Properties of Systems MCQ Quiz in தமிழ் - Objective Question with Answer for Properties of Systems - இலவச PDF ஐப் பதிவிறக்கவும்

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Latest Properties of Systems MCQ Objective Questions

Top Properties of Systems MCQ Objective Questions

Properties of Systems Question 1:

Consider the following properties:

  1. Entropy
  2. Viscosity
  3. Temperature
  4. Specific heat at constant volume
Which of the above properties of a system is/are extensive?

  1. Only 1
  2. Only 1 and 2
  3. Only 2, 3 and 4
  4. Only 1, 2 and 4

Answer (Detailed Solution Below)

Option 1 : Only 1

Properties of Systems Question 1 Detailed Solution

Concept:

Properties

All measurable characteristics of a system are known as properties.

Eg. Pressure, volume, temperature, etc.

There are two types of properties:

Extensive property

  • Those properties which depend on mass are known as extensive properties.
  • Examples are volume, energy, enthalpy, entropy etc.

Intensive property

  • Those properties which don't depend on mass are known as intensive properties.
  • Examples are pressure, temperature, density, viscosity.

Important Points

  • The ratio of two extensive properties is an intensive property.
  • Specific properties are intensive properties. For example specific volume, specific energy, specific heat etc.
  • If a property divides with space then it is extensive property otherwise the property will be intensive.

Extensive Properties

V

Volume

U

Energy

H

Enthalpy

S

Entropy

Intensive Properties

T

Temperature

P

Pressure

ρ

Density

v

Specific Volume, V/m

u

Specific Internal Energy, u = U/m

h

Specific Enthalpy, h = H/m

s

Specific Entropy, s = S/m

x

Quality

CP

Specific heat at constant pressure

cv

Specific heat at constant volume

β

Isothermal Compressibility

κ

Isobaric Compressibility

Properties of Systems Question 2:

Which of the following is NOT an intensive property?

  1. Pressure
  2. Total volume
  3. Temperature
  4. Density

Answer (Detailed Solution Below)

Option 2 : Total volume

Properties of Systems Question 2 Detailed Solution

Explanation:

Properties:

All measurable characteristics of a system are known as properties. Eg. Pressure, volume, temperature, internal energy, density etc.

There are two types of properties:

Intensive Property

Extensive Property

  • An intensive property is a physical property of a system that does not depend on the system size or the amount of material in the system
  • An extensive property of a system depends on the system size or the amount of material in the system
  • Examples are melting point, boiling point, Temperature, Pressure, density, viscosity, etc.
  • Examples are  Total Volume, mass, mole, energy, etc.
  • It is a physical property.
  • It is a physical property.
  • Intensive property divided by the intensive property is an intensive property only.
  • Extensive property divided by extensive property becomes intensive property. For example, mass/volume = density (intensive property)


Total Volume:

  • Volume is the amount of space an object takes up, it is denoted by V.
  • Volume depends on the mass of the substance as the formula for volume is :

 \(V = {m\over d}\), where m= mass, d = density

  • It is thus an extensive property.

Additional Information

Temperature:

  • Temperature(T) is the measurement of the heat content of a body.
  • Its units are Celcius (ºC), Kelvin (K), Farhenheit (ºF).
  • The temperature of a body does not depend on the amount of mass of a substance. If gas has say temperature 288 K, it will mean that every particle of the gas is at temperature 288 K. It is thus an intensive property.
  • Hence, the intensive property is Temperature.

Pressure:

  • A container is having pressure P if the container is divided into equal part then the pressure will remain constant.
  • So the pressure is an intensive property.

Properties of Systems Question 3:

The thermodynamic state of a closed system containing a pure fluid changes from (T1, p1) to (T2, p2), where T and p denote the temperature and pressure, respectively. Let Q denote the heat absorbed (> 0 if absorbed by the system) and W the work done (> 0 if done by the system). Neglect changes in kinetic and potential energies. Which one of the following is CORRECT?

  1. Q is path-independent and W is path-dependent
  2. Q is path-dependent and W is path-independent
  3. (Q - W) is path-independent
  4. (Q + W) is path-independent

Answer (Detailed Solution Below)

Option 3 : (Q - W) is path-independent

Properties of Systems Question 3 Detailed Solution

here are two thermodynamics functions:

Path function: Heat and work are path functions. Their magnitude depends on the path followed during a process as well as end states.

Point function: Pressure, temperature, volume and internal energy etc. are point function. They depend on the end states only, not on the path followed.

According to first law of thermodynamics:

δQ = δW + ΔU

When a process is executed by a system, the change in stored energy of the system is numerically equal to the net heat interaction minus the net work interaction during the process:

ΔU = δQ – δW where U is the internal energy which is introduced by this law.

And change in internal energy is point function (path-independent) i.e. state function.

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Note that Q and W themselves depend on the path followed. But their difference does not.

This implies that the difference between the heat and work interactions during a process is a property of the system.

Properties of Systems Question 4:

Among the following, the low grade energy is:

  1. Tidal energy
  2. Water energy
  3. Wind energy
  4. Heat energy

Answer (Detailed Solution Below)

Option 4 : Heat energy

Properties of Systems Question 4 Detailed Solution

Explanation:

High grade and low-grade energy :

Based on the thermodynamic concepts, an energy source can be called as high-grade or low-grade, depending on the ease with which it can be converted into other forms.

High grade energy:

  • The energy which can be completely converted in to other form of energy is known as high grade energy.
  • Conversion of high grade energy is exempted from limitation of second law of thermodynamics

Examples of high grade energy:

  • Mechanical work 
  • Electrical work
  • Water power 
  • Wind power
  • Kinetic energy of jet
  • Tidal power

Low grade energy:

  • The energy which can not be converted completely in to shaft work is known as low grade energy.
  • Conversion of low grade energy is subjected to limitations of second law of thermodynamics.

Examples of low grade energy:

  • Heat or thermal energy
  • Heat derived from nuclear fission or fusion
  • Heat derived from combustion of fossil fuel

Hence work is high grade and heat is low grade energy.

Properties of Systems Question 5:

The boundary of a system:

  1. is neither fixed nor movable
  2. can be fixed or movable
  3. is always fixed
  4. is always movable

Answer (Detailed Solution Below)

Option 2 : can be fixed or movable

Properties of Systems Question 5 Detailed Solution

Explanation:

Boundary:

  • The thermodynamical system is a body of matter or radiation which is confined in space by walls, which separates it from the surroundings.  

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  • The system is separated from the surrounding by the boundary. 
  • The boundary may be fixed or moveable.
  • The different types of thermodynamic boundaries are 
  • Diathermic boundary:  This is the type of boundary that allows the flow of heat between the system and surroundings
    • A hot cup of Tea is an example of a Diathermic wall.
  • Adiabatic boundary: This type of boundary doesn't allow the flow of heat between the system and surroundings.

Properties of Systems Question 6:

Which of the following are intensive properties

1. Kinetic energy

2. Specific enthalpy

3. Pressure

4. Entropy

  1. 1 and 3
  2. 2 and 3
  3. 1, 3 and 4
  4. 2 and 4

Answer (Detailed Solution Below)

Option 2 : 2 and 3

Properties of Systems Question 6 Detailed Solution

Concept:

Intensive Property: These are the properties of system which are independent of mass under consideration. For e.g. Pressure, Temperature, density

Extensive Properties: The properties which depend on the mass of system under consideration.

For e.g Internal Energy, Enthalpy, Volume, Entropy

Note: All specific properties are intensive properties. For e.g. specific volume, specific entropy etc.

Thus specific enthalpy (enthalpy per unit mass) and pressure is an intensive property.

Properties of Systems Question 7:

The internal energy of a system is dependent on the following aspects:

1) Molecular weight

2) Molecular structure

3) Degree of molecular activity

Which of the above are correct?

  1. 1 and 2 only
  2. 1 and 3 only
  3. 2 and 3 only
  4. 1, 2 and 3

Answer (Detailed Solution Below)

Option 4 : 1, 2 and 3

Properties of Systems Question 7 Detailed Solution

Explanation:

  • There are two types of internal energy of a system i.e. macroscopic and microscopic.
  • From a thermodynamic point of view, we will focus on the microscopic approach i.e. at the molecular level.
  • The microscopic energy consists of energy at the molecular level e.g. molecular rotation, vibration, etc. and energy at the nuclear level is also involved.
  • The rotational and vibrational energy also depends upon the molecular structure e.g. inertia of molecules depends upon how the atoms are arranged.
  • So, the internal energy of a system is dependent on molecular structure and the degree of molecular activity. 
  • Internal energy is an extensive property, so it depends on mass and volume, hence it depends on molecular weight.

Properties of Systems Question 8:

Air with initial condition of p1, v1 expands to final condition of p1/2, 3v1. The process is

  1. Hyperbolic
  2. Adiabatic
  3. Polytropic with n > 1
  4. Polytropic with n < 1

Answer (Detailed Solution Below)

Option 4 : Polytropic with n < 1

Properties of Systems Question 8 Detailed Solution

Concept:

The initial condition is P1, V1

And the final condition is \({P_2} = \frac{{{P_1}}}{2}\), V2 = 3V1

Hyperbolic/Isothermal Process:

T = C i.e. PV = C 

Here: \(P_2V_2=\frac{P_1}{2}(3V_1)\ne P_1V_1\)

Polytropic Process:

PVn = C

\({P_1}V_1^n = {P_2}V_2^n\)

\( \Rightarrow {P_1}V_1^n = \left( {\frac{{{P_1}}}{2}} \right){\left( {3{V_1}} \right)^n }\)

\( \Rightarrow V_1^n = \frac{{{3^n }}}{2}V_1^n \)

⇒ 3n = 2

⇒ For n < 1 ⇒ n = 0.63

Adiabatic Process:

In adiabatic process, γ = 1.4

Properties of Systems Question 9:

Which one of the following is correct about an adiabatic boundary?

  1. It does not allow work transfer
  2. It allows mass transfer
  3. It allows heat transfer
  4. It does not allow heat transfer

Answer (Detailed Solution Below)

Option 4 : It does not allow heat transfer

Properties of Systems Question 9 Detailed Solution

Concept:

  • The thermodynamical system is a body of matter or radiation which is confined in space by walls, which separates it from the surroundings.  

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  • The system is separated from the surrounding by the boundary. 
  • The different types of thermodynamic boundaries are 
  • Diathermic boundary:  This is the type of boundary that allows the flow of heat between the system and surroundings
    • A hot cup of Tea is an example of a Diathermic wall.
  • Adiabatic boundary: This type of boundary doesn't allow the flow of heat between the system and surroundings.
  • There are 3 types of a thermodynamical system     
  1. Open System: The type of system that can exchange heat and temperature with surroundings.
  2. Closed System: The type of system in which the exchange of energy is only possible but not matter.
  3. Isolated System: The type of system which cannot exchange either matter or energy with its surrounding.

Properties of Systems Question 10:

Which combination of the following statements is correct ?

P:  A gas cools upon expansion only when its Joule-Thomson coefficient is positive in the temperature range of expansion.

Q:  For a system undergoing a process, its entropy remains constant only when the process is reversible.

R:  The work done by a closed system in an adiabatic process is a point function.

S:  A liquid expands upon freezing when the slope of its fusion curve on Pressure-Temperature diagram is negative.

  1. P, R and S
  2. P and Q
  3. Q, R and S
  4. P, Q, and R

Answer (Detailed Solution Below)

Option 1 : P, R and S

Properties of Systems Question 10 Detailed Solution

Concept:

Work done by a closed system in an adiabatic process is equal to the internal energy, which is a point function. Also in the case of an adiabatic process for a closed system work is independent of path

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Joule-Kelvin Effect:

  • A graph is made where a gas temperature is recorded at different pressure keeping enthalpy constant.
  • A series of the experiment is done with different enthalpy values and temperature, pressure is recorded.
  • The curve passing through the maxima of these enthalpies is called the inversion curve.

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Inversion Curve:

The numerical value of the slope at any point is called the Joule-Kelvin coefficient (μJ).

\({\mu _J} = {\left( {\frac{{\partial T}}{{\partial p}}} \right)_h}\)

The curve passing through the maximum temperature in different enthalpies in the temperature-pressure graph is known as Inversion Curve. It is the locus of all points where μJ is zero.

μJ

Effect

Positive

Cooling region

Negative

Heating region

0

Only for an ideal gas.

A liquid expands upon freezing when the slope of its fusion curve on the pressure-temperature diagram is negative.

Entropy change,  \(ds = \frac{{\delta \theta }}{T} + {\left( {{\delta _s}} \right)_{gen}}\)

Now for the Heat rejection process, δQ is negative and \({\left( {{\delta _s}} \right)_{gen}}\)  is positive.

If \(\frac{{dQ}}{T} = {\left( {{\delta _s}} \right)_{gen}}\)  then ds = 0

∴ For an irreversible heat rejection process also, entropy may remain constant.

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