एक ठोस शाफ्ट 6 kN.m के बंकन आघूर्ण का विरोध कर सकता है और 8 kN.m का बलआघूर्ण एक साथ लगाया जा सकता है। अकेले लागू होने पर अधिकतम बल आघूर्ण क्या होगा जिसका प्रतिरोध शाफ्ट कर सकता है?

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ISRO LPSC Technical Assistant Mechanical 23 Feb 2020 Official Paper
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  1. 10 kN-m
  2. 7 kN-m
  3. 14 kN-m
  4. 5 kN-m

Answer (Detailed Solution Below)

Option 1 : 10 kN-m
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संकल्पना:

समतुल्य बलआघूर्ण (Te) की गणना निम्न द्वारा की जा सकती है:

\({T_e} = \sqrt {{M^2} + {T^2}} \)

जहाँ M लागू किया गया बंकन आघूर्ण है और T लागू किया गया बलआघूर्ण है।

गणना:

दिया गया है:

M = 6 kN.m, T = 8 kN.m

समतुल्य बलआघूर्ण (Te) है:

\({T_e} = \sqrt {{M^2} + {T^2}} \)

\({T_e} = \sqrt {{6^2} + {8^2}} \)

Te = 10 kN.m

26 June 1

समतुल्य बंकन आघूर्ण (Me) की गणना निम्न द्वारा की जा सकती है:

\({T_e} = \frac{1}{2}\left( {M + \sqrt {{M^2} + {T^2}} } \right)\)

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