Track Design MCQ Quiz - Objective Question with Answer for Track Design - Download Free PDF

Last updated on May 15, 2025

Latest Track Design MCQ Objective Questions

Track Design Question 1:

Which among the following is an incorrect statement?

  1. The wheel diameter of the train is about 0.75 times the gauge width.
  2. Narrow gauge is suitable for curves of smaller radius.
  3. cost of railway track is inversely proportional to the gauge width.
  4. Broad gauge is suitable for higher intensity of traffic.
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : cost of railway track is inversely proportional to the gauge width.

Track Design Question 1 Detailed Solution

The choice of different gauges of railway track depends upon following important factors and prevailing conditions in the region.

Traffic condition: If the intensity of traffic on the track is likely to be more, a gauge wider than the standard gauge is suitable.

Development of areas: To connect a remote location of a smaller population to the world, a narrow gauge may be suitable.

Cost of the track: It is directly proportional to the width of the gauge of railway track. As gauge width increases, the cost of ballast, sleepers, rails, etc increase proportionally.

Speed of Movement: The speed of the train is a function of the diameter of the wheel of a train, the diameter of a wheel is usually about 0.75 times the gauge width. Therefore, as the gauge width increases, wheel diameter increases and thus the speed of the train increases.

Nature of Country: In mountainous country, it is advisable to have a narrow gauge of the track since it is flexible and can be laid to a smaller radius of the curves.

Track Design Question 2:

Which of the following is one of the standard gauges used in Indian Railways for Broad Gauge (BG) tracks?

  1. 1220 mm
  2. 1435 mm
  3. 1000 mm
  4. 1676 mm

Answer (Detailed Solution Below)

Option 4 : 1676 mm

Track Design Question 2 Detailed Solution

Explanation:

Standard Gauge for BG: In India, the Broad Gauge (BG) is defined as having a track gauge of 1676 mm (5 feet 6 inches). This is the most commonly used gauge in the country and accounts for the majority of the railway network.

  • Significance of 1676 mm Gauge:

    • The 1676 mm Broad Gauge is used for long-distance passenger trains, freight trains, and high-speed services across India.

    • It provides better stability and allows for the operation of faster trains compared to narrower gauges (like meter gauge or narrow gauge).

    • The BG tracks can handle larger and heavier trains, which is essential for transporting both passengers and freight over long distances efficiently.

    • Over 80% of the total track length in India is Broad Gauge.

Additional Information Other Gauges in India:

  • Standard Gauge (1435 mm): This is mostly used in some specialized or high-speed rail corridors, like the Mumbai-Ahmedabad bullet train project.

  • Meter Gauge (1000 mm) and Narrow Gauge (762 mm or less): These are used for shorter, regional, or mountainous routes, though their use is gradually being replaced by Broad Gauge for better efficiency.

Track Design Question 3:

Calculate the hauling capacity of a 1-4-1 locomotive when the coefficient of rail-wheel friction and weight on each driving axle are 0.30 and 23 tonnes respectively. 

  1. 12.8 tonnes
  2. 11.8 tonnes
  3. 14.8 tonnes
  4. 13.8 tonnes

Answer (Detailed Solution Below)

Option 4 : 13.8 tonnes

Track Design Question 3 Detailed Solution

Concepts:

The hauling capacity of a railway locomotive is given as:

H = μ × W × N

H = Hauling power

N = number of pairs of driving wheels

W = weight exerted on the driving wheels

μ = coefficient of friction 

Calculation:

Given: μ = 0.3, W = 23 tonnes

For Locomotive 1-4-1:

Nos of driving wheels = 4

Nos. of pair of driving wheels are, N = 4/2 = 2

Now, the hauling capacity is given as:

H = 0.3 × 23 × 2 = 13.8 tonnes.

Track Design Question 4:

The development length in compression for a 20 mm diameter deformed bar of grade Fe 415 embedded in concrete of grade M 25, whose design bond stress is 1.4 N/mm2, is:

  1. 645 mm
  2. 806 mm
  3. 1289 mm
  4. 1489 mm
  5. 1500 mm

Answer (Detailed Solution Below)

Option 1 : 645 mm

Track Design Question 4 Detailed Solution

Concept:

Development length:

(i) The calculated tension or compression in any bar at any section shall be developed on each side of the section by an appropriate development length or end anchorage or a combination thereof.

(ii) Development length can be calculated as:
\({L_d} = \frac{{ϕ × 0.87{f_y}}}{{4{τ _{bd}}}}\)

Where, ϕ = Diameter of bar

τbd = Design bond stress = Permissible value of average bond stress

The value of bond stress is increased by 60% for a deformed bar in tension and a further increase of 25% is made for bars in compression.

Calculation:

Given,

ϕ = 20 mm, τbd = 1.4 N/mm2 (In tension), fy = 415 MPa

∵ Bar in compression, so Increased the value of τbd by 25% and for deformed bar it is increased by 60 %

So, τbd = 1.4 × 1.25 × 1.6 = 2.8 N/mm2

Development length, \({L_d} = \frac{{ϕ × 0.87{f_y}}}{{4{τ _{bd}}}}\) 

\({L_d} = \frac{{20 × 0.87 × 415}}{{4 × 2.8}}\) = 645 mm

Track Design Question 5:

A broad-gauge railway track is laid with wooden sleepers, at a sleeper spacing of 68.4 cm. If the width of the sleeper is 25.4 cm, then the depth of the ballast cushion would be: 

  1. 18.5 cm 
  2. 34.2 cm 
  3. 21.5 cm 
  4. 25.4 cm 

Answer (Detailed Solution Below)

Option 3 : 21.5 cm 

Track Design Question 5 Detailed Solution

Concept:

Relationship between sleeper spacing, width of sleeper, and depth of ballast cushion is given by the following formula:

Sleeper Spacing = Width of Sleeper + (2 × Depth of Ballast Cushion)

Calculation:

Given Data:

Let D = depth of ballast cushion

Sleeper Spacing = 68.4 cm

Width of sleeper = 25.4 cm

Putting these data in above equation, we get,

68.4= 25.4 + (2 × D)

So,

Depth of Ballast Cushion, \(D = \frac{{68.4 - 25.4}}{2} = 21.5\;cm\)

Top Track Design MCQ Objective Questions

Which one of the following statement is correct regarding ballast used for railway tracks?

  1. The minimum depth of ballast for B.G. section is 20 cm – 25 cm
  2. The quantity of stone ballast required for one metre length of track is 0.53 m3 for B.G. section
  3. For M.G. section the width of ballast is 1.83 m
  4. The minimum depth of ballast for N.G. section is 10 cm

Answer (Detailed Solution Below)

Option 1 : The minimum depth of ballast for B.G. section is 20 cm – 25 cm

Track Design Question 6 Detailed Solution

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Explanation:

Ballast

It is the granular material that is placed and packed below and surrounding the sleeper.

Functions:

1. It transmits the load from sleepers to subgrade

2. Provide good drainage.

The characteristics of ballast are:

1. The depth of ballast for different type tracks is:

For BG: 20-25 cm

For MG: 15-20 cm

For NG: 15 cm

2. The quantity of stone ballast required for one-meter length of track for different type of tracks is as follow:

For BG – 1.036 m3.

For MG – 0.71 m3.

For NG – 0.53 m3.

3. The size of ballast depends on the type of sleeper and location of track and its is given as:

For Wooden sleeper - 5 cm

For Metal sleeper - 4 cm

For turnouts and cross-over - 2.5 cm

A BG track is laid with a sleeper density of N+3. The width of the sleeper is 20.25 cm. Find the minimum depth of the ballast cushion. 

  1. 61 cm
  2. 30.5 cm
  3. 20.375 cm
  4. 10.125 cm

Answer (Detailed Solution Below)

Option 2 : 30.5 cm

Track Design Question 7 Detailed Solution

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CONCEPT

Length of 1 rail(N) is taken as 13m

Number of sleepers = N + 3

Spacing of sleepers(S) = (length of 1 rail * 100) / number of sleepers (cm) 

Optimum depth of blast cushion = (S - W ) / 2

Given

Sleeper density = N+ 3 

width of the sleeper is 20.25 cm

CALCULATION

Number of sleepers = 13 + 3 = 16

Spacing of sleepers(S) = 13 X 100 / 16 = 81.25cm

Width of sleepers(W) = 20.25 cm

Minimum depth of blast cushion = (S - W ) / 2 

= (81.25 - 20.25) / 2 

= 30.5 cm (ans)

A 3-degrees curve is situated on a ruling gradient of 1 in 250 on a broad Gauge track. What should be the actual ruling gradient considering the grade compensation of curvature?

  1. 0.12%
  2. 0.28%
  3. 1 in 300
  4. 1 in 280

Answer (Detailed Solution Below)

Option 2 : 0.28%

Track Design Question 8 Detailed Solution

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Concept

Grade compensation (GC) for BG = 0.04% per degree of curve

Calculation

Given,

Degree of curve D = 3° 

Ruling Gradient = 1 in 250 

So for 3° curve, compensation,

= 0.04 × 3 = 0.12%

∴ Ruling gradient \(= \frac{1}{{250}} \times 100 = 0.4{\rm{\% }}\)

∴ The actual ruling gradient considering the grade compensation of curvature = 0.4 - 0.12 = 0.28%

Tapered moveable rail, connected at its thickest end to running rail is termed as

  1. stock rail
  2. tongue rail
  3. lead
  4. sleeper

Answer (Detailed Solution Below)

Option 2 : tongue rail

Track Design Question 9 Detailed Solution

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Concept:

Railway images Q3

 

Railway images Q3a

The points and crossing are the vital components of track asset; necessary for diversion of traffic from one track to another track, such diversion may be necessitated for giving precedence to faster trains in the same direction, giving passage to a train moving in the opposite direction or for connecting places not on the direct line of the track.

Constituents of the points and crossing are explained below:

1. Turnout - The term denotes points and crossing with the lead rails.

2. Tongue rail - It is a tapered moveable rail, connected at its thickest end to the running rail.

3. Stock rail - It is the running rail, against which a tongue rail functions.

4. Switch - A pair of tongues with stock rail with necessary connections and fittings.

5. Points - A pair of tongue rail with their stock rails are termed as points.

6. Crossing - A crossing is a device introduced at the junction where two rails cross to permit the wheel flange of railway vehicle to pass from one track to another track.

7. Heel of the switch - It is an imaginary point on the gauge line midway between the end of the lead rail and the tongue rail in case of loose heel switches In case of fixed heel switches, it is a point on the gauge line of tongue rail opposite the centre of heel block.

8. Lead - The track portion between heels of the switch to the beginning of crossing assembly is called the lead.

9. Turn – in – curve - The track portion between the heel of crossing to the fouling marks is called the turn – in – curve.

For crossings and points, the maximum size of ballast is:

  1. 50 mm
  2. 20 mm
  3. 25 mm
  4. 35 mm

Answer (Detailed Solution Below)

Option 3 : 25 mm

Track Design Question 10 Detailed Solution

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For points & crossing, the maximum of nominal size of the ballast is 25 mm.

Other Points:

1. Points & crossing provide flexibility of movement by connecting one lien to another according to requirements.

2. They also help for imposing restrictions on turnouts which further retards the speed of the train.

3. The main function of ballast is to hold the sleepers and convert line load to uniformly distributed load.

4. Size of ballast for wooden sleepers is 50 mm and for metal sleepers is 40 mm.

Maximum value of 'throw of switch' for Broad gauge track is:

  1. 89 mm
  2. 95 mm
  3. 100 mm
  4. 115 mm

Answer (Detailed Solution Below)

Option 4 : 115 mm

Track Design Question 11 Detailed Solution

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Explanation

Throw of switch: 

(i) It is the distance between the running face of the stock rail and the toe of the tongue rail.

(ii) Its limiting values are 95-115 mm for BG routes and 89-100 mm for MG routes.

Additional Information

Some other important terms are as follows:

Switch angle: It is the angle between the gauge faces of the stock rail and the tongue angle.

Heel clearance: It is the distance between the running edge of the stock rail and the switch rail at the switch heel.

Its recommended value on BG is 133 mm, 121 mm to 117 mm for MG and 98 mm for NG track respectively.

Check rails: These are the rails provided to guide the wheel flanges, while the opposite wheel is jumping the gap.

Flange way clearance: It is the distance between the adjacent faces of the stock rail and the check rail. Its minimum value is 60 mm.

An electric locomotive running at 60 kmph on a curved track of 1.68 m gauge laid at 800 m radius should be provided with superelevation of the rail by an amount of

  1. 50.5 mm
  2. 55.5 mm
  3. 59.5 mm
  4. 65.5 mm

Answer (Detailed Solution Below)

Option 3 : 59.5 mm

Track Design Question 12 Detailed Solution

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Concept:

Superelevation:

To counteract the effect of centrifugal force, the level of the outer rail is raised above the inner rail by a certain amount to introduce the centripetal force.

This raised elevation of the outer rail above the inner rail at a horizontal curve is called superelevation.

For any gauge super elevation ‘e’ (in m) is given as

\(e = \frac{{{\rm{GV}}^2}}{{127{\rm{R}}}}\)

Where, G = Gauge distance

V = velocity in Kmph

R = Radius of curve

Calculation:

Given,

G = Gauge distance = 1.68 m

V = velocity in Kmph = 60

R = Radius of curve = 800 m

\(e = \frac{{{\rm{GV}}^2}}{{127{\rm{R}}}}\)

\(e = \frac{{1.68 \times {{60}^2}}}{{127 \times 800}}\) = 59.52 mm

If the track is laid on the place in a curve of 5 degree, the allowable ruling gradient on the curve is(Ruling Gradient = 1 in 20)

  1. 1 in 334
  2. 1 in 318
  3. 1 in 297
  4. 1 in 253

Answer (Detailed Solution Below)

Option 1 : 1 in 334

Track Design Question 13 Detailed Solution

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Concept:

Grade compensation:

The ruling gradient is the maximum gradient on a particular section, but if a curve lies on a ruling gradient, the resistance due to gradient is increased by that due to curvature, and this further increases the resistance beyond the ruling gradient. In order to avoid resistances beyond the allowable limits, the gradients are reduced on curves, and this reduction is known as the grade compensation for the curve.

Allowable ruling gradient = Ruling gradient - Grade compensation 

Grade compensation (GC) for BG = 0.04% per degree of curve
Grade compensation (GC) for MG = 0.03% per degree of curve
Grade compensation (GC) for NG = 0.02% per degree of curve

Calculation

Given,

Degree of curve D = 5° 

Ruling Gradient = 1 in 200 

So for 5° curve, compensation,

= 0.04 × 5 = 0.2%

∴ Ruling gradient = (1/200) × 100 = 0.5%

∴ Allowable gradient = (0.5 - 0.2)% = 0.3/100 = 1/333.33

∴ Allowable Gradient = 1 in 334

At points and crossings, the total number of sleepers for 1 in 12 turnouts in broad gauge is

  1. 51
  2. 62
  3. 70
  4. 78

Answer (Detailed Solution Below)

Option 3 : 70

Track Design Question 14 Detailed Solution

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Explanation:

(i) Total number of the sleeper at point and crossing depend upon the turnout and in indian railway generally, two types of turnout are provided i.e. 1 in 12 and 1 in 8.5

(ii) For 1 in 12 turnouts, the total number of sleeper = 70

(iii) For 1 in 8.5 turnouts, the total number of sleeper = 62

The ballast material generally used in Indian railways consists of

  1. Broken stone
  2. Gravel
  3. Moorum
  4. All of the above

Answer (Detailed Solution Below)

Option 4 : All of the above

Track Design Question 15 Detailed Solution

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Explanation:

The following materials for Ballast can be used on the railway track.

1. Broken Stone

2. Gravel

3. Cinders / Ashes

4. Sand

5. Kankars

6. Moorum

7. Brick Ballast

Among above materials, broken stone from Igneous rocks like quartzite and granite forms the excellent ballast materials. When these are not available then lime stone and sand stone can also be used as good ballast material.

F1 N.M Madhu 09.04.20 D3

Some of the main functions of ballast are followings:

a) To provide firm and level bedded foundation for the sleepers and rails to rest on

b) To protect the surface of subgrade and to form an elastic bed

c) To transmit and distribute the loads from the sleepers to the subgrade

d) To allow for maintaining correct track level without disturbing the rail road bed

e) To hold the sleepers in position during the passage of trains

f) To provide lateral stability to the track as a whole.

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