Question
Download Solution PDFAfter emission of a β-particle, the nucleus :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 2) i.e. A, Z+1.
CONCEPT:
- Radioactive decay: Radioactive decay is the spontaneous breakdown of the nucleus of an atom along with the release of energy and matter from the nucleus.
- Beta Decay: The radioactive decay in which the parent nucleus emits an electron and an antineutrino and converts a neutron to a proton.
The equation for β-decay is given by:
\(_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+e^{-} +\bar{\nu }\)
Where X is the parent nucleus, Y is the daughter nucleus, A is the atomic mass, Z is the atomic number, e- is the electron, \(\bar\nu\) is the antineutrino.
EXPLANATION:
Mass number (A) | Atomic number (Z) | |
Beta Decay | No change | Z + 1 |
- Therefore, the nucleus after emission has no change in mass A and attains atomic number Z + 1.
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