Question
Download Solution PDFA reversible heat engine, operation on Carnot cycle, between the temperature limits of 300 K and 1000 K produces 14 kW of power. If the calorific value of the fuel is 40,000 kJ/kg. The fuel consumption will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For a reversible heat engine
where, Tmin is the minimum temperature and Tmax is the maximum temperature of the cycle.
Also,
where Q is the heat supplied to the engine and W is the work output of the engine
Q = ṁf × CV
Where, ṁf is the mass flow rate of fuel and CV is the calorific value of the fuel
Calculation:
Given, Tmin = 300 K, Tmax = 1000 K, W = 14 kW and CV of fuel = 40,000 kJ/kg
Q = ṁf × CV
ṁf = 18 kg/hr
Last updated on Jul 2, 2025
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