Abrasive Jet Machining (AJM) MCQ Quiz in मराठी - Objective Question with Answer for Abrasive Jet Machining (AJM) - मोफत PDF डाउनलोड करा
Last updated on Mar 20, 2025
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Abrasive Jet Machining (AJM) Question 1:
During the abrasive jet machining mixing ratio used is 0.2. Calculate mass ratio, if ratio of density of abrasive & density of carrier gas is equal to 20.
Answer (Detailed Solution Below) 0.8
Abrasive Jet Machining (AJM) Question 1 Detailed Solution
\(\begin{array}{l} Mixing\;ratio = \frac{{{V_a}}}{{{V_{gas}}}} = 0.2\\ Mass\;ratio\;\left( \alpha \right) = \frac{{{M_a}}}{{{M_{a + g}}}} = \frac{{{\rho _a}{V_a}}}{{{\rho _a}{V_a} + {\rho _g}{V_g}}} \end{array}\)
\(\begin{array}{l} \frac{1}{\alpha } = \frac{{{\rho _a}{V_a} + {\rho _g}{V_g}}}{{{\rho _a}{V_a}}}\\ = 1 + \frac{{{\rho _g}}}{{{\rho _a}}}\frac{{{V_g}}}{{{V_a}}} \end{array}\)
\(\begin{array}{l} = 1 + \frac{1}{{20}} \times \frac{1}{{0.2}}\\ \frac{1}{\alpha } = 1 + 0.25\\ \alpha = \frac{1}{{1.25}} = 0.8 \end{array}\)
Abrasive Jet Machining (AJM) Question 2:
In an abrasive jet machining (AJM) process, the metal removal rate (MRR) for Q flow rate of abrasives and d mean diameter of the abrasive is 10 mm3/s. If the flow rate of abrasives is doubled and the mean diameter of abrasives is halved, then the MRR will be _______ mm3/s.
Answer (Detailed Solution Below) 2.5
Abrasive Jet Machining (AJM) Question 2 Detailed Solution
In AJM given data,
Metal removal rate (MRR) = 10 mm3/sec
Flow rate = Q
Mean diameter of abrasive = d
We know,
\(MRR = KQ{d^3}{V^{\frac{3}{2}}}{\left( {\frac{l}{{2H}}} \right)^{\frac{3}{4}}}\)
∴ MRR α (Qd3)
If flow rate (Q) is double and ‘d’ is made half, then
\(\begin{array}{l} MRR' = 2Q\frac{{{d^3}}}{8} = \frac{{MRR}}{4}\\ \therefore MRR' = \frac{{10}}{4} = 2.5\;m{m^3}/sec \end{array}\)