किन्हीं दो स्वतंत्र घटनाओं A और B के लिए, P(A - B) किसके बराबर है:

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. P(A) - P(A)P(B)
  2. P(B) - P(A)
  3. P(B) (1 - P(AB))
  4. P(A) - P(B)

Answer (Detailed Solution Below)

Option 1 : P(A) - P(A)P(B)
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SSC CGL Tier 1 2025 Full Test - 01
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दिया है:

दो स्वतंत्र घटनाएँ A और B हैं

प्रयुक्त सूत्र:

P(A - B) = P(A) - P(A ∩ B)

स्वतंत्र घटनाओं P(A ∩ B) = P(A) × P(B) के लिए, 

गणना:

हमें P(A - B) ज्ञात करना है।

P(A - B) = P(A) - P(A ∩ B)

चूँकि A और B स्वतंत्र घटनाएँ हैं:

P(A ∩ B) = P(A) × P(B)

इसलिए, P(A - B) = P(A) - P(A) × P(B)

हल:

P(A - B) = P(A) - P(A) × P(B)

P(A - B) = P(A)(1 - P(B))

इसलिए, P(A - B) = P(A)(1 - P(B)).

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