For the three coupled coils in the figure shown below, calculate the total inductance:

This question was previously asked in
SSC JE Electrical 14 Nov 2022 Shift 3 Official Paper
View all SSC JE EE Papers >
  1. 20 H
  2. 48 H
  3. 70 H
  4. 100 H

Answer (Detailed Solution Below)

Option 1 : 20 H
Free
RRB JE CBT I Full Test - 23
100 Qs. 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

Concept

The total inductance for series connection is given by:

where, L = Self inductance

M = Mutual inductance

+ Sign is used in mutual inductance when current either enters or leaves from the dot in both the coils

- Sign is used in mutual inductance when current enters from a dot in one coil and leaves without a dot from another coil

Calculation

Given, L1 = 12 H, L2 = 16 H and L3 = 20 H

M1 = - 8 H, M2 = -10 and M3 = 4 H

Leq = 20 H

Additional Information The total inductance for parallel connection is given by:

- Sign is used in mutual inductance when current either enters or leaves from the dot in both the coils

+ Sign is used in mutual inductance when current enters from a dot in one coil and leaves without a dot from another coil

Latest SSC JE EE Updates

Last updated on Jun 16, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Hot Links: teen patti glory teen patti master gold download teen patti 50 bonus