Steam Power Plants MCQ Quiz in తెలుగు - Objective Question with Answer for Steam Power Plants - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

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పొందండి Steam Power Plants సమాధానాలు మరియు వివరణాత్మక పరిష్కారాలతో బహుళ ఎంపిక ప్రశ్నలు (MCQ క్విజ్). వీటిని ఉచితంగా డౌన్‌లోడ్ చేసుకోండి Steam Power Plants MCQ క్విజ్ Pdf మరియు బ్యాంకింగ్, SSC, రైల్వే, UPSC, స్టేట్ PSC వంటి మీ రాబోయే పరీక్షల కోసం సిద్ధం చేయండి.

Latest Steam Power Plants MCQ Objective Questions

Top Steam Power Plants MCQ Objective Questions

Steam Power Plants Question 1:

In a thermal power plant, a condenser is installed to condense exhaust steam coming out of

  1. Turbine
  2. Economizer
  3. Super-heater
  4. Boiler

Answer (Detailed Solution Below)

Option 1 : Turbine

Steam Power Plants Question 1 Detailed Solution

Concept:

  • In a thermal power plant, a condenser is installed to condense the exhaust steam coming out of turbine
  • After the steam has passed through the turbine, doing work and losing pressure and temperature, it is sent to the condenser.
  • The primary function of the condenser is to condense the exhaust steam from the turbine for reuse in the boiler as feed water. The condenser creates a vacuum that maximizes the energy extraction from the steam, leading to increased efficiency.

Additional Information Coal-fired power plant:

  • A coal-fired power station or coal power plant is a thermal power station that burns coal to generate electricity.
  • A coal-fired power station is a type of fossil fuel power station.
  • The coal is usually pulverized and then burned in a pulverized coal-fired boiler.
  • The furnace heat converts boiler water to steam, which is then used to spin turbines that turn generators.
  • Thus chemical energy stored in coal is converted successively into thermal energy, mechanical energy, and, finally, electrical energy.

Main components of coal-fired power plant:

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1.) Conveyor Belt:

Coals from the coal storage area are transported to the plant through a large conveyor belt. The load-carrying capacity of this belt is very high because very large quantities of coal are required every day.

2.) Pulverizing Plant:

Pulverized coal firing ensures complete combustion of coal, thus ensuring higher efficiency of steam generators. The finer the grinding of coal, the more efficient its combustion.

3.) Boiler:

Boilers are used in power plants in order to produce high pressured steam which is used to run the turbine.

4.) Turbine:

High-pressure steam from the boiler is fed to the steam turbine, which converts its pressurized energy into mechanical energy.

5.) Generator:

A generator uses the mechanical energy generated by the turbines to generate electricity at significantly higher voltages.

6.) Condenser:

The steam leaving the turbines is condensed into a condenser, which is pumped back into the boiler. Cold water from a water source (river) or expansion process is used to cool steam into water.

7.) Chimney:

A chimney is the tallest structure in the power plant for venting hot flue gases or smoke from a boiler, stove, furnace, or fireplace to the external atmosphere.

It also ensures that enough air is drawn into the stove for the fire to burn clean.

Steam Power Plants Question 2:

A diesel power station has fuel consumption of 0.215 kg per kWh, the calorific value of fuel being 10,000 kcal / kg. Determine the overall efficiency.

  1. 40%
  2. 30%
  3. 45%
  4. 55%

Answer (Detailed Solution Below)

Option 1 : 40%

Steam Power Plants Question 2 Detailed Solution

Concept:

Overall efficiency can be calculated as

\(\% \eta = \frac{{100}}{{{m_f} × CV}}\)

Where,

mf = mass flow rate of fuel or fuel consumption in kg / Joule

CV = calorific value of fuel in Joule/kg

1 cal = 4.18 Joule

Calculation:

m= 0.215 kg / kWh = \(\frac{{0.215}}{{3600 × {{10}^3}}}\;kg/J\)

CV = 10,000 kcal / kg = 4.18 × 10J / kg

\(\% \eta = \frac{{100 × 3600 × {{10}^3}}}{{0.215 × 4.18 × {{10}^7}}} \approx 40\% \)

Steam Power Plants Question 3:

A Thermal station has following data:

Boiler efficiency = 75%, Electrical Efficiency = 50%

Turbine efficiency = 80%

Calculate overall efficiency of the plant.

  1. 31%
  2. 30%
  3. 29%
  4. 35%

Answer (Detailed Solution Below)

Option 2 : 30%

Steam Power Plants Question 3 Detailed Solution

The correct answer is option 2): 30%

Concept:

The overall efficiency of the steam power plant is given as

\(Overall\;Efficiency\;\; = \frac{{Electrical\;energy\;output}}{{chemical\;energy\;input}}\)

Overall efficiency is also expressed as

\({\eta _0} = \;\frac{{Thermal\;Energy}}{{Chemical\;Energy}} × \frac{{Mechanical\;Energy}}{{Thermal\;Energy}} × \frac{{Electrical\;Energy}}{{Mechanical\;energy}}\)

So, the overall efficiency of the power plant is equal to the multiplication of the efficiencies of the boiler, turbine, and generator.

Overall Efficiency = Boiler efficiency × turbine efficiency × generator efficiency

Boiler efficiency = Thermal efficiency Turbine efficiency × Generator efficiency = Electrical efficiency.

Calculation:

Given

Boiler efficiency = 75%,

Electrical Efficiency = 50%

Turbine efficiency = 80%

Overall Efficiency = Boiler efficiency × turbine efficiency × generator efficiency

= 0.75 × 0.5 × 0.80

= 0.30 

= 30 %

Steam Power Plants Question 4:

The prime mover used in thermal power plant is:

  1. wind turbine
  2. steam turbine
  3. PV cell
  4. Francis Turbine

Answer (Detailed Solution Below)

Option 2 : steam turbine

Steam Power Plants Question 4 Detailed Solution

Prime Mover: Prime Mover is a machine that used to convert another form of energy into rotational energy or mechanical energy for driven the shaft of Alternator to create revolving flux or cut the stationary flux for the generation of electrical energy.

Example: Steam turbine, gas turbine, water turbine, etc

The Prime Mover used in various power plant:

Types of Power Plant

Prime Mover

Thermal Power Plant

Steam Turbine

Nuclear Power Plant

Steam Turbine

Low Head Hydro Power Plant

Francis Turbine, Kaplan Turbine

Medium Head Hydro Power Plant

Francis Turbine

High Head Hydro Power Plant

Impulse Turbine

Steam Power Plants Question 5:

In a thermal power plant, feedwater heaters, superheaters and air preheaters are mainly used to

  1. Have a better dust removal in the plant
  2. Have a better Ash removal in the plant
  3. Increase the efficiency of the plant
  4. None of the above

Answer (Detailed Solution Below)

Option 3 : Increase the efficiency of the plant

Steam Power Plants Question 5 Detailed Solution

In a thermal power plant, feedwater heaters, superheaters, and air preheaters are mainly used to increase the efficiency of the plant.

Additional Information

Thermal (Steam) Power Plant :

A generating station that converts heat energy of coal combustion into electrical energy is known as a Thermal/Steam power station.

Layout of Steam Power Plant:

 

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1. Coal and ash handling plant:
The coal is transported to the power station by road or rail and is stored in the coal storage plant. From the coal storage plant, coal is delivered to the coal handling plant where it is pulverized in order to increase its surface exposure, thus promoting rapid combustion without using a large quantity of excess air. The coal is burnt in the boiler and the ash produced after the complete combustion of coal is removed to the ash handling plant and then delivered to the ash storage plant for disposal.

2. Steam generating plant:
The steam generating plant consists of a boiler, superheater, and economizer for the production of steam and other auxiliary equipment for the utilization of flue gases.

(i) Boiler: The heat of the combustion of coal in the boiler is utilized to convert water into steam at high temperatures and pressure. The flue gases from the boiler make their journey through superheater, economizer, air pre-heater and are finally exhausted to atmosphere through the chimney.

(ii) Superheater: The steam produced in the boiler is wet and is passed through a superheater where it is dried and superheated by the flue gases on their way to the chimney. Superheating provides two principal benefits. Firstly, the overall efficiency is increased. Secondly, too much condensation in the last stages of the turbine is avoided. The superheated steam from the superheater is fed to the steam turbine through the main valve.

(iii) Economiser: An economizer is essentially a feedwater heater and derives heat from the flue gases for this purpose. The feed water is fed to the economizer before supplying to the boiler. The economizer extracts a part of the heat of flue gases to increase the feedwater temperature.

(iv) Air preheater: An air preheater increases the temperature of the air supplied for coal burning by deriving heat from flue gases. Air is drawn from the atmosphere by a forced draught fan and is passed through the air preheater before supplying to the boiler furnace. The air preheater extracts heat from flue gases and increases the temperature of the air used for coal combustion.

3. Steam turbine:
The dry and superheated steam from the superheater is fed to the steam turbine through the main valve. The heat energy of steam when passing over the blades of a turbine is converted into mechanical energy.

4. Alternator:
The steam turbine is coupled to an alternator. The alternator converts the mechanical energy of the turbine into electrical energy.

Steam Power Plants Question 6:

Identify the given general symbol shown:

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  1. Ceiling Fan
  2. Exhaust fan
  3. Bracket Fan
  4. Fan Regulator

Answer (Detailed Solution Below)

Option 2 : Exhaust fan

Steam Power Plants Question 6 Detailed Solution

Exhaust fan:

Exhaust fans are used to pull excess moisture and unwanted odors out of a particular room or area.

Exhaust fans pull odors, fumes, and moisture from an area of the home, venting them outdoors for removal.

Ceiling fan:

It is a device suspended from the ceiling of a room, with hub-mounted rotating blades that circulate the air, thereby producing a loading effect.

Wall bracket fan:

Windy wall bracket fan can be directly mounted on the wall so that it doesn’t occupy floor space, it can manually oscillate when required.

Fan regulator:

A fan regulator is a crucial component that serves to increase or decrease the speed of one’s fan according to one’s needs.

Note:

Equipment

Schematic symbol

Exhaust fan

F1 J.P 18.8.20 Pallavi D2

Bracket fan

F1 J.P 18.8.20 Pallavi D3

Ceiling fan

F1 J.P 18.8.20 Pallavi D4

Fan regulator

F1 J.P 18.8.20 Pallavi D5

Steam Power Plants Question 7:

The economiser of steam turbine system is located in the:

  1. turbine circuit
  2. feeding water circuit
  3. coal handling plant
  4. condenser circuit

Answer (Detailed Solution Below)

Option 2 : feeding water circuit

Steam Power Plants Question 7 Detailed Solution

Economizer:

It is also known as a feedwater heater. It is a device in which the waste heat of the flue gases is utilized for heating the feed water.

In economizer, feed water is preheated to improve overall efficiency and only sensible heat transfer is taking place so feed water is heated without converting it into steam. Therefore, the economizer is placed after the superheater and located in the feeding water circuit.

Following are the advantages:

  • There is about 15 to 20% of coal saving.
  • It increases the steam raising capacity of a boiler because it shortens the time required to convert water into steam.
  • It prevents the formation of scale in boiler water tubes.          

    

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Steam Power Plants Question 8:

The overall efficiency of the steam power plant is defined as:

  1. \(\frac{{heat\;equivalent\;of\;mechanical\;output}}{{heat\;of\;combustion\;of\;coal}}\)
  2. \(\frac{{heat\;equivalent\;of\;electrical\;output}}{{heat\;of\;combustion\;of\;coal}}\)
  3. \(\frac{{heat\;equivalent\;of\;electrical\;output}}{{heat\;equivalent\;of\;mechanical\;output}}\)
  4. \(\frac{{electrical\;output}}{{heat\;of\;combustion\;of\;coal}}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{{heat\;equivalent\;of\;electrical\;output}}{{heat\;of\;combustion\;of\;coal}}\)

Steam Power Plants Question 8 Detailed Solution

The efficiency of Steam Power Station:

  • The overall efficiency of a steam power station is low (about 29%) due mainly given reasons.
  • Firstly, a huge amount of heat is lost in the condenser.
  • Secondly, heat losses occur at various Stages of the plant.
  • We cannot avoid the heat lost in the condenser. It is because heat energy cannot be converted into mechanical energy without temperature difference.
  • The greater the temperature difference, the greater is the heat energy converted into mechanical energy.
  • Therefore we have to keep the steam in the condenser at the lowest temperature. But the greater temperature difference causes a greater amount of heat lost.

\(Thermal\;Efficiency = \frac{{Heat\;equivalent\;of\;mechanical\;energy\;transmitted\;to\;turbine\;shaft}}{{Heat\;of\;combustion\;of\;coal}}\)

Thermal Efficiency: The ratio of heat equivalent of mechanical energy transmitted to the turbine shaft to the heat of combustion of coal is known as thermal efficiency of the steam power station.

The thermal efficiency of a modern steam power station is about 30%.

Overall efficiency: The ratio of heat equivalent of electrical output to the heat of combustion of coal is known as the overall efficiency of the steam power station.

\(Overall\;Efficiency = \frac{{Heat\;equivalent\;of\;electrical\;output}}{{Heat\;of\;combustion\;of\;coal}} \)

The overall efficiency of the Thermal Power Plant is about 29% because there is an approximation of 1% loss in the Alternator.

Steam Power Plants Question 9:

If the station has a thermal efficiency of 30% and electrical efficiency of 95%, find the overall efficiency of the station.

  1. 26.5%
  2. 27.5%
  3. 28.5%
  4. 29.5%

Answer (Detailed Solution Below)

Option 3 : 28.5%

Steam Power Plants Question 9 Detailed Solution

Concept of Overall Efficiency:

The overall efficiency (ηoverall) of a station is the product of its thermal efficiency (ηthermal) and its electrical efficiency (ηelectrical).

The formula to calculate the overall efficiency is:

ηoverall = ηthermal × ηelectrical

Where,

  • ηthermal = Thermal efficiency (in decimal form)
  • ηelectrical = Electrical efficiency (in decimal form)

Given Data:

  • Thermal efficiency (ηthermal) = 30% = 0.30
  • Electrical efficiency (ηelectrical) = 95% = 0.95

Calculation:

Using the formula:

ηoverall = ηthermal × ηelectrical

Substituting the given values:

ηoverall = 0.30 × 0.95

ηoverall = 0.285

Converting to percentage:

ηoverall = 0.285 × 100%

ηoverall = 28.5%

Conclusion:

Hence, the overall efficiency of the station is 28.5%.

Steam Power Plants Question 10:

Economisers are used to heat:

  1. condensed steam
  2. air
  3. steam
  4. feed water

Answer (Detailed Solution Below)

Option 4 : feed water

Steam Power Plants Question 10 Detailed Solution

Economizer:

  • It is also known as feed water heater. It is a device in which the waste heat of the flue gases is utilised for heating the feed water.
  • In a steam boiler, it is a heat exchanger device that heats up fluids or recovers residual heat from the combustion product i.e. flue gases in a thermal power plant before being released through the chimney.
  • Economiser is situated before air pre-heater in the flue gas path. 
  • Economiser increases the efficiency of the power plant.

 

Important Points:

Air preheater:

  • Air preheaters are used in large boilers found in thermal power stations producing electric power.
  • An air preheater or air heater is a general term to describe any device designed to heat air before another process (for example, combustion in a boiler) with the primary objective of increasing the thermal efficiency of the process.
  • The purpose of the air preheater is to recover the heat from the boiler flue gas which increases the thermal efficiency of the boiler by reducing the useful heat lost in the flue gas.

 

Superheater:

  • A superheater is a device used to convert saturated steam or wet steam into superheated steam or dry steam
  • Superheated steam is used in steam turbines for electricity generation, steam engines, and in processes such as steam reforming
  • While the temperature of the steam in the superheater rises, the pressure remains the same as that of the boiler.
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