पृथ्वी की सतह के निकट कक्षा में परिक्रमा कर रहे उपग्रह के लिए, पलायन करने के लिए वेग में प्रतिशत वृद्धि ________ है।

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AIIMS BSc NURSING 2024 Memory-Based Paper
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  1. 41%
  2. 61%
  3. 81%
  4. 98%

Answer (Detailed Solution Below)

Option 1 : 41%
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AIIMS BSc NURSING 2024 Memory-Based Paper
100 Qs. 100 Marks 120 Mins

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अवधारणा:

पृथ्वी के गुरुत्वाकर्षण से बचने के लिए, निम्न पृथ्वी कक्षा में एक उपग्रह को अपनी गति को कक्षीय वेग (vo) से पलायन वेग (ve) तक बढ़ाना होगा।

सूत्र:

  • कक्षीय वेग (vo) = √(GM / R)
  • पलायन वेग (ve) = √(2GM / R)

इसलिए, ve = √2 x vo

वेग में प्रतिशत वृद्धि = [(ve - vo) / vo] × 100%

= [(√2 x vo - vo) / vo] × 100%

= (√2 - 1) × 100%

≈ (1.414 - 1) × 100% = 0.414 × 100% = 41.4%

उत्तर: विकल्प 1) 41% है।

Latest AIIMS BSc Nursing Updates

Last updated on Jun 6, 2025

-> AIIMS BSc Nursing Notification 2025 has been released.

-> The AIIMS BSc Nursing (Hons) Exam will be held on 1st June 2025 and the exam for BSc Nursing (Post Basic) will be held on 21st June 2025.

-> The AIIMS BSc Nursing Application Form 2025 can be submitted online till May 15, 2025.

-> AIIMS BSc Nursing Result 2025 Out Today at the official webiste of AIIIMS Portal.

-> The AIIMS BSc Nursing Cut Off 2025 has been Released by the AIIMS Delhi Along with the Result

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