A solid shaft can resist a bending moment of 6 kN.m and a torque of 8 kN.m applied together. The maximum torque that the shaft can resist when applied alone is

Concept:

Equivalent torque (T_e) can be calculated by:

\({T_e} = \sqrt {{M^2} + {T^2}} \)

where M is bending moment applied and T is the torque applied

Calculation:

Given:

M = 6 kN.m, T = 8 kN.m

Equivalent torque (T_e) is:

\({T_e} = \sqrt {{M^2} + {T^2}} \)

\({T_e} = \sqrt {{6^2} + {8^2}} \)

T_e = 10 kN.m

Equivalent bending moment (M_e) can be calculated by:

\({T_e} = \frac{1}{2}\left( {M + \sqrt {{M^2} + {T^2}} } \right)\)