Question
Download Solution PDFAn 8-pole generator has an output of 200 A at 500 V, the lap-connected armature has 1280 conductors, 160 commutator segments. If the brushes are advanced 4-segments from the no-load neutral axis, what is the cross-magnetising ampere-turns per pole ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a DC generator:
Cross-magnetizing ampere turn
Where,
Z = Total number of conductors
Ia = Armature current (Ia)
A = Number of parallel paths
β= Bbrush shift angle
P = Number of poles
Calculation:
P = 8, Z = 1280, Ia = 200 A,
Given, 160 commutator segment,
Hence, βm =
Now β = βm ×
A = P = 8 (for lap winding)
Cross-magnetizing ampere turn
Last updated on Jul 2, 2025
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