General Design Principles MCQ Quiz in मल्याळम - Objective Question with Answer for General Design Principles - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 9, 2025

നേടുക General Design Principles ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക General Design Principles MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest General Design Principles MCQ Objective Questions

Top General Design Principles MCQ Objective Questions

General Design Principles Question 1:

While designing for fire resistance of a structure made with structural steel, no reduction in the yield stress needs to be considered below T° C, where T is:

  1. 313
  2. 235
  3. 215
  4. 205

Answer (Detailed Solution Below)

Option 3 : 215

General Design Principles Question 1 Detailed Solution

Explanation:

As per IS code 800 : 2007, clause 16.4.1

The influence of temperature on the yield stress of steel shall be taken as follows for the structure of mild steels and high strength low alloy steels

\({f_{y}(T)\over f_{y}(20)}={905-T\over 905}\leq1.0\)

fy(T) = Yield stress of steel at T°C,

fy(20) = Yield stress of steel at 20°C

T = Temperature of steel in °C.

For temperature less than 215°C no reduction in the yield stress needs to be considered.

General Design Principles Question 2:

According to IS 800 ∶ 2007, identify the property which is considered as a mechanical property of structural steel, important in design.

  1. Maximum percent elongation on a standard gauge length
  2. Co-efficient of thermal expansion
  3. Unit mass
  4. Poisson ratio 

Answer (Detailed Solution Below)

Option 1 : Maximum percent elongation on a standard gauge length

General Design Principles Question 2 Detailed Solution

Concepts:

The principle mechanical properties of the structural steel important in design, as detailed by the code IS 800:2007 in cl. 2.2.4.2, are:

  1. Yield stress
  2. Tensile or ultimate stress 
  3. The maximum percent elongation on a standard gauge length and
  4. Notch toughness

Note:

The various Physical properties of structural steel irrespective of its grade, as detailed by cl.2.2.4.1 of IS 800:2007 are:

  1. Unit weight of steel = 7850 kg/m3
  2. Modulus of elasticity, E = 2.0 x105 N/mm2 
  3. Poisson ratio, μ = 0.3
  4. Modulus of rigidity, G = 0.769 x 105 N/mm2
  5. Coefficient of thermal expansion α = 12 x 10-6/0C.

General Design Principles Question 3:

For the web of channel section to be classified in plastic class, the ratio of depth to thickness of web should be ________.

  1. less than 9.4 ε
  2. less than 52 ε
  3. less than 84 ε
  4. less than 42 ε

Answer (Detailed Solution Below)

Option 4 : less than 42 ε

General Design Principles Question 3 Detailed Solution

Concept:

Prevention of Local Buckling:

The local buckling can be prevented by adopting a higher thickness value for the plate element IS800:2007 puts a limit on width to thickness ratio of component steel plates of the section as given in Table 1.1.

Compression element Ratio Class of section

Class 1

Plastic

Class 2

Compact

Class 3

Semi-compact

Web of a channel d/tw 42ϵ 42ϵ 42ϵ
Angle, compression due to bending (both criteria should be satisfied)

b/t

or

d/t

9.4ϵ 10.5ϵ 15.7ϵ

Where, 

ϵ = \(\sqrt \frac{250}{f_y}\)

fy = Yield strength of Steel

General Design Principles Question 4:

The design criterion for laterally supported steel beams with respect to crippling recommends that the maximum permissible bearing stress should NOT exceed ______ times of the yield stress of steel (fy).

  1. 0.80
  2. 0.66
  3. 0.40
  4. 0.75

Answer (Detailed Solution Below)

Option 4 : 0.75

General Design Principles Question 4 Detailed Solution

Permissible Maximum Stress

Stress Value

Permissible average shear stress

0.40 fy

Permissible maximum shear stress

0.45 fy

Permissible axial tensile stress

0.60 fy

Permissible compressive or tensile bending Stress

0.66 fy

Permissible bearing stress

0.75 fy

Permissible combined bending & bearing stress

0.90 fy

General Design Principles Question 5:

The minimum yield stress of a steel to be used in the steel structure is 420 MPa. The permissible stress in axial tension for this steel will be:

  1. 150 MPa
  2. 210 MPa
  3. 252 MPa
  4. 420 MPa

Answer (Detailed Solution Below)

Option 3 : 252 MPa

General Design Principles Question 5 Detailed Solution

Concept:

Permissible stresses in steel,

Cases Permissible stress
Axial tension and compression 0.6 fy
In bending 0.66 fy
In bearing 0.75 fy
In shear

Max. permissible avg = 0.4 fy

Max. permissible = 0.45 fy


Where, fy = Yield stress

Calculation:

Given,

Yield stress (fy) = 420 MPa

Permissible stress in axial tension is given by,

Permissible stress = 0.6 fy = 0.6 × 420 = 252 MPa

General Design Principles Question 6:

According to IS 800-2007, the minimum distance between centre of a fastener shall NOT be less than:

  1. 32 times the thickness of plate or 300 mm
  2. 2.5 times the nominal diameter of the fastener
  3. 1.5 times the nominal diameter of the fastener
  4. 16 times the thickness of plate or 200 mm

Answer (Detailed Solution Below)

Option 2 : 2.5 times the nominal diameter of the fastener

General Design Principles Question 6 Detailed Solution

Specification for the pitch of bolts or rivets

1. Minimum pitch and minimum gauge length

\( = \left\{ {2.5 \times nominal\;diameter\;of\;the\;bolt} \right.\)

2. Minimum end and edge distance

\(= \left\{ {\begin{array}{*{20}{c}} {1.5 \times diameter\;of\;the\;bolt\;hole,\;for\;machine\;cut\;element}\\ {1.7 \times diameter\;of\;the\;bolt\;hole,\;for\;hand\;cut\;element} \end{array}} \right.\)

3. Maximum end and edge distance

\(= \left\{ {\;12 \times t \times \epsilon,\;\begin{array}{*{20}{c}} {\;where\;\epsilon = \sqrt {\frac{{250}}{{{f_y}}}} }\\ {{f_y} = yield\;stress}\\ {t = tickness\;of\;thinner\;plate\;} \end{array}} \right.\)

4. Maximum pitch of bolts or rivets or welds in the compression zone 

\(= \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {12 \times t\;}\\ {or}\\ {200\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\;\)

5. Maximum pitch of bolts or rivets or welds in the tension zone

\(= \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {16 \times t\;}\\ {or}\\ {200\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)

6. If bolts are Staggered, the above values can be increased by 50%, i.e. 

\(Maximum\;pitch\;in\;compression = \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {18 \times t\;}\\ {or}\\ {300\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)

\(Maximum\;pitch\;in\;tension\;zone = \left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {24 \times t\;}\\ {or}\\ {300\;mm} \end{array},\;whichever\;is\;less}\\ {\;t = thickness\;of\;the\;thinner\;plate} \end{array}} \right.\)

General Design Principles Question 7:

For a structural steel based construction in which, the connections between members (beam and column) at their junction will not resist any appreciable moment and shall be assumed to be hinged, is a type of:

  1. Rigid
  2. Simple
  3. Semi-rigid
  4. Composite

Answer (Detailed Solution Below)

Option 2 : Simple

General Design Principles Question 7 Detailed Solution

Explanation:

As per IS 800 (2007): General Construction In Steel - Code of Practice:

Rigid construction

  • In rigid construction, the connections between members (beam and column) at their junction shall be assumed to have sufficient rigidity to hold the original angles between the members connected at a joint unchanged under loading.

Semi-rigid construction

  • In semi-rigid construction, the connections between members (beam and column) at their junction may not have sufficient rigidity to hold the original angles between the members at a joint unchanged, but shall be assumed to have the capacity to furnish a dependable and known degree of flexural restraint. The relationship between the degree of flexural restraint and the level of the load effects shall be established by any rational method or based on test results.

Simple construction

  • In simple construction, the connections between members (beam and column) at their junction will not resist any appreciable moment and shall be assumed to be hinged. 

General Design Principles Question 8:

Two plates of thickness 10 mm and 12 mm are connected together with a fillet weld. What is the minimum size of fillet weld?

  1. 3 mm
  2. 4 mm
  3. 5 mm
  4. 6 mm

Answer (Detailed Solution Below)

Option 3 : 5 mm

General Design Principles Question 8 Detailed Solution

As per IS: 800 - 2007, Clause 10.5.2.3, Table 21

The thickness of the thicker plate

The minimum size of the welding

Up to 10 mm

3 mm

10 – 20 mm

5 mm

20 – 32 mm

6 mm

 32 mm -  50 mm

8 mm of the first run
10 for minimum size of weld

General Design Principles Question 9:

Permissible stresses in bending for steel structures should not be greater than:

  1. 0.6 fy
  2. 0.66 fy
  3. 0.75 fy
  4. fy

Answer (Detailed Solution Below)

Option 2 : 0.66 fy

General Design Principles Question 9 Detailed Solution

Explanation:

Type of force

Permissible stress

Axial tension and Compression

0.6 fy

Bending

0.66 fy

Bearing

0.75 fy

Average Shear

0.4 fy

General Design Principles Question 10:

In a design of structures, an additional lateral load considered, to account for the initial imperfections of the structure geometry is called:

  1. damping load
  2. notional load
  3. frictional drag load
  4. rotational load

Answer (Detailed Solution Below)

Option 2 : notional load

General Design Principles Question 10 Detailed Solution

Explanation:

Notional load:

  • A notional load is a lateral load that is derived from an existing vertical load case.
  • This load type has been introduced to accommodate a requirement in design codes.
  • It accounts for the initial imperfections of the structure geometry. The AISC 360-05 specification for example defines notional loads as lateral loads that are applied at each framing level and are specified in terms of gravity loads.

Rotational load:

Rotational load defines loads resulting from the rotation of the model. You can specify either angular velocity or rotary acceleration. Abaqus defines the load by using the square of the angular velocity or by using the acceleration directly. In either case, the load definition must include an axis of rotation, which is defined as follows:

  • If you are working in three-dimensional space, you define the location and direction of the axis by entering the global coordinates of two points.
  • If you are working in two-dimensional space, you specify the location of the axis by entering the coordinates of a point in the plane. The direction of the axis is always out of the plane.
  • If you are working in axisymmetric space, the axis is always in the location and direction of the positive global Z-axis.
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