Question
Download Solution PDFA can complete a work in 15 days, and B can complete the same work in 18 days. A works for 5 days and then leaves. The remaining work is completed by B alone. How many days does B take to complete the remaining work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFWork done per day:
A's 1 day work = 1 ÷ 15
B's 1 day work = 1 ÷ 18
A works for 5 days
⇒ Work done by A in 5 days = 5 × (1 ÷ 15) = 5 ÷ 15 = 1 ÷ 3
Remaining work = 1 − 1/3 = 2/3
B does 1 ÷ 18 of work in a day
⇒ Number of days B takes to complete 2 ÷ 3 work = (2 ÷ 3) ÷ (1 ÷ 18) = (2 ÷ 3) × 18 = 12 days
Thus, the correct answer is 12 days.
Last updated on Jun 17, 2025
-> The IBPS Customer Service Associate (Clerk) Prelims 2025 will be held on 4th, 5th, 11th October 2025.
-> The Mains 2025 exam will take place on 29th November 2025.
-> The IBPS Clerk designation name has been changed to “Customer Service Associate” (CSA). This change in designation is effective from 01.04.2024.
-> The IBPS Clerk Notification 2025 is likely to be released in July, 2025.
-> Candidates with a graduate degree are eligible for this post.
->The selection process includes prelims and mains examinations.
-> Candidates must refer to the IBPS Clerk Previous Year Papers and IBPS Clerk Mock Test to prepare well.
-> Candidates can also Attempt Free Current Affairs Banking Mock Test