Question
Download Solution PDFA series LCR circuit with inductance 10H, capacitance 10 μF, resistance 50Ω is connected to an ac source of voltage, V = 200 sin(100t) volt. If the resonant frequency of the LCR circuit is vo and the frequency of the ac source is v, then:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The resonant frequency of LCR circuit = \(\upsilon_{0} = \frac{1}{2π }\sqrt{\frac{1}{LC}} \) ----- (1)
The frequency of ac source is = v = ω/2π ----- (2)
Here, V = 200 sin (100 t) = 200 sin (ωt)
Calculation:
Given: L = inductance = 10 H , resistance R = 50 Ω , capacitance (c) = 10 μF, angular velocity = ω = 100 rad/s
V = 200 sin (100 t)
Resonant frequency = ?, the frequency of AC source = ?
From equation (1) we get:
Resonant frequency, \(\upsilon_{0} = \frac{1}{2π }\sqrt{\frac{1}{LC}} \) ⇒ \(\upsilon_{0} = \frac{1}{2\times 3/14}\sqrt{\frac{1}{10\times 10\times 10^{-6}}} = 50/π \)
νo = 50/π ----- (3)
The frequency of ac source = v = ω/2π = 100/2π = 50/π
Hence, Option 3) is correct.
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