General Design Principles MCQ Quiz in मल्याळम - Objective Question with Answer for General Design Principles - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 9, 2025
Latest General Design Principles MCQ Objective Questions
Top General Design Principles MCQ Objective Questions
General Design Principles Question 1:
While designing for fire resistance of a structure made with structural steel, no reduction in the yield stress needs to be considered below T° C, where T is:
Answer (Detailed Solution Below)
General Design Principles Question 1 Detailed Solution
Explanation:
As per IS code 800 : 2007, clause 16.4.1
The influence of temperature on the yield stress of steel shall be taken as follows for the structure of mild steels and high strength low alloy steels
\({f_{y}(T)\over f_{y}(20)}={905-T\over 905}\leq1.0\)
fy(T) = Yield stress of steel at T°C,
fy(20) = Yield stress of steel at 20°C
T = Temperature of steel in °C.
For temperature less than 215°C no reduction in the yield stress needs to be considered.
General Design Principles Question 2:
According to IS 800 ∶ 2007, identify the property which is considered as a mechanical property of structural steel, important in design.
Answer (Detailed Solution Below)
General Design Principles Question 2 Detailed Solution
Concepts:
The principle mechanical properties of the structural steel important in design, as detailed by the code IS 800:2007 in cl. 2.2.4.2, are:
- Yield stress
- Tensile or ultimate stress
- The maximum percent elongation on a standard gauge length and
- Notch toughness
Note:
The various Physical properties of structural steel irrespective of its grade, as detailed by cl.2.2.4.1 of IS 800:2007 are:
- Unit weight of steel = 7850 kg/m3
- Modulus of elasticity, E = 2.0 x105 N/mm2
- Poisson ratio, μ = 0.3
- Modulus of rigidity, G = 0.769 x 105 N/mm2
- Coefficient of thermal expansion α = 12 x 10-6/0C.
General Design Principles Question 3:
For the web of channel section to be classified in plastic class, the ratio of depth to thickness of web should be ________.
Answer (Detailed Solution Below)
General Design Principles Question 3 Detailed Solution
Concept:
Prevention of Local Buckling:
The local buckling can be prevented by adopting a higher thickness value for the plate element IS800:2007 puts a limit on width to thickness ratio of component steel plates of the section as given in Table 1.1.
Compression element | Ratio | Class of section | ||
Class 1 Plastic |
Class 2 Compact |
Class 3 Semi-compact |
||
Web of a channel | d/tw | 42ϵ | 42ϵ | 42ϵ |
Angle, compression due to bending (both criteria should be satisfied) |
b/t or d/t |
9.4ϵ | 10.5ϵ | 15.7ϵ |
Where,
ϵ = \(\sqrt \frac{250}{f_y}\)
fy = Yield strength of Steel
General Design Principles Question 4:
The design criterion for laterally supported steel beams with respect to crippling recommends that the maximum permissible bearing stress should NOT exceed ______ times of the yield stress of steel (fy).
Answer (Detailed Solution Below)
General Design Principles Question 4 Detailed Solution
Permissible Maximum Stress |
Stress Value |
Permissible average shear stress |
0.40 fy |
Permissible maximum shear stress |
0.45 fy |
Permissible axial tensile stress |
0.60 fy |
Permissible compressive or tensile bending Stress |
0.66 fy |
Permissible bearing stress |
0.75 fy |
Permissible combined bending & bearing stress |
0.90 fy |
General Design Principles Question 5:
The minimum yield stress of a steel to be used in the steel structure is 420 MPa. The permissible stress in axial tension for this steel will be:
Answer (Detailed Solution Below)
General Design Principles Question 5 Detailed Solution
Concept:
Permissible stresses in steel,
Cases | Permissible stress |
Axial tension and compression | 0.6 fy |
In bending | 0.66 fy |
In bearing | 0.75 fy |
In shear |
Max. permissible avg = 0.4 fy Max. permissible = 0.45 fy |
Where, fy = Yield stress
Calculation:
Given,
Yield stress (fy) = 420 MPa
Permissible stress in axial tension is given by,
Permissible stress = 0.6 fy = 0.6 × 420 = 252 MPa
General Design Principles Question 6:
According to IS 800-2007, the minimum distance between centre of a fastener shall NOT be less than:
Answer (Detailed Solution Below)
General Design Principles Question 6 Detailed Solution
Specification for the pitch of bolts or rivets
1. Minimum pitch and minimum gauge length
\( = \left\{ {2.5 \times nominal\;diameter\;of\;the\;bolt} \right.\)
2. Minimum end and edge distance
\(= \left\{ {\begin{array}{*{20}{c}} {1.5 \times diameter\;of\;the\;bolt\;hole,\;for\;machine\;cut\;element}\\ {1.7 \times diameter\;of\;the\;bolt\;hole,\;for\;hand\;cut\;element} \end{array}} \right.\)
3. Maximum end and edge distance
\(= \left\{ {\;12 \times t \times \epsilon,\;\begin{array}{*{20}{c}} {\;where\;\epsilon = \sqrt {\frac{{250}}{{{f_y}}}} }\\ {{f_y} = yield\;stress}\\ {t = tickness\;of\;thinner\;plate\;} \end{array}} \right.\)
4. Maximum pitch of bolts or rivets or welds in the compression zone
\(= \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {12 \times t\;}\\ {or}\\ {200\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\;\)
5. Maximum pitch of bolts or rivets or welds in the tension zone
\(= \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {16 \times t\;}\\ {or}\\ {200\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)
6. If bolts are Staggered, the above values can be increased by 50%, i.e.
\(Maximum\;pitch\;in\;compression = \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {18 \times t\;}\\ {or}\\ {300\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)
\(Maximum\;pitch\;in\;tension\;zone = \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {24 \times t\;}\\ {or}\\ {300\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)
General Design Principles Question 7:
For a structural steel based construction in which, the connections between members (beam and column) at their junction will not resist any appreciable moment and shall be assumed to be hinged, is a type of:
Answer (Detailed Solution Below)
General Design Principles Question 7 Detailed Solution
Explanation:
As per IS 800 (2007): General Construction In Steel - Code of Practice:
Rigid construction
- In rigid construction, the connections between members (beam and column) at their junction shall be assumed to have sufficient rigidity to hold the original angles between the members connected at a joint unchanged under loading.
Semi-rigid construction
- In semi-rigid construction, the connections between members (beam and column) at their junction may not have sufficient rigidity to hold the original angles between the members at a joint unchanged, but shall be assumed to have the capacity to furnish a dependable and known degree of flexural restraint. The relationship between the degree of flexural restraint and the level of the load effects shall be established by any rational method or based on test results.
Simple construction
- In simple construction, the connections between members (beam and column) at their junction will not resist any appreciable moment and shall be assumed to be hinged.
General Design Principles Question 8:
Two plates of thickness 10 mm and 12 mm are connected together with a fillet weld. What is the minimum size of fillet weld?
Answer (Detailed Solution Below)
General Design Principles Question 8 Detailed Solution
As per IS: 800 - 2007, Clause 10.5.2.3, Table 21
The thickness of the thicker plate |
The minimum size of the welding |
Up to 10 mm |
3 mm |
10 – 20 mm |
5 mm |
20 – 32 mm |
6 mm |
32 mm - 50 mm |
8 mm of the first run |
General Design Principles Question 9:
Permissible stresses in bending for steel structures should not be greater than:
Answer (Detailed Solution Below)
General Design Principles Question 9 Detailed Solution
Explanation:
Type of force |
Permissible stress |
Axial tension and Compression |
0.6 fy |
Bending |
0.66 fy |
Bearing |
0.75 fy |
Average Shear |
0.4 fy |
General Design Principles Question 10:
In a design of structures, an additional lateral load considered, to account for the initial imperfections of the structure geometry is called:
Answer (Detailed Solution Below)
General Design Principles Question 10 Detailed Solution
Explanation:
Notional load:
- A notional load is a lateral load that is derived from an existing vertical load case.
- This load type has been introduced to accommodate a requirement in design codes.
- It accounts for the initial imperfections of the structure geometry. The AISC 360-05 specification for example defines notional loads as lateral loads that are applied at each framing level and are specified in terms of gravity loads.
Rotational load:
Rotational load defines loads resulting from the rotation of the model. You can specify either angular velocity or rotary acceleration. Abaqus defines the load by using the square of the angular velocity or by using the acceleration directly. In either case, the load definition must include an axis of rotation, which is defined as follows:
- If you are working in three-dimensional space, you define the location and direction of the axis by entering the global coordinates of two points.
- If you are working in two-dimensional space, you specify the location of the axis by entering the coordinates of a point in the plane. The direction of the axis is always out of the plane.
- If you are working in axisymmetric space, the axis is always in the location and direction of the positive global Z-axis.