Geetanjali purchased some beads to make a garland. She had some packs of beads which contain 10 beads and some loose beads. Each bead costs 50 paise. On the purchase of 1 pack of 10 beads, she gets a reduction of Rs. 1. She purchased beads such that the total number of beads is the largest two digit even number. If she got maximum possible discount, how much money she has paid to shopkeeper?

This question was previously asked in
CTET Paper 1 - 21st Dec 2021 (Eng/Hin/Sans/Ben/Mar/Tel)
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  1. 49
  2. 32
  3. 36
  4. 40

Answer (Detailed Solution Below)

Option 4 : 40
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CTET CT 1: TET CDP (Development)
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Detailed Solution

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Given:

1 pack contains 10 beads.

The value of each bead = Rs. 0.5 

The largest two-digit even number = 98

Calculation:

Geetanjali purchased a total of 98 beads.

1 pack contains 10 beads.

Therefore,

9 packs contain = 9 × 10 = 90 beads

The value of each bead is Rs. 0.5.

⇒ 90 × 0.5 = Rs. 45 

It is given in the question that, 

On the purchase of 1 pack of 10 beads, Geetanjali gets a reduction of Rs. 1.

Similarly,

On the purchase of 9 packs of 90 beads, Geetanjali gets a reduction of Rs. 9.

⇒ Rs. 45 - Rs. 9

⇒ Rs. 36

The remaining 8 beads are loose beads.

The cost of 8 beads = 8 × 0.5 = Rs. 4

Therefore,

The money paid to the shopkeeper = Rs. 36 + Rs. 4

The money paid to the shopkeeper = Rs. 40

Hence, the correct answer is Rs. 40.

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