton's Theorem is a way to reduce a network to

  1. An equivalent circuit composed of a single current source, series resistance, and series load
  2. An equivalent circuit composed of a single voltage source, parallel resistance, and parallel load
  3. An equivalent circuit composed of a single voltage source, series resistance, and series load
  4. An equivalent circuit composed of a single current source, parallel resistance, and parallel load 

Answer (Detailed Solution Below)

Option 4 : An equivalent circuit composed of a single current source, parallel resistance, and parallel load 

Network Theorems Question 4 Detailed Solution

Explanation:

Norton’s Theorem

Definition: Norton’s Theorem is a fundamental concept in electrical circuit analysis. It states that any linear electrical network with voltage or current sources and resistances can be replaced by an equivalent circuit composed of a single current source in parallel with a single resistor connected to a load. This theorem is particularly useful for simplifying complex circuits to make analysis more manageable.

Correct Option Analysis:

The correct option is:

Option 4: An equivalent circuit composed of a single current source, parallel resistance, and parallel load.

This option accurately reflects the essence of Norton’s Theorem. According to the theorem, any linear network can be replaced by an equivalent circuit consisting of:

  1. A single current source (known as Norton’s equivalent current, denoted as IN).
  2. A single resistance (known as Norton’s equivalent resistance, denoted as RN) connected in parallel with the current source.
  3. A load resistance connected in parallel with the equivalent circuit.

Steps to Apply Norton’s Theorem:

  1. Identify the portion of the circuit: Select the part of the circuit where you want to calculate the load current or voltage, and remove the load resistance temporarily.
  2. Calculate Norton’s Equivalent Current (IN): Short-circuit the terminals where the load resistance was connected and calculate the current flowing through the short circuit. This current is IN.
  3. Calculate Norton’s Equivalent Resistance (RN): Turn off all independent sources (replace voltage sources with short circuits and current sources with open circuits) in the original circuit, and calculate the equivalent resistance seen from the open terminals. This resistance is RN.
  4. Reconstruct the Norton Equivalent Circuit: Replace the original network with an equivalent circuit consisting of IN in parallel with RN, and reconnect the load resistance to this equivalent circuit.
  5. Analyze the Equivalent Circuit: Use parallel circuit analysis to calculate the current through or voltage across the load resistance.

Advantages of Norton’s Theorem:

  • It simplifies complex circuits, making it easier to analyze the behavior of the circuit with different load resistances.
  • It is particularly useful for determining the current through or voltage across a specific load resistor in a circuit with multiple components.
  • The theorem is applicable to both AC and DC circuits as long as the circuit is linear.

Disadvantages of Norton’s Theorem:

  • It is limited to linear circuits and cannot be applied to circuits with non-linear elements such as diodes and transistors.
  • The process of turning off independent sources and calculating equivalent resistance may become cumbersome for very large and complex circuits.

Applications:

  • Used in electrical circuit analysis to simplify the study of load variations.
  • Widely applied in power systems and electronics to understand the behavior of networks under different loading conditions.
  • Useful in network theorems for solving problems in both academic and practical engineering scenarios.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: An equivalent circuit composed of a single current source, series resistance, and series load.

This option is incorrect because it does not align with the principles of Norton’s Theorem. Norton’s Theorem specifies that the equivalent circuit consists of a current source in parallel with a resistance. A series configuration of resistance and load is not applicable in the context of Norton’s equivalent circuit.

Option 2: An equivalent circuit composed of a single voltage source, parallel resistance, and parallel load.

This option describes a configuration that is related to Thevenin’s Theorem, not Norton’s Theorem. Thevenin’s Theorem states that any linear electrical network can be replaced by an equivalent circuit consisting of a single voltage source in series with a resistance. The presence of a voltage source and parallel components makes this option inconsistent with Norton’s Theorem.

Option 3: An equivalent circuit composed of a single voltage source, series resistance, and series load.

Similar to option 2, this description corresponds to Thevenin’s equivalent circuit. Thevenin’s Theorem involves a voltage source in series with a resistance, whereas Norton’s Theorem involves a current source in parallel with a resistance. Hence, this option is also incorrect.

Option 5: (Not mentioned in the problem context).

Since there is no description provided for Option 5, it is not relevant to the question and does not align with the principles of Norton’s Theorem.

Conclusion:

Norton’s Theorem is a powerful tool for simplifying the analysis of electrical circuits, especially when focusing on the behavior of a specific load. The correct representation of Norton’s equivalent circuit involves a single current source in parallel with a single resistance and a parallel load. This configuration facilitates efficient circuit analysis and provides insights into the impact of load variations on the overall circuit behavior. By contrast, the other options either describe configurations unrelated to Norton’s Theorem or pertain to Thevenin’s Theorem, highlighting the importance of understanding the distinctions between these two fundamental network theorems.

Network Theorems Question 5:

What is the Thevenins equivalent resistance at the terminals X, Y for the circuit shown in the figure?

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  1. 3 kΩ
  2. 9 kΩ
  3. 6 kΩ
  4. 2 kΩ

Answer (Detailed Solution Below)

Option 4 : 2 kΩ

Network Theorems Question 5 Detailed Solution

Thevenin Theorem

Thevenin’s theorem states that it is possible to simplify any linear circuit, into an equivalent circuit with a single voltage source and a series resistance.

Steps to calculate:

  1. Thevenin Resistance (Rth): Open the circuit to the terminal from where the Thevenin resistance has to be found. While finding the Rth, short circuit the independent voltage source and open circuit the independent current source.
  2. Thevenin Voltage (Vth): This is the open-circuit voltage across the terminals where the load was connected.
     

Calculation

Open circuit the terminal XY to calculate Rth

qImage67d58d8965a01d0b543ed17c

3 kΩ, 1 kΩ and 2 kΩ are connected in series.

R = 3 + 2 + 1 = 6 kΩ 

This 6 kΩ and 3 kΩ are connected in parallel.

\(R_{XY}={6\times 3\over 6+3}\)

RXY = 2 kΩ 

Top Network Theorems MCQ Objective Questions

A voltage source having some internal resistance delivers a 2A current when a 5Ω load is connected to it. When the load is 10Ω, then the current becomes 1.6A. Calculate the power transfer efficiency of the source for a 15Ω load.

  1. 90%
  2. 50%
  3. 100%
  4. 10%

Answer (Detailed Solution Below)

Option 2 : 50%

Network Theorems Question 6 Detailed Solution

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Concept

The power transfer efficiency is:

\(η={I^2R_L\over VI}\times 100\)

\(η={IR_L\over V}\times 100\)

The current across any resistor is given by:

\(I={V\over R}\)

where, I = Current

V = Voltage

R = Resistance

Calculation

Let the voltage and internal resistance of the voltage source be V and R respectively.

Case 1: When the current of 2 A flows through 5 Ω resistance.

\(2={V\over 5+R}\) .... (i)

Case 2: When the current of 1.6 A flows through 10 Ω resistance.

\(1.6={V\over 10+R}\) .....(ii)

Solving equations (i) and (ii), we get:

2(5+R)=1.6(10+R)

10 + 2R = 16 + 1.6R

0.4R = 6

R = 15Ω

Putting the value of R = 15Ω in equation (i):

V = 40 volts

Case 3: Current when the load is 15Ω

\(I={V\over R+R_L}\)

\(I={40\over 15+15}={4\over 3}A\)

\(η={{4\over 3}\times 15\over 40}\times 100\)

η = 50%

Additional Information Condition for Maximum Power Transfer Theorem:

When the value of internal resistance is equal to load resistance, then the power transferred is maximum.

Under such conditions, the efficiency is equal to 50%.

As shown in the figure, a 1Ω resistance is connected across a source that has a load line V + i = 100. The current through the resistance is

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  1. 25 A
  2. 50 A
  3. 100 A
  4. 200 A

Answer (Detailed Solution Below)

Option 2 : 50 A

Network Theorems Question 7 Detailed Solution

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Concept:

Thevenin's Theorem:

Any two terminal bilateral linear DC circuits can be replaced by an equivalent circuit consisting of a voltage source and a series resistor.

To find Voc: Calculate the open-circuit voltage across load terminals. This open-circuit voltage is called Thevenin’s voltage (Vth).

To find Isc: Short the load terminals and then calculate the current flowing through it. This current is called Norton current (or) short circuit current (isc).

To find Rth: Since there are Independent sources in the circuit, we can’t find Rth directly. We will calculate Rth using Voc and Isc and it is given by

\({{\rm{R}}_{{\rm{th}}}} = \frac{{{{\rm{V}}_{{\rm{oc}}}}}}{{{{\rm{i}}_{{\rm{sc}}}}}}\)  

Application:

Given: Load line equation = V + i = 100

To obtain open-circuit voltage (Vth) put i = 0 in load line equation 

⇒ Vth = 100 V

To obtain short-circuit current (isc) put V = 0 in load line equation

⇒ isc = 100 A

So, \({R_{th}} = \frac{{{V_{th}}}}{{{i_{sc}}}} = \frac{{100}}{{100}} = 1{\rm{\Omega }}\)

Equivalent circuit is

Gate EE NETWORK 1 mobile-Images-Q51.1

Current (i) = 100/2 = 50 A

 

Applying loop-law in the given circuit.

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- V + i × R = 0

- V + I × 1 = 0

⇒ V = i

Given Load line equation is V + i = 100

Putting V = i 

then i + i = 100 

⇒ i = 50 A

Which of the following statements are true for KCL and KVL

(a) Valid for distributed parameters networks

(b) Valid for lumped parameters networks

(c) Valid for linear elements

(d) Valid for non-linear elements

Code:

  1. (b) and (c)
  2. (a), (b) and (c)
  3. (b), (c) and (d)
  4. (a), (c) and (d)

Answer (Detailed Solution Below)

Option 3 : (b), (c) and (d)

Network Theorems Question 8 Detailed Solution

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Distributed Network:

  • If the network element such as resistance, capacitance, and inductance are not physically separated, then it is called a Distributed network.
  • Distributed systems assume that the electrical properties R, L, C, etc. are distributed across the entire circuit.
  • These systems are applicable for high (microwave) frequency applications.

Lumped Network:

  • If the network element can be separated physically from each other, then they are called a lumped network.
  • Lumped means a case similar to combining all the parameters and considering it as a single unit.
  • Lumped systems are those systems in which electrical properties like R, L, C, etc. are assumed to be located on a small space of the circuit.
  • These systems are applicable to low-frequency applications.

Kirchoff's Laws:

  • Kirchhoff’s laws are used for voltage and current calculations in electrical circuits.
  • These laws can be understood from the results of the Maxwell equations in the low-frequency limit.
  • They are applicable for DC and AC circuits at low frequencies where the electromagnetic radiation wavelengths are very large when we compare with other circuits. So they are only applicable for lumped parameter networks.

Kirchhoff's current law (KCL) is applicable to networks that are:

  • Unilateral or bilateral 
  • Active or passive 
  • Linear or non-linear
  • Lumped network

KCL (Kirchoff Current Law): According to Kirchhoff’s current law (KCL), the algebraic sum of the electric currents meeting at a common point is zero.

Mathematically we can express this as:

\(\mathop \sum \limits_{n = 1}^M {i_n} = 0\)

Where in represents the nth current

M is the total number of currents meeting at a common node.

KCL is based on the law of conservation of charge.

Kirchhoff’s Voltage Law (KVL):

It states that the sum of the voltages or electrical potential differences in a closed network is zero. 

According to Tellegen's Theorem, the sum of instantaneous powers for the n branches in a network is always:

  1. Constant
  2. Equal to zero
  3. In-phase with current
  4. Alternating

Answer (Detailed Solution Below)

Option 2 : Equal to zero

Network Theorems Question 9 Detailed Solution

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  • According to Tellegen’s theorem, the summation of instantaneous powers for the n number of branches in an electrical network is zero.
  • Let n number of branches in an electrical network have I1, I2, I3, ….. In respective instantaneous currents through them.
  • These branches have instantaneous voltages across them are V1, V2, V3, ….. Vn respectively.
  • According to Tellegen’s theorem, \(\mathop \sum \limits_{k = 1}^n {V_k}.{I_k} = 0\)
  • It is based on the conservation of energy.
  • It is applicable to both linear and non-linear circuits.

Consider the following network

F1 Vijay 19-02-21 Savita D4

Suppose Va = 60 V and R is adjustable then find the value of 'R' such that maximum power is transferred through network N2 from network N1

  1. 7 Ω
  2. 8 Ω
  3. 9 Ω
  4. 10 Ω

Answer (Detailed Solution Below)

Option 2 : 8 Ω

Network Theorems Question 10 Detailed Solution

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Concept:

Maximum power transfer theorem:

Maximum power transfer theorem states that " In a linear bilateral network if the entire network is represented by its Thevenin's equivalent circuit then the maximum power transferred from source to the load when the load impedance is equal to the complex conjugate of  Thevenin's impedance.

Let's consider variable resistive load and Thevenin's equivalent network as shown below,

F1 Jai 9.11.20 Pallavi D1 

\({P_m} = \frac{{V_{th}^2}}{{4{R_{th}}}}\)

Where, 

Pm is the maximum power 

Vth is the source voltage or Thevenin's voltage

Rth is the Thevenin's resistance (Rth = RL = RS)

The efficiency of the maximum power transfer theorem will be 50 %

The voltage across the load resistance/impedance is VL = VS / 2

Calculation:

Given the circuit diagram

F1 Vijay 19-02-21 Savita D4

Source voltage VS = 200 V

Va = 60 V

As V is the voltage across the load.

V = VS / 2 = 200 / 2 = 100 V

Load current i = V / RL (When maximum power is transferred RL = RS = Rth = 10 Ω) 

i = 100 / 10 = 10 A

By applying nodal analysis at node V

\( - i + \frac{V}{{20}} + \frac{{V - {V_a}}}{R} = 0\)

\( - 10 + \frac{{100}}{{20}} + \frac{{100 - 60}}{R} = 0\)

R = 8 Ω

Therefore, the value of R is 8 Ω when Va is 60 V and maximum power is transferred from N1 to N2

Calculate current I in the following circuit using superposition theorem.

F1 Shubham Madhuri 11.05.2021 D12

  1. 375 mA
  2. 200 mA
  3. 150 mA
  4. 100 mA

Answer (Detailed Solution Below)

Option 1 : 375 mA

Network Theorems Question 11 Detailed Solution

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Concept:

Superposition theorem is used to solve a circuit that contains multiple current and/or voltage sources acting together.

Theorem:

  • The superposition theorem states that "in a linear circuit with several sources, the current and voltage for any element in the circuit is the sum of the currents and voltages produced by each source acting independently."
  • The superposition theorem applies only when all the components of the circuit are linear, which is the case for resistors, capacitors, and inductors it is not applicable to networks containing nonlinear elements.


​Calculation:

case 1:

When 8 V source are there

F1 Shubham Madhuri 11.05.2021 D13

I = 8 / 16 = 0.5 A

case 2:

When only 2 A current source present

F1 Shubham Madhuri 11.05.2021 D14

Apply KVL in loop

6 I + 2 ( I - 2 )+ 8 I = 0

I = 0.25 A

case 3:

When 6 V source are there

F1 Shubham Madhuri 11.05.2021 D15

I = - 6 / 16 = - 0.375 A

Now using superposition theorem

Total current I = 0.5 + 0.25 + ( - 0.375 ) A

= 0.375 A

= 375 mA

Important Points

Various Theorem and the circuits where they are applicable is shown below in the table:

Theorem

Applicability

Superposition Theorem

Linear

Thevenin Theorem

Linear

Norton Theorem

Linear

Maximum Power Transfer

Linear

Tellegen

All

Substitution

Linear and Non-Linear

A DC voltage source has a source resistance variable from 5 Ω to 25 Ω and it is connected to a load of 10 Ω. For maximum power transfer, the source resistance should be:

  1. 5 Ω 
  2. 10 Ω 
  3. 15 Ω 
  4. 25 Ω 

Answer (Detailed Solution Below)

Option 1 : 5 Ω 

Network Theorems Question 12 Detailed Solution

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Concept:

Maximum power transfer theorem:

  • Maximum power transfer theorem states that " In a linear bilateral network if the entire network is represented by its Thevenin's equivalent circuit then the maximum power transferred from source to the load when the load resistance is equal to the Thevenin's resistance."
  • P=VS2.RL(RS+RL)2" role="presentation" style="display: inline; position: relative;" tabindex="0">P=VS2.RL(RS+RL)2For maximum power transfer, RL = Rth 
  • Then the maximum power transferred is given by \({{\rm{P}}_{max}} = {\rm{\;}}\frac{{V_S^2}}{{4{R_L}}}\)

Explanation:

Circuit Diagram

F1 Nakshatra Anil 14-06.21 D2

Given,

Rs = 5 to 25 Ω (variable)

RL = 10 Ω (fixed)

Here Maximum Power Transfer theorem is not applicable as the load resistor is not variable.

Current, \(I=\frac{V}{R_s+R_L}\)

Power transferred to load RL,

\(P=I^2R_L=[\frac{V}{R_S+R_L}]^2\times R_L\)

It is clear that for P to be maximum, RS should be minimum.

∴ RS = 5 Ω 

Additional Information 

Properties of maximum power transfer theorem: 

  • This theorem is applicable only for linear networks i.e networks with R, L, C, transformer, and linear controlled sources as elements.
  • The presence of dependent sources makes the network active and hence, MPPT is used for both active as well as passive networks.
  • This theorem is applicable when the load is variable.


Maximum power transfers at RL = Rs

The current at this condition is,

\(I_L=\frac{V_S}{2R_L}=\frac{V_S}{2R_S}\)

The maximum value of current occurs at R = 0 and is given by
\(I_L=\frac{V}{R_S}\)

Therefore, the current at maximum power is equal to 50% of the maximum current

Key Points

  •  If source impedance is complex then load impedance has to be a complex conjugate of source impedance for maximum power transfer to occur.
  •  Maximum efficiency is not related to maximum power transfer.

Reciprocity theorem cannot be applied to the circuits having ______.

  1. Linear elements
  2. Dependent sources
  3. Bilateral elements
  4. Passive elements

Answer (Detailed Solution Below)

Option 2 : Dependent sources

Network Theorems Question 13 Detailed Solution

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Reciprocity theorem:

Reciprocity theorem states that in any branch of a network, the current (I) due to a single source of voltage (V) elsewhere in the network is equal to the current through the branch in which the source was originally placed when the source is placed in the branch in which the current (I) was originally obtained.

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In the circuit (a), the value Iis obtained for a voltage source V. According to reciprocity theorem, this current is equivalent to Ib in the circuit B.

Limitations of reciprocity theorem:

  • The network should be bilateral linear and time-invariant.
  • It can apply only to the single-source network and not for multi-source.
  • It is also applicable for passive networks consisting L,C.
  • Not applicable for circuits containing dependent sources even if it is linear.

Determine the load resistance RL that will result in maximum power delivered to the load for the given circuit. Also, determine the maximum power Pmax delivered to the load resistor.

F1 ENG Savita 12-04-24 D1 V2

  1. RL = 50 Ω; Pmax = 225 W
  2. RL = 35 Ω; Pmax = 200 W
  3. RL = 20 Ω; Pmax = 200 W
  4. RL = 25 Ω; Pmax = 225 W

Answer (Detailed Solution Below)

Option 4 : RL = 25 Ω; Pmax = 225 W

Network Theorems Question 14 Detailed Solution

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Concept:

Maximum power transfer for DC circuit:

F1 Jai 9.11.20 Pallavi D1

According to the MPT the maximum power transfer to the load when the load resistance is equal to the source resistance or Thevenin resistance.

RL = Rth 

RL = load resistance

Rth = Thevenin or source resistance

The power at maximum power transfer (Pmax) = Vth2 / 4Rth

The maximum power transfer theorem is used in electrical circuits.

Calculation:

F1 Ravi Ranjan Ravi 10.05.21 D1

Rth = RL

= ( 30 × 150 )  / 180

= 25 Ω 

F1 Ravi Ranjan Ravi 10.05.21 D2

Vth = Vab 

= ( 150 × 180 ) / (150 + 30 )

= 150 V

From above concept,

\(P_{max}=\frac{V_{th}^2}{4R_{th}}=\frac{150^2}{4\times25}=225\ W\)

Pmax = 225 W

Reciprocity theorem is applicable to a network

1. Containing R, L and C elements

2. Which is initially not a relaxed system

3. Having both dependent and independent sources

Which of the above is/are correct?

  1. 1 only
  2. 1 and 2 only
  3. 2 and 3 only
  4. 1, 2 and 3

Answer (Detailed Solution Below)

Option 1 : 1 only

Network Theorems Question 15 Detailed Solution

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Reciprocity theorem: It states that the current I in any branch of a network, due to single voltage source (E) anywhere in the network is equal to the current of the branch in which source was placed originally and when the source is again put in the branch in which current is obtained originally.

Limitations of reciprocity theorem:

  • The network should be linear and time-invariant
  • It can apply only to the single-source network
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