Right Circular Cylinder MCQ Quiz - Objective Question with Answer for Right Circular Cylinder - Download Free PDF
Last updated on Jun 7, 2025
Latest Right Circular Cylinder MCQ Objective Questions
Right Circular Cylinder Question 1:
Water flows out through a pipe, whose internal radius is 3 cm, at the rate of x cm per second into a cylindrical tank, the radius of whose base is 60 cm. If the level of water in the tank rises by 15 cm in 5 minutes, then the value of x is :
Answer (Detailed Solution Below)
Right Circular Cylinder Question 1 Detailed Solution
Given:
Internal radius of the pipe (rpipe) = 3 cm
Rate of water flow from the pipe (speed of water) = x cm/second
Radius of the base of the cylindrical tank (Rtank) = 60 cm
Rise in water level in the tank (htank) = 15 cm
Time taken (T) = 5 minutes
Formula used:
Volume of water flowing out of the pipe in a given time = Area of cross-section of pipe × Speed of water × Time
Volume of water in cylindrical tank = πR2h
Calculation:
T = 5 minutes × 60 seconds/minute = 300 seconds
Volume of water flowed from pipe = Volume of water in the tank
Volume of water flowed from pipe = (π × rpipe2) × (rate of flow) × Time
= π × (3 cm)2 × (x cm/second) × (300 seconds)
= π × 9 × x × 300 cm3 = 2700πx cm3
Volume of water in the tank = π × Rtank2 × htank
= π × (60 cm)2 × (15 cm)
= π × 3600 × 15 cm3
= 54000π cm3
Equating the two volumes:
2700πx = 54000π
2700x = 54000
x = 54000 / 2700
x = 540 / 27
x = 20
∴ The correct answer is option 3.
Right Circular Cylinder Question 2:
Volume of cylinder and cone are in the ratio 25: 16, their height are in the ratio 3: 4. Then ratio of radii of base of cylinder and cone is
Answer (Detailed Solution Below)
Right Circular Cylinder Question 2 Detailed Solution
Given:
Ratio of Volume of Cylinder to Volume of Cone = 25 : 16
Ratio of Height of Cylinder (H1) to Height of Cone (H2) = 3 : 4
Formula Used:
Volume of Cylinder (Vcyl) = πR12H1
Volume of Cone (Vcone) = (1/3)πR22H2
Calculation:
According to the given information:
Vcyl / Vcone = 25 / 16
(πR12H1) / ((1/3)πR22H2) = 25 / 16
Substitute the ratio of heights H1/H2 = 3/4, so H1 = (3/4)H2:
(πR12(3/4)H2) / ((1/3)πR22H2) = 25 / 16
⇒ (3/4)R12 / ((1/3)R22) = 25 / 16
⇒ [(3/4)R12 × 3] / (1 × R22) = 25 / 16
⇒ 9R12 / 4R22 = 25 / 16
⇒ R12 / R22 = (25 / 16) × (4 / 9)
R12 / R22 = 100 / 144
⇒ R1 / R2 = √(100 / 144)
⇒ R1 / R2 = 10 / 12
⇒ R1 / R2 = 5 / 6
∴ The ratio of the radii of the base of the cylinder and the cone is 5 : 6.
Right Circular Cylinder Question 3:
A housing society consisting of 2,750 people needs 100 L of water per person per day. The cylindrical supply tank is 7 m high and has a diameter of 10 m. For how many days will the water in the tank last for the society?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 3 Detailed Solution
Given:
Number of people = 2,750
Water requirement per person per day = 100 L
Height of cylindrical tank (h) = 7 m
Diameter of cylindrical tank = 10 m
Radius of cylindrical tank (r) = Diameter / 2 = 10 / 2 = 5 m
Formula used:
Volume of cylinder = \(\pi r^2 h\)
Total water requirement per day = Number of people × Water requirement per person
Number of days water lasts = Volume of tank / Total water requirement per day
Calculation:
Volume of tank = \(\pi r^2 h\)
⇒ Volume = \(\pi × 5^2 × 7\)
⇒ Volume = \(\pi × 25 × 7 = 175\pi\) m3
Convert volume to liters (1 m3 = 1,000 L):
⇒ Volume in liters = \((175\pi × 1000)\) = 175,000\(\pi\) L
Using \(\pi \approx 22/7\):
⇒ Volume in liters = \((175,000 × 22/7 = 5,50,000)\) L
Total water requirement per day = 2,750 × 100 = 275,000 L
Number of days water lasts = \(\frac{\text{Volume of tank}}{\text{Total water requirement per day}}\)
⇒ Number of days = \(\frac{ 5,50,000}{275,000}\)
⇒ Number of days ≈ 2 days
∴ The correct answer is option (3).
Right Circular Cylinder Question 4:
A cylindrical vessel of radius 3.5 m is full of water. If 15400 litres of water is taken out from it, then the drop in the water level in the vessel will be?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 4 Detailed Solution
Given:
Radius of the cylindrical vessel = 3.5 m
Volume of water taken out = 15400 liters = 15.4 m3
Formula Used:
Volume of a cylinder = π × radius2 × height
Drop in water level = Volume taken out / (π × radius2)
Calculation:
Radius = 3.5 m
Volume taken out = 15.4 m3
π = 3.14
Drop in water level = Volume taken out / (π × radius2)
⇒ Drop in water level = 15.4 / (3.14 × 3.52)
⇒ Drop in water level = 15.4 / (3.14 × 12.25)
⇒ Drop in water level = 15.4 / 38.465
⇒ Drop in water level ≈ 0.4 m
Convert to cm: 0.4 × 100 = 40 cm
The drop in the water level in the vessel is 40 cm.
Right Circular Cylinder Question 5:
The volume of a cylindrical tank is 12,320 m³. If the radius of the base is 14 m, then the depth of the tank is: (Use
Answer (Detailed Solution Below)
Right Circular Cylinder Question 5 Detailed Solution
Given:
Volume of the tank (V) = 12,320 m3
Radius of the base (r) = 14 m
Formula used:
Volume of a cylinder: V = πr2h
Where, h = depth of the tank
Calculation:
12,320 = (22/7) × 14 × 14 × h
⇒ h = 12,320 / [(22/7) × 14 × 14]
⇒ h = 12,320 / (44 × 14)
⇒ h = 12,320 / 616
⇒ h = 20 m
∴ The correct answer is option (1).
Top Right Circular Cylinder MCQ Objective Questions
A closed cylindrical tank with a height of 1 m and a base diameter of 140 cm must be constructed from a metal sheet. For the same, how many m2 of the sheet are required? [Use π = 22/7]
Answer (Detailed Solution Below)
Right Circular Cylinder Question 6 Detailed Solution
Download Solution PDFGiven:
Height of the cylinder = 1 m
Diameter = 140 cm = 1.4 m, so radius = 1.4/2 = 0.7 m
Concept used:
Total surface area of the cylinder = 2πrh + 2πr2
Calculation:
Total sheet required = 2πrh + 2πr2 = 2πr(h + r)
⇒ 2 × 22/7 × 0.7 × (1 + 0.7)
⇒ 4.4 × 1.7
⇒ 7.48 m2
∴ The correct answer is 7.48 m2.
The ratio of the volume of first and second cylinder is 32 ∶ 9 and the ratio of their heights is 8 ∶ 9. If the area of the base of the second cylinder is 616 cm2, then what will be the radius of the first cylinder?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 7 Detailed Solution
Download Solution PDFGiven:
Volume ratio = 32 ∶ 9
Ratio of their heights is 8 ∶ 9
Area of the base of the second cylinder is 616 cm2
Concept Used:
Volume of cylinder = πr2h
Calculation:
Volume of the cylinder can be written as 32y and 9y
Height of the cylinder can be written as 8h and 9h
Since we know that the Volume of cylinder is Area of base × height
⇒ Volume of second cylinder = 616 × 9h
Let the radius of first cylinder be r
⇒ base area of first cylinder = πr2
Volume of first cylinder = πr2 × 8h
Their ratios can be written as
⇒ 616 × 9h/ (πr2 × 8h) = 9/32
Put π = 22/7
⇒ (22r2 × 8)/(616 × 9 × 7)/ = 32/9
⇒ r2 = (616 × 9 × 32 × 7)/(9 × 22 × 8)
⇒ r = 28
∴ Radius of first cylinder is 28 cm.
∴ Option 3 is the correct answer.
The ratio between the height and radius of the base of a cylinder is 7 ∶ 5. If its volume is 14836.5 cm3, then find its total surface area (take π = 3.14).
Answer (Detailed Solution Below)
Right Circular Cylinder Question 8 Detailed Solution
Download Solution PDFGiven:
The ratio between the height and radius of the base of a cylinder is 7 ∶ 5.
Volume is 14836.5 cm3
Formula used:
Volume of cylinder = πr2h
TSA of cylinder = 2πr(r + h)
Calculation:
Let the height be 7x and radius be 5x
According to the question,
Volume = π (5x)2 × 7x
⇒ 14836.5 = (3.14)(25x2) × 7x
⇒ 14836.5 = (3.14)(25x2) × 7x
⇒ 175x3 = 14836.5/3.14
⇒ x3 = 4725/175
⇒ x3 = 27
⇒ x = 3
Now,
Radius = 5x = 5 × 3 = 15 cm
Height = 7x = 7 × 3 = 21 cm
For TSA of cylinder,
TSA = 2(3.14) × 15 × (15 + 21)
⇒ TSA = 6.28 × 15 × 36
⇒ TSA = 3391.2 cm2
∴ The TSA of the cylinder is 3391.2 cm2.
The diameter of the base of a cylinder is 35 cm and its curved surface area is 3080 cm2. Find the volume of cylinder(in cm3).
Answer (Detailed Solution Below)
Right Circular Cylinder Question 9 Detailed Solution
Download Solution PDFGiven:
Diameter of cylinder = 35 cm
Curved surface area = 3080 cm2
Formula used:
Radius = Diameter/2
Curved surface are of cylinder = 2πrh
Volume of cylinder = πr2h
where r = radius , h = height
Calculation:
Diameter (d) = 35 cm
⇒ Radius = d/2
⇒ 35/2
⇒Radius = 17.5
Curved surface area of cylinder = 2πrh = 3080
⇒ 2 × 22/7 × 17.5 × h = 3080
⇒ h = 28 cm
Now Volume of cylinder = πr2h
⇒ 22/7 × (17.5)2 × 28
⇒ 22 × 306.25 × 4
⇒ 26,950 cm3
∴ Volume of cylinder is 26,950 cm3.
The sum of the radius of the base and the height of a solid right circular cylinder is 39 cm. Its total surface area is 1716 cm2. What is the volume (in cm3) of the cylinder? (Take π = \(\frac{22}{7}\))
Answer (Detailed Solution Below)
Right Circular Cylinder Question 10 Detailed Solution
Download Solution PDFGiven:
Sum of radius and height of the cylinder = 39 cm
Total surface area of the cylinder = 1716 cm2
Concept used:
Total surface area of a cylinder = 2πr(h + r)
Volume = πr2h
Here,
r = radius
h = height
Calculation:
Let the radius and the height of the cylinder be r and h,
According to the question,
2πr(h + r) = 1716 ----(i)
(h + r) = 39 ----(ii)
Putting the value of eq (ii) in eq (i) we get,
2πr × 39 = 1716
⇒ 2πr = 1716/39
⇒ 2πr = 44
⇒ πr = 22
⇒ r = 22 × (7/22)
⇒ r = 7
So, radius = 7 cm
Now, by putting the value of r in the eq (ii) we get
h + 7 = 39
⇒ h = 32
So, height = 32 cm
Now, volume = (22/7) × 72 × 32
⇒ 22 × 7 × 32
⇒ 4928
So, volume of the cylinder = 4928 cm3
∴ The volume (in cm3) of the cylinder i 4928.
Curved surface area of a cylinder is 308 cm2, and height is 14 cm. What will be the volume of the cylinder?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 11 Detailed Solution
Download Solution PDFGiven:
Curved surface area of cylinder = 308 cm2
Height = 14 cm
Formula used:
CSA (Curved surface area) = 2πrh
Volume = πr2h
Where r is radius and h is height
Calculation:
CSA = 2πrh
308 = 2 × (22/7) × r × 14
⇒ 308 = 88r
⇒ r = 7/2 = 3.5 cm
Volume = πr2h
⇒ Volume = (22/7) × (3.5)2 × 14
⇒ Volume = 539 cm3
∴ Volume of the cylinder is 539 cm3
Water in a canal 6 m wide and 1.5 m deep is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 12 Detailed Solution
Download Solution PDFGiven:
Width of canal 6 m
Depth of canal = 1.5 m
Speed of water in the canal = 10 km/hr
Time of irrigation is 30 min = 1/2 hr
8 cm of standing water is needed
Concept Used:
The volume of a Cuboid = (Length × Breadth × Height) cubic units.
Water flow through canal = water required to irrigate
Calculation:
According to the question
Length of water flow in 1/2 hr = l = 10 × (1/2) km
⇒ 5 km = 5000 m
⇒ Volume of water flown in 30 min = 6 × 1.5 × 5000
⇒ 45000 m3.
Now, According to the concept used
The volume of irrigated land = Area × Height
⇒ 45000 = Area × (8/100)
∴ The area of land of irrigation = 562500 m2.
A sphere has a radius of 8 cm. A solid cylinder has a base radius of 4 cm and a height of h cm. If the total surface area of the cylinder is half the surface area of the sphere, then find the height of the cylinder.
Answer (Detailed Solution Below)
Right Circular Cylinder Question 13 Detailed Solution
Download Solution PDFGiven:
Radius of sphere = 8 cm
Radius of cylinder = 4 cm
The total surface area of the cylinder is half the surface area of the sphere
Formula used:
Total surface area of cylinder = 2πr(h + r)
Surface area of sphere = 4πr2
Calculation:
According to the question
The total surface area of the cylinder is half the surface area of the sphere
⇒ 2πr(h + r)/4πr2 = 1/2
⇒ 2 × π × 4(h + 4)/(4 × π × 82) = 1/2
⇒ 8(h + 4)/256 = 1/2
⇒ h + 4/32 = 1/2
⇒ h + 4 = 16
⇒ h = (16 – 4)
⇒ h = 12 cm
∴ The height of the cylinder is 12 cm
A hollow cylindrical iron pipe has internal and external radii of 14 m and 21 m, respectively, and its height of 14 m. If this pipe is to be painted all over, find the area to be painted.
(Use π = \(\frac{22}{7}\))
Answer (Detailed Solution Below)
Right Circular Cylinder Question 14 Detailed Solution
Download Solution PDFGiven:
The internal radius (r) of a hollow cylindrical pipe = 14 m
External radius (R) = 21 m
Height (h) = 14 m
Formula Used:
Total Surface area of the hollow cylinder = 2πRh + 2πrh + 2π(R2 - r2)
Calculation:
Total Surface Area = 2πRh + 2πrh + 2π(R2 - r2)
⇒ 2π × [h(R + r) + (R2 - r2)]
⇒ (44/7)[2 × 14(21 + 14) + (441 - 196)]
⇒ (44/7)[(14 × 35) + 245]
⇒ (44/7)[490 + 245]
⇒ 44 × 735/7
⇒ 44× 105
⇒ 4620
Hence, the correct answer is 4620 m2.
The radius of the base of a right circular cylinder is 5 cm and its volume is 3125 π cm3. A metallic wire of radius 2.5 mm is wrapped around a cylinder so as to cover the curved surface of the cylinder. What will be the length (in m) of the wire?
Answer (Detailed Solution Below)
Right Circular Cylinder Question 15 Detailed Solution
Download Solution PDFGiven :
Radius = 5 cm
Volume = 3125π
Wire of radius = 2.5 mm
Formula Used :
Volume of Cylinder = πr2h
Curved Surface Area of Cylinder = 2πrh
Calculation :
We know,
⇒ 1 cm = 10 mm
⇒ 1 m = 100 cm
Voulme of Cylinder = 3125π = πr2h
⇒ 3125 = 25 × h
⇒ h = 125
Now, Radius of Wire = 2.5 mm = 0.25 cm
Diameter of Wire = 5 mm = 0.5 cm
So, number of rows of wire to cover the whole cylinder = Height/Diameter of Wire
So, number of rows of wire to cover the whole cylinder = 125/0.50 = 250
Length covered in one round of wire = 2π × 5 cm
Total Length of the Wire = 250 x (2π × 5) = 2500 π cm = 25 π m
∴ The correct answer is 25π m.