अजय ने दो पासे एक साथ घुमाएं। क्या प्रायिकता है कि पहले पासा ने 3 का एक गुणक दर्शाया और दूसरे पासे ने एक सम संख्या दर्शाई?

  1. \(\frac{1}{6}\)
  2. \(\frac{1}{3}\)
  3. \(\frac{5}{6}\)
  4. \(\frac{1}{9}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{1}{6}\)
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Detailed Solution

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दिया गया है:

एक पासा 3 के गुणक दर्शाता है।

अन्य पासा सम संख्या दर्शाता है।

अवधारणा:

दो पासे में कुल परिणामों की संख्या 36 है।

प्रयुक्त सूत्र:

P = अनुकूल परिणाम/कुल परिणाम

गणना:
केवल ऐसी 6 स्थितियों की आवश्यकता है,

(3,2), (3,4) (3,6) (6,2) (6,4) (6,6)

अभीष्ट प्रायिकता = 6/36 = 1/6

∴ प्रायिकता 1/6 है।

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