A can do a piece of work in 63 days and B is 40% more efficient than A. Then the number of days taken by B to do the same work is :

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  1. 60 days
  2. 45 days
  3. 49 days
  4. 40 days

Answer (Detailed Solution Below)

Option 2 : 45 days
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Detailed Solution

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Given:

A can do the work in 63 days.

B is 40% more efficient than A.

Formula used:

If B is 40% more efficient than A, then B will take less time to complete the same work. The time taken by B is inversely proportional to their efficiency.

Calculation:

Let the efficiency of A be 100 units. Then the efficiency of B is 140 units.

Time taken by B = (Efficiency of A / Efficiency of B) × Time taken by A

⇒ Time taken by B = (100 / 140) × 63

⇒ Time taken by B = (5/7) × 63

⇒ Time taken by B = 45 days

∴ The number of days taken by B to do the same work is 45 days.

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