Question
Download Solution PDFThe pulley system shown in figure has a mass of 1.5 kg and a radius of gyration of 0.2 m. The angular acceleration of the pulleys, when the suspended masses are released is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given,
m1 = 1.5 kg k = 0.2 m
m2 = 1 kg m3 = 3 kg
r2 = 0.2 m r3 = 0.1 m
I1 = m1k2
= 1.5 × 0.22 = 1 × 0.22
= 0.06
\(\rm I_2 = m_2 r^2_2\) = 1 × 0.22 = 0.04
\(\rm I_3 = m_3 r^2_3\)
= 3 × 0.12
= 0.03
(I1 + I2 + I3) α = m3gr3 - m2gr2
(0.06 + 0.04 + 0.03) α = 3 × 10 × 0.1 - 1 × 10 × 0.2
\(\alpha=\frac{1}{0.13}=\frac{10}{1.3} \mathrm{rad} / \mathrm{s}\)
Last updated on Apr 14, 2023
The ISRO ( Indian Space Research Centre) released the official notification for the ISRO Scientist ME 2022 on 29th November 2022. The application window will remain open till 19th December 2022. A total of 33 vacancies have been released for the current recruitment cycle. The selected candidates for the post of ME in ISRO will get a basic salary of Rs. 56,100. Candidates who want a successful selection can refer to the ISRO Scientist ME Previous Year Papers to understand the level of the examination and improve their preparation accordingly.