Right Circular Cylinder MCQ Quiz - Objective Question with Answer for Right Circular Cylinder - Download Free PDF

Last updated on Jun 22, 2025

Testbook provides Right Circular Cylinder MCQ Quizwith logical and easy explanations to all the questions. Detailed solutions for all the Right Circular Cylinder Objective questions have been provided so that the candidates can get the strategies and shortcuts to approach a question and solve it in less time. The Right Circular Cylinder Question Answers will help the candidates understand the concept better and grasp faster making it easier for them to solve the problems.

Latest Right Circular Cylinder MCQ Objective Questions

Right Circular Cylinder Question 1:

The length and breadth of a rectangle are in the ratio 9 : 5, respectively, and the perimeter of the rectangle is 280 cm. If the area of the rectangle is equal to the area of the top surface of a solid cylinder, then find the curved surface area of the cylinder given that its radius is 120% of its height.

  1. 8600 cm²
  2. 6900 cm²
  3. 7500 cm²
  4. 8200 cm²
  5. 9000 cm²

Answer (Detailed Solution Below)

Option 3 : 7500 cm²

Right Circular Cylinder Question 1 Detailed Solution

Find Length and Breadth of the Rectangle

Let length= 9x, breadth= 5x.

Perimeter = 2(9x + 5x) = 280

2(14x) = 280 ⟹ 28x = 280 ⟹ x = 10

Thus,

Length = 9x = 90 cm, Breadth = 5x = 50 cm

Area of rectangle = 90 × 50 = 4500 cm2.

The top surface of the cylinder is a circle with area πr2

Given:

πr2 = 4500 r2 = 4500π

Given: Radius r = 120% of height h, so:

r = 1.2h h = r / 1.2 = 5r / 6

Now, let's find the Curved Surface Area of Cylinder:

Curved surface area = 2πr

Substituteh = 5r / 6:

CSA = 2πr(5r/6) = 10πr/ 6 = 5πr/ 3

Since πr2 = 4500:

CSA = 5 x 4500 / 3 = 7500 cm2

Thus, the correct answer is 7500 cm2.

Right Circular Cylinder Question 2:

A rectangular sheet of 31.4 cm x 10 cm size is rolled across its length to make a cylinder without overlap. What will be the approximate volume of the cylinder?

  1. 785 cm³
  2. 1570 cm³
  3. 3140 cm³
  4. 6280 cm³

Answer (Detailed Solution Below)

Option 1 : 785 cm³

Right Circular Cylinder Question 2 Detailed Solution

Given:

Length of rectangular sheet = 31.4 cm

Breadth of rectangular sheet = 10 cm

Formula used:

Circumference of the base of the cylinder = Length of the sheet

Height of the cylinder = Breadth of the sheet

Volume of the cylinder = π × r2 × h

Where, r = radius of the base, h = height

Calculation:

Length of the sheet = Circumference of the base = 2πr

⇒ 31.4 = 2 × 3.14 × r

⇒ r = 31.4 / (2 × 3.14)

⇒ r = 5 cm

Height of the cylinder = Breadth of the sheet = 10 cm

Volume of the cylinder = π × r2 × h

⇒ Volume = 3.14 × (5)2 × 10

⇒ Volume = 3.14 × 25 × 10

⇒ Volume = 785 cm3

∴ The correct answer is option (1).

Right Circular Cylinder Question 3:

Radius of two cylinder is [r – 3] and [ r + 4] m respectively. Ratio of radius two cylinder is 1: 2. Height of cylinder is 7 and 14 m more than radius of cylinder respectively. Find the difference between the volume of two cylinder?

  1. 13025
  2. 15092
  3. 11592
  4. 14725
  5. 13265

Answer (Detailed Solution Below)

Option 2 : 15092

Right Circular Cylinder Question 3 Detailed Solution

Calculation

So, [r – 3] / [r + 4] = 1 /2

Or, 2r – 6 = r + 4

r = 10

So, Radius of cylinder is 10 – 3 = 7 and 10 + 4 = = 14 respectively.

Height of cylinder is 14 and 28 respectively.

So, volume is cylinder = [22/7] × 14 × 7 × 7 = 2156

Volume of cylinder = [ 22/7] × 14 × 14 × 28 = 17248

So, difference is 17248 – 2156 = 15092

Right Circular Cylinder Question 4:

A rectangular sheet 31.4 cm × 10 cm is rolled across its length to make a cylinder and both ends of the cylinder are covered with additional circular sheets. What will be the total surface area of the covered cylinder approximately?

  1. 314 cm2
  2. 392.5 cm2
  3. 471 cm2
  4. 785 cm2

Answer (Detailed Solution Below)

Option 3 : 471 cm2

Right Circular Cylinder Question 4 Detailed Solution

Given:

Length of the rectangular sheet = 31.4 cm

Breadth of the rectangular sheet = 10 cm

The sheet is rolled across its length to form a cylinder with covered ends.

Formula used:

Total Surface Area of a closed cylinder = 2πr² + 2πrh

Where:

r = radius of the base

h = height of the cylinder

Calculations:

Circumference of the cylinder's base = Length of the rectangular sheet

⇒ 2πr = 31.4

⇒ r = 31.4 / (2 × 3.14)

⇒ r = 5 cm

Height of the cylinder = Breadth of the rectangular sheet

⇒ h = 10 cm

Total Surface Area = 2πr² + 2πrh

⇒ Total Surface Area = 2 × 3.14 × 5² + 2 × 3.14 × 5 × 10

⇒ Total Surface Area = 157 + 314 = 471 cm²

∴ The correct answer is option (3).

Right Circular Cylinder Question 5:

Water flows out through a pipe, whose internal radius is 3 cm, at the rate of x cm per second into a cylindrical tank, the radius of whose base is 60 cm. If the level of water in the tank rises by 15 cm in 5 minutes, then the value of x is :

  1. 15
  2. 16
  3. 20
  4. 24

Answer (Detailed Solution Below)

Option 3 : 20

Right Circular Cylinder Question 5 Detailed Solution

Given:

Internal radius of the pipe (rpipe) = 3 cm

Rate of water flow from the pipe (speed of water) = x cm/second

Radius of the base of the cylindrical tank (Rtank) = 60 cm

Rise in water level in the tank (htank) = 15 cm

Time taken (T) = 5 minutes

Formula used:

Volume of water flowing out of the pipe in a given time = Area of cross-section of pipe × Speed of water × Time

Volume of water in cylindrical tank = πR2h

Calculation:

T = 5 minutes × 60 seconds/minute = 300 seconds

Volume of water flowed from pipe = Volume of water in the tank

Volume of water flowed from pipe = (π × rpipe2) × (rate of flow) × Time

= π × (3 cm)2 × (x cm/second) × (300 seconds)

= π × 9 × x × 300 cm3 = 2700πx cm3

Volume of water in the tank = π × Rtank2 × htank

= π × (60 cm)2 × (15 cm)

= π × 3600 × 15 cm3

= 54000π cm3

Equating the two volumes:

2700πx = 54000π

2700x = 54000

x = 54000 / 2700

x = 540 / 27

x = 20

∴ The correct answer is option 3.

Top Right Circular Cylinder MCQ Objective Questions

A closed cylindrical tank with a height of 1 m and a base diameter of 140 cm must be constructed from a metal sheet. For the same, how many m2 of the sheet are required? [Use π = 22/7]

  1. 10.56 m2
  2. 7.48 m2
  3. 9.23 m2
  4. 7 m2

Answer (Detailed Solution Below)

Option 2 : 7.48 m2

Right Circular Cylinder Question 6 Detailed Solution

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Given:

Height of the cylinder = 1 m 

Diameter = 140 cm = 1.4 m, so radius = 1.4/2 = 0.7 m

Concept used:

Total surface area of the cylinder = 2πrh + 2πr2

Calculation:

Total sheet required = 2πrh + 2πr2 = 2πr(h + r)

⇒ 2 × 22/7 × 0.7 × (1 + 0.7)

⇒ 4.4 × 1.7

⇒ 7.48 m2 

∴ The correct answer is 7.48 m2. 

The ratio of the volume of first and second cylinder is 32 ∶ 9 and the ratio of their heights is 8  9. If the area of the base of the second cylinder is 616 cm2, then what will be the radius of the first cylinder? 

  1. 24 cm
  2. 20 cm
  3. 28 cm
  4. 36 cm

Answer (Detailed Solution Below)

Option 3 : 28 cm

Right Circular Cylinder Question 7 Detailed Solution

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Given:

Volume ratio = 32 ∶ 9

Ratio of their heights is 8 ∶ 9

Area of the base of the second cylinder is 616 cm2

Concept Used:

Volume of cylinder = πr2h

Calculation:

Volume of the cylinder can be written as 32y and 9y

Height of the cylinder can be written as 8h and 9h

Since we know that the Volume of cylinder is Area of base × height

⇒ Volume of second cylinder = 616 × 9h

Let the radius of first cylinder be r

⇒ base area of first cylinder = πr2

Volume of first cylinder = πr2 × 8h

Their ratios can be written as

⇒ 616 × 9h/ (πr2 × 8h) = 9/32

Put π = 22/7

⇒  (22r2 × 8)/(616 × 9 × 7)/ = 32/9

⇒ r2 = (616 × 9 × 32 × 7)/(9 × 22 ×  8)

⇒ r = 28

∴ Radius of first cylinder is 28 cm.

Option 3 is the correct answer.

The ratio between the height and radius of the base of a cylinder is 7 ∶ 5. If its volume is 14836.5 cm3, then find its total surface area (take π = 3.14).

  1. 3391.2 cm2
  2. 5391.2 cm2
  3. 5491.2 cm2
  4. 5393.2 cm2

Answer (Detailed Solution Below)

Option 1 : 3391.2 cm2

Right Circular Cylinder Question 8 Detailed Solution

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Given:

The ratio between the height and radius of the base of a cylinder is 7 ∶ 5.

Volume is 14836.5 cm3 

Formula used:

Volume of cylinder = πr2h

TSA of cylinder = 2πr(r + h)

Calculation:

Let the height be 7x and radius be 5x

According to the question,

Volume = π (5x)2 × 7x

⇒ 14836.5 = (3.14)(25x2) × 7x

⇒ 14836.5 = (3.14)(25x2) × 7x

⇒ 175x3 = 14836.5/3.14

⇒ x3 = 4725/175

⇒ x3 = 27

⇒ x = 3

Now,

Radius = 5x =  5 × 3 = 15 cm

Height = 7x = 7 × 3 = 21 cm

For TSA of cylinder,

TSA = 2(3.14) × 15 × (15 + 21)

⇒ TSA = 6.28 × 15 × 36

⇒ TSA = 3391.2 cm2 

∴ The TSA of the cylinder is 3391.2 cm2.

The diameter of the base of a cylinder is 35 cm and its curved surface area is 3080 cm2. Find the volume of cylinder(in cm3). 

  1. 56,890 cm3
  2. 19,568 cm3
  3. 26,950 cm3
  4. 26,000 cm3

Answer (Detailed Solution Below)

Option 3 : 26,950 cm3

Right Circular Cylinder Question 9 Detailed Solution

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Given:

Diameter of cylinder = 35 cm

Curved surface area = 3080 cm2

Formula used:

Radius = Diameter/2

Curved surface are of cylinder = 2πrh

Volume of cylinder = πr2h

where r = radius , h = height

Calculation: 

Diameter (d) = 35 cm

⇒ Radius = d/2

⇒ 35/2

 ⇒Radius = 17.5

Curved surface area of cylinder = 2πrh = 3080

⇒ 2 × 22/7 × 17.5 × h = 3080

⇒ h = 28 cm

Now Volume of cylinder = πr2h

⇒ 22/7 × (17.5)2 × 28

⇒ 22 × 306.25 × 4

⇒ 26,950 cm3 

∴ Volume of cylinder is 26,950 cm3.

The sum of the radius of the base and the height of a solid right circular cylinder is 39 cm. Its total surface area is 1716 cm2. What is the volume (in cm3) of the cylinder? (Take π = )

  1. 4774
  2. 5082
  3. 4928
  4. 4620

Answer (Detailed Solution Below)

Option 3 : 4928

Right Circular Cylinder Question 10 Detailed Solution

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Given:

Sum of radius and height of the cylinder = 39 cm

Total surface area of the cylinder = 1716 cm2

Concept used:

Total surface area of a cylinder = 2πr(h + r)

Volume = πr2h

Here,

r = radius

h = height

Calculation:

Let the radius and the height of the cylinder be r and h,

According to the question,

2πr(h + r) = 1716      ----(i)

(h + r) = 39      ----(ii)

Putting the value of eq (ii) in eq (i) we get,

2πr × 39 = 1716

⇒ 2πr = 1716/39

⇒ 2πr = 44

⇒ πr = 22

⇒ r = 22 × (7/22)

⇒ r = 7

So, radius = 7 cm

Now, by putting the value of r in the eq (ii) we get

h + 7 = 39

⇒ h = 32

So, height = 32 cm

Now, volume = (22/7) × 72 × 32

⇒ 22 × 7 × 32

⇒ 4928

So, volume of the cylinder = 4928 cm3

∴ The volume (in cm3) of the cylinder i 4928.

Curved surface area of a cylinder is 308 cm2, and height is 14 cm. What will be the volume of the cylinder?

  1. 439 cm3
  2. 385 cm3
  3. 539 cm3
  4. 529 cm3

Answer (Detailed Solution Below)

Option 3 : 539 cm3

Right Circular Cylinder Question 11 Detailed Solution

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Given:

Curved surface area of cylinder = 308 cm2

Height = 14 cm

Formula used:

CSA (Curved surface area) = 2πrh

Volume = πr2h

Where r is radius and h is height

Calculation:

CSA = 2πrh

308 = 2 × (22/7) × r × 14

⇒ 308 = 88r

⇒ r = 7/2 = 3.5 cm

Volume = πr2h

⇒ Volume = (22/7) × (3.5)2 × 14

⇒ Volume = 539 cm3 

∴ Volume of the cylinder is 539 cm3

Water in a canal 6 m wide and 1.5 m deep is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

  1. 560000 m2
  2. 600000 m2
  3. 700000 m2
  4. 562500 m2

Answer (Detailed Solution Below)

Option 4 : 562500 m2

Right Circular Cylinder Question 12 Detailed Solution

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Given:

Width of canal  6 m 

Depth of canal = 1.5 m 

Speed of water in the canal = 10 km/hr

Time of irrigation is 30 min = 1/2 hr

8 cm of standing water is needed 

Concept Used:

The volume of a Cuboid = (Length × Breadth × Height) cubic units.

Water flow through canal = water required to irrigate

Calculation:

According to the question 

Length of water flow in 1/2 hr = l = 10 × (1/2) km

5 km = 5000 m

⇒ Volume of water flown in 30 min = 6 × 1.5 × 5000

45000 m3.

Now, According to the concept used

The volume of irrigated land = Area × Height

⇒ 45000 = Area × (8/100)

∴ The area of land of irrigation = 562500 m2.

A sphere has a radius of 8 cm. A solid cylinder has a base radius of 4 cm and a height of h cm. If the total surface area of the cylinder is half the surface area of the sphere, then find the height of the cylinder.

  1. 15 cm
  2. 12 cm
  3. 10 cm
  4. 9 cm

Answer (Detailed Solution Below)

Option 2 : 12 cm

Right Circular Cylinder Question 13 Detailed Solution

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Given:

Radius of sphere = 8 cm

Radius of cylinder = 4 cm

The total surface area of the cylinder is half the surface area of the sphere

Formula used:

Total surface area of cylinder = 2πr(h + r)

Surface area of sphere = 4πr2

Calculation:

According to the question

The total surface area of the cylinder is half the surface area of the sphere

⇒ 2πr(h + r)/4πr2 = 1/2

⇒ 2 × π × 4(h + 4)/(4 × π × 82) = 1/2

⇒ 8(h + 4)/256 = 1/2

⇒ h + 4/32 = 1/2

⇒ h + 4 = 16

⇒ h = (16 – 4)

⇒ h = 12 cm

∴ The height of the cylinder is 12 cm

The curved surface area of a cylinder is 484 sq. cm. If height of the cylinder is 7 cm, then what is the volume of the cylinder (in cubic cm)? (Use π = 22/7)

  1. 2200
  2. 2750
  3. 2662
  4. 2650

Answer (Detailed Solution Below)

Option 3 : 2662

Right Circular Cylinder Question 14 Detailed Solution

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Given:

Curved surface area(CSA) of the cylinder = 484 cm2

Height(h) of the cylinder = 7 cm

Formula used:

CSA of cylinder = 2πrh

Volume(V) of cylinder = πr2h

r = radius of the base of the cylinder

Calculation:

2πrh = 484

⇒ 2 ×  × r × 7 = 484

⇒ r = 11

V = πr2h

⇒ V =  × 112 × 7

⇒ V = 2662 

∴ Volume of the cylinder = 2662 cm3

A hollow cylindrical iron pipe has internal and external radii of 14 m and 21 m, respectively, and its height of 14 m. If this pipe is to be painted all over, find the area to be painted.

(Use π = )

  1. 4000 m2
  2. 3562 m2
  3. 4620 m2
  4. 5624 m2

Answer (Detailed Solution Below)

Option 3 : 4620 m2

Right Circular Cylinder Question 15 Detailed Solution

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Given:

The internal radius (r) of a hollow cylindrical pipe = 14 m

External radius (R) = 21 m

Height (h) = 14 m

Formula Used:

Total Surface area of the hollow cylinder = 2πRh + 2πrh + 2π(R2 - r2)

Calculation:

Total Surface Area = 2πRh + 2πrh + 2π(R2 - r2)

⇒ 2π ×  [h(R + r) + (R2 - r2)]

 (44/7)[2 × 14(21 + 14) + (441 - 196)]

⇒ (44/7)[(14 × 35) + 245]

⇒ (44/7)[490 + 245]

⇒ 44 × 735/7

⇒ 44× 105

4620

Hence, the correct answer is 4620 m2.

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