Question
Download Solution PDFA generating plant has an installed capacity of 20 MW and produces 20 × 106 kWh. What is the plant use factor if it operates for 4000 hours in a year?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The Plant Use Factor is calculated using the formula:
\(Plant \space use \space factor={Actual \space Energy \space Produced \over Installed \space capacity \times Operating \space hours}\)
Calculation
Given, Installed capacity = 20 MW
Energy generated = 20 × 106 kWh
Operating hours = 4000 hours
\(Plant \space use \space factor={20\times 10^6 \times 10^3 \over 20\times 10^6\times4000} \)
Plant Use Factor = 0.25
Last updated on May 29, 2025
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> Candidates can apply online from 23rd December 2024 to 24th January 2025.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.