Question
Download Solution PDFA variable reluctance tachometer has 180 teeth on its rotor. The speed of the shaft on which it is mounted is 1200 r.p.m. The frequency of the output pulses is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In variable reluctance tachometer,
Frequency of output pulse = (No. of teeth on the rotor) × (speed of shaft).
Calculation:
Given:
No. of teeth = 180, speed = 1200 rpm
So, the frequency of the output pulse will be:
\(= \frac{{\left( {180 \times 1200} \right)}}{{minute}}\)
\( = \left( {\frac{{180 \times 1200}}{{60}}} \right)/sec\)
= 3600/sec
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