An isosceles ΔMNP is inscribed in a circle. If MN = MP =  cm, and NP = 32 cm, what is the radius (in cm) of the circle?

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SSC CGL 2021 Tier-I (Held On : 13 April 2022 Shift 3)
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  1. 18
  2. 20

Answer (Detailed Solution Below)

Option 4 : 20
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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Given:

MN = MP = 16√5 cm

NP = 32 cm

Formula used:

Area of a triangle = (1/2) × Base × Height

Circumradius = ABC/4Δ

Where. A, B, and C are three sides of the triangle

Δ = Area of the triangle

Calculation:

MD is perpendicular to NP

So, ND = DP = 32/2 = 16 cm

MD = √[(16√5)2 - (16)2] = √(1280 - 256) = √1024 = 32 cm

Area of ΔMNP = (1/2) × 32 × 32 = 512 cm2

Circumradius = (16√5 × 16√5 × 32)/(4 × 512) = 20 cm

∴ The radius (in cm) of the circle is 20 cm

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