Question
Download Solution PDF1 m/s के वेग से गतिमान 10 kg द्रव्यमान की एक वस्तु पर दो सेकंड के लिए 50 N का बल लागू किया जाता है। अंतिम वेग कितना होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFबल = द्रव्यमान × त्वरण
∴ 50 = 10 × अ
⇒ a = 5 मीटर/सेकंड 2
2 सेकंड के बाद वेग,
वी = यू + पर
= 1 + 5 × 2
= 11 मीटर/सेकंडLast updated on Jun 13, 2025
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