Question
Download Solution PDFAn orthogonal cutting operation is being carried out under the following conditions : Cutting Speed = 2 m/sec, Depth of cut = 0.5 mm, Chip thickness = 0.6 mm. What is the chip velocity?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
We know that,
\(r = \frac{t}{{{t_c}}} = \frac{{{V_c}}}{V}\)
r = chip thickness ratio, t = chip thickness before cutting/(uncut chip thickness) (mm), tc = chip thickness after cutting (mm), V = cutting speed (m/s), Vc = chip velocity (m/s)
Calculation:
Given:
V = 2 m/s, Depth of cut = 0.5 mm
In orthogonal cutting,
t = f(feed)
and b(width) = d(depth of cut)
but in the question, nothing is mentioned about the uncut chip thickness and feed so we have taken the uncut chip thickness equal to the depth of cut. (Official Question of UPPSC AE)
tc = 0.6 mm
\(\frac{t}{{{t_c}}} = \frac{{{V_c}}}{V}\)
\(\frac{{0.5}}{{0.6}} = \frac{{{V_c}}}{2} \Rightarrow {V_c} = 1.66\;m/s\)
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