Question
Download Solution PDF1000 kJ/s of heat is transferred from a constant temperature heat reservoir maintained at 1000 K to a system at a constant temperature of 500 K. The temperature of the surroundings is 300 K. The net loss of available energy as a result of this heat transfer is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
According to Gouy-Stodola theorem, the loss of available energy is given by To(ΔS)gen
where To is the atmospheric temperature and (ΔS)gen is the entropy generation due to the heat transfer from one reservoir to another reservoir.
\({({\rm{\Delta }}S)_{gen}} = \oint \frac{{dQ}}{T}\)
\({({\rm{\Delta }}S)_{gen}} = \frac{Q}{{{T_2}}} - \frac{Q}{{{T_1}}}\)
Calculation:
Given, Q = 1000 kJ/s and T1 = 1000 K, T2 = 500 K
Then, \({({\rm{\Delta }}S)_{gen}} = \frac{{1000}}{{500}} - \frac{{1000}}{{1000}} = 1\;kJ/Ks\)
∴ Loss of available energy = To(ΔS)gen = 300 × 1 = 300 kJ/s
Last updated on Jun 23, 2025
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