Question
Download Solution PDFJitesh and Kamal can complete a certain piece of work in 18 and 17 days, respectively, They started to work together, and after 5 days, Kamal left. In how many days will Jitesh complete the remaining work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Time taken by Jitesh alone = 18 days
Time taken by Kamal alone = 17 days
Jitesh and Kamal worked together for 5 days.
Formula Used:
Efficiency = Total Work / Time taken
Work done = Efficiency × Time
Calculation:
LCM of 18 and 17 = 306. Let Total Work = 306 units.
Efficiency of Jitesh = Total Work / Time taken by Jitesh = 306 / 18 = 17 units/day
Efficiency of Kamal = Total Work / Time taken by Kamal = 306 / 17 = 18 units/day
Work done by Jitesh and Kamal together in the first 5 days = (Efficiency of Jitesh + Efficiency of Kamal) × Time
Work done in 5 days = (17 + 18) × 5 = 35 × 5 = 175 units
Remaining work = Total Work - Work done in 5 days = 306 - 175 = 131 units
Now, Jitesh alone has to complete the remaining 131 units of work.
Time taken by Jitesh alone to complete the remaining work = Remaining work / Efficiency of Jitesh
Time taken by Jitesh = 131 / 17 days = \(\frac{131\times 18}{17\times 18}\) = \(\frac{2358}{306} \)
∴ The correct answer is option 1.
Last updated on Jun 2, 2025
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