After emission of a β-particle, the nucleus :

  1. A – 4, Z – 2
  2. A, Z+1
  3. A, Z-2
  4. A + 2, Z

Answer (Detailed Solution Below)

Option 2 : A, Z+1
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The correct answer is option 2) i.e. A, Z+1.

CONCEPT:

  • Radioactive decay: Radioactive decay is the spontaneous breakdown of the nucleus of an atom along with the release of energy and matter from the nucleus.
    • Beta Decay: The radioactive decay in which the parent nucleus emits an electron and an antineutrino and converts a neutron to a proton.

The equation for β-decay is given by:

 \(_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+e^{-} +\bar{\nu }\)

Where X is the parent nucleus, Y is the daughter nucleus, is the atomic massis the atomic numbere- is the electron\(\bar\nu\) is the antineutrino.

EXPLANATION:

  Mass number (A) Atomic number (Z)
Beta Decay No change Z + 1
  • Therefore, the nucleus after emission has no change in mass A and attains atomic number Z + 1.
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