Question
Download Solution PDFAn outlet pipe can empty a cistern in 5 hours. In how much time will the pipe empty 2/15th of the tank?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
An outlet pipe can empty a cistern in 5 hours.
Formula Used:
Time to empty part of the tank = (Part of the tank) × (Total time to empty the tank)
Calculation:
Time to empty the entire tank = 5 hours
Part of the tank to be emptied = 2/15
Time to empty 2/15 of the tank = \(\frac{2}{15} × 5\) hours
Time to empty 2/15 of the tank = \(\frac{2}{15} × 5\)
Time to empty 2/15 of the tank = \(\frac{10}{15}\) hours
Time to empty 2/15 of the tank = \(\frac{2}{3}\) hours
Time to empty 2/15 of the tank in minutes = \(\frac{2}{3} × 60\)
Time to empty 2/15 of the tank in minutes = 40 minutes
The correct answer is option 2.
Last updated on Jul 31, 2024
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