A charged particle with velocity v and charge q passes through a magnetic field B. What will be the force on it due to magnetic field given that the velocity is along the direction of magnetic field?

CONCEPT:

• When moving through a magnetic field, the charged particle experiences a force.
• This force is given by the charge times the vector product of velocity and magnetic field.

\(F = q (\vec{v}\times \vec{B}) =qvBsinθ\)

where q is the charge on particle, v is perpendicular velocity and B is the magnetic field, θ is the angle between v and B.

EXPLANATION:

Force on a charged particle in a magnetic field is given by

\(F = qvBsinθ\)

• Since the velocity and magnetic field are in the same direction. The angle between them will be 0°.

θ = 0° 

\(F = qvBsinθ= qvBsin0=0 \)

• Hence the magnetic force on it will be 0.
• So the correct answer is option 1.