Question
Download Solution PDFचित्र में दर्शाई गई घिरनी प्रणाली का द्रव्यमान 1.5 kg है तथा घूर्णन त्रिज्या 0.2 m है। जब निलंबित द्रव्यमानों को छोड़ा जाता है, तो घिरनियों का कोणीय त्वरण होता है
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFस्पष्टीकरण:
दिया गया है,
m1 = 1.5 kg k = 0.2 m
m2 = 1 kg m3 = 3 kg
r2 = 0.2 m r3 = 0.1 m
I1 = m1k2
= 1.5 × 0.22 = 1 × 0.22
= 0.06
\(\rm I_2 = m_2 r^2_2\) = 1 × 0.22 = 0.04
\(\rm I_3 = m_3 r^2_3\)
= 3 × 0.1 2
= 0.03
(I1 + I2 + I3) α = m3gr3 - m2gr2
(0.06 + 0.04 + 0.03) α = 3 × 10 × 0.1 - 1 × 10 × 0.2
\(\alpha=\frac{1}{0.13}=\frac{10}{1.3} \mathrm{rad} / \mathrm{s}\)
Last updated on Apr 14, 2023
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