Question
Download Solution PDFA sinusoidal flux 0.02 Wb links with 55 turns of a transformer secondary. What is the rms value of the induced emf in the secondary, if the supply frequency is 50 Hz ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a transformer, an alternating current is applied to the primary winding, a current in the primary winding (magnetizing current) produces alternating flux in the core of the transformer. This alternating flux gets linked with the secondary winding, by mutual induction, so an emf gets induced in the secondary winding. This induced emf is given by the EMF equation of the transformer.
The rms value of Emf equation of the transformer is given by,
E = 4.44 N ϕm f
The average value of Emf equation of the transformer is given by,
E = 4 N ϕm f
Where N is the number of turns
f is the supply frequency
ϕm is the flux
Calculation:
Given,
flux ϕ = 0.02 Wb
N2 = 55
frequency f = 50 Hz
⇒ Erms = 4.44 × 0.02 × 55 × 50 = 244.2 V
Last updated on Jun 23, 2025
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.