Question
Download Solution PDFयदि \({\rm{A}} = \left( {\begin{array}{*{20}{c}} 4&{{\rm{x}} + 2}\\ {2{\rm{x}} - 3}&{{\rm{x}} + 1} \end{array}} \right)\) सममित है तो x किसके बराबर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
सममित आव्यूह: यदि एक आव्यूह का परिवर्त स्वयं के बराबर है तो उस आव्यूह को सममित कहा जाता है।
या आव्यूह A केवल तभी सममित है यदि गमनागमन सूचकांक अपने घटकों को परिवर्तित नहीं करता है।
- A = AT
- aij = aji
गणना:
दिया गया है - \({\rm{A}} = \left( {\begin{array}{*{20}{c}} 4&{{\rm{x}} + 2}\\ {2{\rm{x}} - 3}&{{\rm{x}} + 1} \end{array}} \right)\)
एक वास्तविक वर्गाकार आव्यूह A = (aij) को सममित कहा जाता है, यदि A = AT है।
जहाँ AT = आव्यूह A का परिवर्त
\({{\rm{A}}^{\rm{T}}} = \left( {\begin{array}{*{20}{c}} 4&{2{\rm{x}} - 3}\\ {{\rm{x}} + 2}&{{\rm{x}} + 1} \end{array}} \right)\)
∴ A = AT
\(\Rightarrow \left[ {\begin{array}{*{20}{c}} 4&{{\rm{x}} + 2}\\ {2{\rm{x}} - 3}&{{\rm{x}} + 1} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 4&{2{\rm{x}} - 3}\\ {{\rm{x}} + 2}&{{\rm{x}} + 1} \end{array}} \right]\)
A21 तत्व की तुलना करने पर।
⇒ x + 2 =2x - 3
⇒ x = 5
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